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Published byBruce Newton Modified over 9 years ago
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Regression Correlation Background Defines relationship between two variables X and Y R ranges from -1 (perfect negative correlation) 0 (No correlation) +1 (perfect positive correlation) R=.689
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Regression Correlation Background R 2 Indicates reduction in error knowing X and Predicting Y R 2 ranges from 0 (No reduction in error) 1 (complete reduction in error) R 2 =.474
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Regression Examples Predicting height from G.P.A. R 2 = 0 (Knowing height does not help predict G.P.A – best guess is always mean G.P.A.) R 2 = 1 (Knowing height in CM completely predicts height in Inches)
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Regression Real world examples are somewhere in between Predicting height from weight R 2 =.36 (Knowing height somewhat helps predict weight)
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Regression But how do we figure out HOW to make that prediction given one of the variables?
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Regression Need background concept of slope How much does Y change for a given change in X? All lines have R=1
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Regression All lines have R=-1
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Regression Need background concept of INTERCEPT What is Y when X=0? All lines have Same Slope but different intercept
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Regression Unique line is defined by Slope and Y- Intercept Y=bX+a b=slope a=Y-Interecpt
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Regression Predicting depression from loneliness Y= BDI Depression X= Loneliness Y=2X+2
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Regression Predicted vs. Actual R=1, R 2 =1 No Error Never happens like this in real world
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Actual scores don’t fit on a line perfectly
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Some possible solutions? Error is Sum of (Predicted Y-Actual Y) 2
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Where is the line with smallest error? Least Squares Regression Line
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Calc slope=b= Σ (X-X)(Y-Y) ---------------------------------------------------------- Σ (X-X)(X-X) =2.13 with this data
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Where is the line with smallest error? Least Squares Regression Line Calc y intercept = a Y- (b)(X) =4 with this data So Least squares regression line is Y=2.13X+4
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Where is the line with smallest error? Least Squares Regression Line
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How good is our prediction? Sum of (Predicted Y-Actual Y) 2 X ScoreActual Y scorePredicted Y scoreSquared Error 054.001.00 176.130.75 288.270.07 31110.400.36 4812.5320.55 51514.670.11 61716.800.04 72218.939.40 81821.079.40 92523.203.24 4.513.644.93
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Can we standardize this for an average Error? Yes: Standard error of the estimate Like a standard deviation Gives average precition error per score Standard error of the estimate = SQRT(SS residual /N pairs -2) In this example = SQRT(44.9/10-2)=SQRT(44.9/8)=2.36
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Chi-square (χ2) Non Parametric Statistical tests Used for nominal data (categories) ordinal (ordered categories) non-normal interval/ratio data
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Goodness of fit χ2 Used with nominal data Tests a DISTRIBUTION (not a mean) Sees if observed data FITS an expected distribution H 0 =true frequency distribution is expected H 1 =true frequency distribution has some other form
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VEGAS BABY!!! Rolling dice at the Mirage Lots of Snake Eyes coming up Are the dice fixed? Test with goodness of fit Does our distribution FIT the expected distribution
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VEGAS BABY!!! Expected distribution for 120 rolls if fair: Each die(dice) has 1/6 chance 1/6 X 120 = 20 of each type Expected Distribution = [20,20,20,20,20,20]
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VEGAS BABY!!! Actual distribution for 120 rolls is: [28,16,23,23,17,13] Are these dice fair? Use Goodness of fit χ2
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VEGAS BABY!!! Determine critical χ2 value: df = number of categories – 1 = 6-1 = 5 χ2 critical for df=5 is 11.07 from table
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CatOiOi EiEi (O i -E i )(O i -E i ) 2 (O i -E i ) 2 / E i 128208643.2 21620-4160.8 32320390.45 42320390.45 51720-390.45 61320-7492.45 Σ120 07.8 FAIR!!!
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CatOiOi EiEi (O i -E i )(O i -E i ) 2 (O i -E i ) 2 / E i 15640162566.4 23240-8641.6 346406360.9 446406360.9 53440-6360.9 62640-141964.9 Σ240 015.6 CHEAT!!!
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Test of independence χ2 Used with nominal data Tests whether DISTRIBUTION 1 is dependent upon DISTRIBUTION 2 H 0 = Distribution 1 is independent of Distribution 2 H 1 = Distribution 1 is related to Distribution 2
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Example: Are Men more likely to have supported was in IRAQ 100 Subjects (50 male, 50 female) Asked yes or no question about supporting war in Iraq H 0 = Gender does not affect likelihood of supporting war H 1 = Gender does affect likelihood of supporting war
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Determine critical Value Df = (R-1) (C-1) Df = (Category 1 Size -1) size X Category 2 Size -1) =(2-1) X (2-1) = 1 X 1 = 1 Critical Value from A-3 is 3.84
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Set up Data MalesFemalesTotal Support war 32 2153 Not support war 18 2947 Total 5050100
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Set up Data MalesFemalesTotal Support war 32 (26.5) 21(26.5)53 Not support war 18 (23.5) 29(23.5)47 Total 5050100
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CategoryOiEi(Oi-Ei)(Oi-Ei) 2 (Oi-Ei) 2 / Ei M/S3226.55.530.31.14 M/N1823.5-5.530.31.29 F/S2126.5-5.530.31.14 F/N2923.55.530.31.29 Σ100 04.86 Calculate observed χ2
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Test observed against critical observed χ2 = 4.86 critical χ2 = 3.84 So we reject the idea that gender does not affect support of war and conclude Gender DOES affect support of war
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McNemar test for significance of change Used with nominal data Tests whether DISTRIBUTION 1 is dependent upon DISTRIBUTION 2 Same as test of dependence but uses SAME person to test nominal data before and after some event
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Example: Are Men more likely to have supported was in IRAQ 100 Subjects Do you favor the pledge allegiance? Before and After terrorist attacks H 0 = proportion of individuals supporting pledge before attacks is same as after attacks H 1 = proportion of individuals supporting pledge before attacks is different after attacks
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Determine critical Value Df = 1 for all McNemar tests Critical Value is 3.84
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Set up Data Before Attacks YesNoTotal After AttacksYes 33 2053 No 9 3847 Total 4258100
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Set up Data Before Attacks YesNoTotal After AttacksYes 33 20 (14.5) 53 No 9 (14.5) 3847 Total 4258
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CategoryOiEi(Oi-Ei)(Oi-Ei) 2 (Oi-Ei) 2 / Ei 1914.5-5.530.32.09 22014.55.530.32.09 Σ29 04.17 Calculate observed χ2
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Test observed against critical observed χ2 = 4.71 critical χ2 = 3.84 So we reject the idea that the proportions are the same Conclusion: Attacks did change the proportion who support pledge of allegiance
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