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1 Mendelelian Genetics copyright cmassengale 2 Gregor Mendel (1822-1884) Responsible for the Laws governing Inheritance of Traits copyright cmassengale.

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Presentation on theme: "1 Mendelelian Genetics copyright cmassengale 2 Gregor Mendel (1822-1884) Responsible for the Laws governing Inheritance of Traits copyright cmassengale."— Presentation transcript:

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2 1 Mendelelian Genetics copyright cmassengale

3 2 Gregor Mendel (1822-1884) Responsible for the Laws governing Inheritance of Traits copyright cmassengale

4 3 Gregor Johann Mendel  Studied the inheritance of traits in pea plants  Developed the laws of inheritance  Mendel's work was not recognized until the turn of the 20th century copyright cmassengale

5 4 Gregor Johann Mendel  He found that the plants' offspring retained traits of the parents  Called the “Father of Genetics" copyright cmassengale

6 5 Site of Gregor Mendel’s experimental garden in the Czech Republic copyright cmassengale

7 6  Mendel stated that physical traits are inherited as “particles”  Mendel did not know that the “particles” were actually Chromosomes & DNA Particulate Inheritance copyright cmassengale

8 7 Genetic Terminology  Gene – a segment of DNA that is located in a chromosome & codes for a specific heredity trait  Trait - any characteristic that can be passed from parent to offspring  Heredity - passing of traits from parent to offspring  Genetics - study of heredity copyright cmassengale

9 8 Types of Genetic Crosses  Cross – mating of two individuals  Gamete – male and female sex cells (egg & sperm)  Fertilization – the union of male and female gametes to form a zygote.  Monohybrid cross - cross involving a single trait e.g. flower color  Dihybrid cross - cross involving two traits e.g. flower color & plant height copyright cmassengale

10 9 Punnett Square Used to help solve genetics problems copyright cmassengale

11 10copyright cmassengale

12 11 Designer “Genes”  Alleles - two forms of a gene Ex. on chromosomes that code for ht. there would be 2 alleles, short & tall)  Dominant - visible, observable trait; stronger of two genes expressed in the hybrid and masks the recessive. represented by a capital letter (R)  Recessive – hidden trait; gene that shows up less often in a cross; represented by a lowercase letter (r) copyright cmassengale

13 12 More Terminology  Genotype - gene combination for a trait; genetic make up of an organism (e.g. RR, Rr, rr)  Phenotype - the physical feature or visible traits of an organism (e.g. red, white) (e.g. red, white) copyright cmassengale

14 13 Genotype & Phenotype in Flowers Genotype of alleles: R = red flower r = yellow flower All genes occur in pairs, so 2 alleles affect a characteristic Possible combinations are: GenotypesRR Rrrr PhenotypesRED RED YELLOW copyright cmassengale

15 14 Genotypes  Homozygous genotype – both alleles are identical for a specific trait; 2 dominant or 2 recessive genes; (e.g. RR or rr); also called pure (e.g. RR or rr); also called pure  Heterozygous genotype – having 2 different alleles for a given 1 dominant & 1 recessive allele (e.g. Rr); also called hybrid (e.g. Rr); also called hybrid copyright cmassengale

16 15 Mendel’s Pea Plant Experiments copyright cmassengale

17 Mendel’s Pea Plant Experiments copyright cmassengale16 Mendel crossed 2 plants with different characters, or forms, for the same trait. Ex. 1 tall & 1 short *The plants that grew were hybrid. Hybrid – are the offspring of crosses between parents with different traits.

18 17 Why peas, Pisum sativum?  Can be grown in a small area  Produce lots of offspring  Produce pure plants when allowed to self-pollinate several generations  Can be artificially cross-pollinated copyright cmassengale

19 18 Mendel’s Experimental Methods Mendel hand-pollinated flowers using a paintbrush He could snip the stamens to prevent self-pollination Covered each flower with a cloth bag He traced traits through the several generations copyright cmassengale

20 19 How Mendel Began Mendel produced pure strains by allowing the plants to self- pollinate for several generations copyright cmassengale

21 20 Eight Pea Plant Traits Seed shape --- Round (R) or Wrinkled (r) Seed Color ---- Yellow (Y) or Green ( y ) Pod Shape --- Smooth (S) or wrinkled ( s ) Pod Color --- Green (G) or Yellow (g) Seed Coat Color ---Gray (G) or White (g) Flower position---Axial (A) or Terminal (a) Plant Height --- Tall (T) or Short (t) Flower color --- Purple (P) or white ( p ) copyright cmassengale

22 21copyright cmassengale

23 22copyright cmassengale

24 23 Mendel’s Experimental Results copyright cmassengale

25 Experiment I Concluded: *Each trait is based on two genes, one from the mother and the other from the father *The hybrid plants looked like only 1 parent and the character of the other parent seemed to disappear. *Each trait is controlled by 1 gene. Alleles- controls the different forms of a gene. Genes- chemical factors that determine traits. Phenotype is based on Genotype copyright cmassengale24

26 25 Mendel’s Laws copyright cmassengale

27 26 Law of Dominance *States that some alleles are dominant & others are recessive. *Whenever a living thing inherits a dominant allele, that trait is visible. *All the offspring will be heterozygous and express only the dominant trait. RR x rr yields all Rr (round seeds) copyright cmassengale

28 27 Law of Dominance copyright cmassengale

29 28 Law of Segregation During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other. Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring. copyright cmassengale

30 Experiment II: Law of Segregation Mendel crossed a tall plant (dominant) with a short plant (recessive), the F1 plant inherited an allele for tallness from the tall parent & an allele for shortness from the short parent. Pg. 265 Mendel allowed his hybrid plants to self-pollinate. Some showed recessive traits, the recessive traits did not disappear. Earlier, the dominant masked the recessive, so it was not visible. Alleles for the same trait can be separated. copyright cmassengale29

31 Law of Segregation Segregation – When sex cells, or gametes, are formed. Each gamete carries only 1 copy of each gene. Therefore, each F1 plant produces 2 types of gametes (some with an allele for tallness & some with an allele for shortness). Ex. T, t, T, t = TT, Tt, Tt, tt copyright cmassengale30

32 31 Applying the Law of Segregation copyright cmassengale

33 32 Probability – the likelihood that a particular event will occur. Ex. Flipping a coin. The probability that it will land on tails is ½.

34 33 Law of Independent Assortment Alleles for different traits are distributed to sex cells (& offspring) independently of one another. This helps account for genetic variations. This law can be illustrated using dihybrid crosses. Ex Pea shape & pea color copyright cmassengale

35 34 Generation “Gap” Parental P 1 Generation = the parental generation in a breeding experiment. F 1 generation = the first-generation offspring in a breeding experiment. (1st filial generation) From breeding individuals from the P 1 generation F 2 generation = the second-generation offspring in a breeding experiment. (2nd filial generation) From breeding individuals from the F 1 generation From breeding individuals from the F 1 generation copyright cmassengale

36 35 Following the Generations Cross 2 Pure Plants TT x tt Results in all Hybrids Tt Cross 2 Hybrids get 3 Tall & 1 Short TT, Tt, tt copyright cmassengale

37 36 Monohybrid Crosses copyright cmassengale

38 A Punnett Square shows: copyright cmassengale37 *All the possible results of a genetic cross. *The genotypes of the offspring. *The alleles in the gametes of each parent.

39 38 Trait: Seed Shape Alleles: R – Roundr – Wrinkled Cross: Round seeds x Wrinkled seeds RR x rr P 1 Monohybrid Cross R R rr Rr Genotype:Rr Genotype: Rr PhenotypeRound Phenotype: Round Genotypic Ratio:All alike Genotypic Ratio: All alike Phenotypic Ratio: All alike copyright cmassengale

40 39 P 1 Monohybrid Cross Review  Homozygous dominant x Homozygous recessive  Offspring all Heterozygous (hybrids)  Offspring called F 1 generation  Genotypic & Phenotypic ratio is ALL ALIKE copyright cmassengale

41 40 Trait: Seed Shape Alleles: R – Roundr – Wrinkled Cross: Round seeds x Round seeds Rr x Rr F 1 Monohybrid Cross R r rR RR rrRr Genotype:RR, Rr, rr Genotype: RR, Rr, rr PhenotypeRound & wrinkled Phenotype: Round & wrinkled G.Ratio:1:2:1 G.Ratio: 1:2:1 P.Ratio: 3:1 copyright cmassengale

42 41 F 1 Monohybrid Cross Review  Heterozygous x heterozygous  Offspring: 25% Homozygous dominant RR 50% Heterozygous Rr 25% Homozygous Recessive rr  Offspring called F 2 generation  Genotypic ratio is 1:2:1  Phenotypic Ratio is 3:1 copyright cmassengale

43 42 What Do the Peas Look Like? copyright cmassengale

44 43 …And Now the Test Cross Mendel then crossed a pure & a hybrid from his F 2 generation This is known as an F 2 or test cross There are two possible testcrosses: Homozygous dominant x Hybrid Homozygous recessive x Hybrid copyright cmassengale

45 44 Trait: Seed Shape Alleles: R – Roundr – Wrinkled Cross: Round seeds x Round seeds RR x Rr F 2 Monohybrid Cross (1 st ) R R rR RR RrRR Rr Genotype:RR, Rr Genotype: RR, Rr PhenotypeRound Phenotype: Round Genotypic Ratio:1:1 Genotypic Ratio: 1:1 Phenotypic Ratio: All alike copyright cmassengale

46 45 Trait: Seed Shape Alleles: R – Roundr – Wrinkled Cross: Wrinkled seeds x Round seeds rr x Rr F 2 Monohybrid Cross (2nd) r r rR Rr rrRr rr Genotype:Rr, rr Genotype: Rr, rr PhenotypeRound & Wrinkled Phenotype: Round & Wrinkled G. Ratio:1:1 G. Ratio: 1:1 P.Ratio: 1:1 copyright cmassengale

47 46 F 2 Monohybrid Cross Review  Homozygous x heterozygous(hybrid)  Offspring: 50% Homozygous RR or rr 50% Heterozygous Rr  Phenotypic Ratio is 1:1  Called Test Cross because the offspring have SAME genotype as parents copyright cmassengale

48 47 Summary of Mendel’s laws LAW PARENT CROSS OFFSPRING DOMINANCE TT x tt tall x short 100% Tt tall SEGREGATION Tt x Tt tall x tall 75% tall 25% short INDEPENDENT ASSORTMENT RrGg x RrGg round & green x round & green 9/16 round seeds & green pods 3/16 round seeds & yellow pods 3/16 wrinkled seeds & green pods 1/16 wrinkled seeds & yellow pods copyright cmassengale

49 48 Dihybrid Cross A breeding experiment that tracks the inheritance of two traits. Mendel’s “Law of Independent Assortment” a. Each pair of alleles segregates independently during gamete formation b. Formula: 2 n (n = # of heterozygotes) copyright cmassengale

50 49 Question: How many gametes will be produced for the following allele arrangements? Remember: 2 n (n = # of heterozygotes) 1.RrYy 2.AaBbCCDd 3.MmNnOoPPQQRrssTtQq copyright cmassengale

51 50 Answer: 1. RrYy: 2 n = 2 2 = 4 gametes RY Ry rY ry 2. AaBbCCDd: 2 n = 2 3 = 8 gametes ABCD ABCd AbCD AbCd aBCD aBCd abCD abCD 3. MmNnOoPPQQRrssTtQq: 2 n = 2 6 = 64 gametes copyright cmassengale

52 Experiment III *Mendel wanted to see if genes that determine 1 trait have anything to do with genes that determine another. *He followed 2 different genes as they passed from one generation to the next. *Mendel crossed true-breeding plants - round yellow peas (RRYY) with wrinkled green peas (rryy). *The F 1 offspring were all round & yellow showing that both were dominant alleles. The genotype is RrYy. Pg. 270 copyright cmassengale51

53 52 Dihybrid Cross Traits: Seed shape & Seed color Alleles: Alleles: R round r wrinkled Y yellow y green RrYy x RrYy RY Ry rY ry All possible gamete combinations copyright cmassengale

54 53 Dihybrid Cross RYRyrYry RYRy rY ry copyright cmassengale

55 54 Dihybrid Cross RRYY RRYy RrYY RrYy RRYy RRyy RrYy Rryy RrYY RrYy rrYY rrYy RrYy Rryy rrYy rryy Round/Yellow: 9 Round/green: 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 phenotypic ratio RYRyrYryRY Ry rY ry copyright cmassengale

56 55 Dihybrid Cross Round/Yellow: 9 Round/green: 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 copyright cmassengale

57 56 Test Cross A mating between an individual of unknown genotype and a homozygous recessive individual. Example: bbC__ x bbcc BB = brown eyes Bb = brown eyes bb = blue eyes CC = curly hair Cc = curly hair cc = straight hair bCb___bc copyright cmassengale

58 57 Test Cross Possible results: bCb___bcbbCc CbCb___bc bbccor c copyright cmassengale

59 58 Incomplete Dominance and Codominance copyright cmassengale

60 Different Patterns of Dominant & Recessive copyright cmassengale59 Incomplete Dominance – 1 allele is not completely dominant over another. Ex. Red flower (RR) & white flower (WW), F1 is a pink flower (RW). Pg. 272 Codominance – both alleles contribute to the phenotype. Ex. A cross of a black chicken (BB) with a white chicken (WW) will produce all speckled offspring (BBWW); colors appear separately.

61 Different Patterns of Dominant & Recessive Multiple Alleles – have more than 2 alleles. Ex. Coat color in rabbits. Polygenic Traits – traits controlled by 2 or more genes; “ having many genes ”. Ex. Variation in human skin color. copyright cmassengale60

62 61 Incomplete Dominance F1 hybrids in betweenphenotypes F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties. Example:snapdragons (flower) Example: snapdragons (flower) red (RR) x white (rr) RR = red flower rr = white flower R R rr copyright cmassengale

63 62 Incomplete Dominance RrRrRrRr R Rr All Rr = pink (heterozygous pink) produces the F 1 generation r copyright cmassengale

64 63 Incomplete Dominance copyright cmassengale

65 64 Codominance Two alleles are expressed (multiple alleles) in heterozygous individuals. Example: blood type 1.type A= I A I A or I A i 2.type B= I B I B or I B i 3.type AB= I A I B 4.type O= ii copyright cmassengale

66 65 Codominance Problem Example:homozygous male Type B (I B I B ) x heterozygous female Type A (I A i) IAIBIAIB IBiIBi IAIBIAIB IBiIBi 1/2 = I A I B 1/2 = I B i IBIB IAIA i IBIB copyright cmassengale

67 66 Another Codominance Problem Example:Example: male Type O (ii) x female type AB (I A I B ) IAiIAiIBiIBi IAiIAiIBiIBi 1/2 = I A i 1/2 = I B i i IAIA IBIB i copyright cmassengale

68 67 Codominance Question: If a boy has a blood type O and his sister has blood type AB, what are the genotypes and phenotypes of their parents? boy - type O (ii) X girl – type AB (I A I B ) AB (I A I B ) copyright cmassengale

69 68 Codominance Answer: IAIBIAIB ii Parents: genotypes genotypes = I A i and I B i phenotypes phenotypes = A and B IBIB IAIA i i copyright cmassengale

70 69 Sex-linked Traits Traits (genes) located on the sex chromosomes Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carried on X chromosome copyright cmassengale

71 70 Sex-linked Traits Sex Chromosomes XX chromosome - femaleXy chromosome - male fruit fly eye color Example: Eye color in fruit flies copyright cmassengale

72 71 Sex-linked Trait Problem Example: Eye color in fruit flies (red-eyed male) x (white-eyed female) X R Y x X r X r Remember: the Y chromosome in males does not carry traits. RR = red eyed Rr = red eyed rr = white eyed XY = male XX = female XRXR XrXr XrXr Y copyright cmassengale

73 72 Sex-linked Trait Solution: X R X r X r Y X R X r X r Y 50% red eyed female 50% white eyed male XRXR XrXr XrXr Y copyright cmassengale

74 73 Female Carriers copyright cmassengale

75 Pedigrees *Pedigrees – are graphic representations of a family tree, which allows for patterns of inheritance to be seen. *Each horizontal row of circles and squares represents a generation. *People that do not show the trait but are heterozygous (Tt) for the trait are called carriers. copyright cmassengale74

76 Pedigree on mouse color copyright cmassengale75

77 76 Genetic Practice Problems copyright cmassengale

78 77 Breed the P 1 generation tall (TT) x dwarf (tt) pea plants T T tt copyright cmassengale

79 78 Solution: T T tt Tt All Tt = tall (heterozygous tall) produces the F 1 generation tall (TT) vs. dwarf (tt) pea plants copyright cmassengale

80 79 Breed the F 1 generation tall (Tt) vs. tall (Tt) pea plants T t Tt copyright cmassengale

81 80 Solution: TT Tt tt T t Tt produces the F 2 generation 1/4 (25%) = TT 1/2 (50%) = Tt 1/4 (25%) = tt 1:2:1 genotype 3:1 phenotype 3:1 phenotype tall (Tt) x tall (Tt) pea plants copyright cmassengale


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