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Genotype x Environment Interactions Analyses of Multiple Location Trials
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Why do researchers conduct multiple experiments? Effects of factors under study vary from location to location or from year to year. To obtain an unbias estimate. Interest in determining the effect of factors over time. To investigate genotype (or treatment) x environment interactions.
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What are Genotype x Environment Interactions? Differential response of genotypes to varying environmental conditions. Delight for statisticians who love to investigate them. The biggest nightmare for plant breeders (and some other agricultural researchers) who try to avoid them like the plague.
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What causes Genotype x Environment interactions?
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B A Yield Locations No interaction
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B A Yield Locations B A Yield Locations No interaction Cross-over interaction
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B A Yield Locations B A Yield Locations B A Yield Locations No interaction Scalar interaction Cross-over interaction
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Examples of Multiple Experiments Plant breeder grows advanced breeding selections at multiple locations to determine those with general or specific adaptability ability. A pathologist is interested in tracking the development of disease in a crop and records disease at different time intervals. Forage agronomist is interested in forage harvest at different stages of development over time.
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Types of Environment Researcher controlled environments, where the researcher manipulates the environment. For example, variable nitrogen. Semi-controlled environments, where there is an opportunity to predict conditions from year to year. For example, soil type. Uncontrolled environments, where there is little chance of predicting environment. For example, rainfall, temperature, high winds.
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Why? To investigate relationships between genotypes and different environmental (and other) changes. To investigate relationships between genotypes and different environmental (and other) changes. To identify genotypes which perform well over a wide range of environments. General adaptability. To identify genotypes which perform well over a wide range of environments. General adaptability. To identify genotypes which perform well in particular environments. Specific adaptability. To identify genotypes which perform well in particular environments. Specific adaptability.
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How many environments do I need? Where should they be?
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Number of Environments Availability of planting material. Diversity of environmental conditions. Magnitude of error variances and genetic variances in any one year or location. Availability of suitable cooperators Cost of each trial ($’s and time).
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Location of Environments Variability of environment throughout the target region. Proximity to research base. Availability of good cooperators. $$$’s.
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Analyses of Multiple Experiments
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Points to Consider before Analyses Normality. Homoscalestisity (homogeneity) of error variance. Additive. Randomness.
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Points to Consider before Analyses Normality. Homoscalestisity (homogeneity) of error variance. Additive. Randomness.
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Bartlett Test (same degrees of freedom) M = df{nLn(S) - Ln 2 } Where, S = 2 /n 2 n-1 = M/C C = 1 + (n+1)/3ndf n = number of variances, df is the df of each variance
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Bartlett Test (same degrees of freedom) S = 101.0; Ln(S) = 4.614
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Bartlett Test (same degrees of freedom) S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083
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Bartlett Test (same degrees of freedom) S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083 2 3df = 1.880/1.083 = 1.74 ns
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Bartlett Test (different degrees of freedom) M = ( df)nLn(S) - dfLn 2 Where, S = [ df. 2 ]/( df) 2 n-1 = M/C C = 1+{(1)/[3(n-1)]}.[ (1/df)-1/ ( df)] n = number of variances
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Bartlett Test (different degrees of freedom) S = [ df. 2 ]/( df) = 13.79/37 = 0.3727 ( df)Ln(S) = (37)(-0.9870) = -36.519
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Bartlett Test (different degrees of freedom) M = ( df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057
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Bartlett Test (different degrees of freedom) S = [ df. 2 ]/( df) = 13.79/37 = 0.3727 ( df)Ln(S) = (37)(=0.9870) = -36.519 M = ( df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057 2 3df = 17.96/1.057 = 16.99 **, 3df
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Heterogeneity of Error Variance
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Significant Bartlett Test “ What can I do where there is significant heterogeneity of error variances?” Transform the raw data: Often ~ cw Binomial Distribution where = np and = npq Transform to square roots
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Heterogeneity of Error Variance
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Significant Bartlett Test “What else can I do where there is significant heterogeneity of error variances?” Transform the raw data: Homogeneity of error variance can always be achieved by transforming each site’s data to the Standardized Normal Distribution [x i - ]/
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Significant Bartlett Test “What can I do where there is significant heterogeneity of error variances?” Transform the raw data Use non-parametric statistics
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Analyses of Variance
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Model ~ Multiple sites Y ijk = + g i + e j + ge ij + E ijk i g i = j e j = ij ge ij Environments and Replicate blocks are usually considered to be Random effects. Genotypes are usually considered to be Fixed effects.
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Analysis of Variance over sites
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Y ijkl = +g i +s j +y k +gs ij +gy ik +sy jk +gsy ijk +E ijkl i g i = j s j = k y k = 0 ij gs ij = ik gy ik = jk sy ij = 0 ijk gsy ijk = 0 Models ~ Years and sites
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Analysis of Variance
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