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TEKNIK PERMESINAN KAPAL II (Minggu – 3) LS 1329 ( 3 SKS) Jurusan Teknik Sistem Perkapalan ITS Surabaya
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Gas Cycles Carnot Cycle T2 T1 s1 s2 Work W 1 2 3 4 1-2 - ADIABATIC COMPRESSION (ISENTROPIC) 2-3 - HEAT ADDITION (ISOTHERMAL) 3-4 - ADIABATIC EXPANSION (ISENTROPIC) 4-1 - WORK (ISOTHERMAL) Heat Q
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Carnot Cycle Carnot cycle is the most efficient cycle that can be executed between a heat source and a heat sink. However, isothermal heat transfer is difficult to obtain in reality--requires large heat exchangers and a lot of time.
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Carnot Cycle Therefore, the very important (reversible) Carnot cycle, composed of two reversible isothermal processes and two reversible adiabatic processes, is never realized as a practical matter. Its real value is as a standard of comparison for all other cycles.
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Gas cycles have many engineering applications Internal combustion engine Otto cycle Diesel cycle Gas turbines Brayton cycle Refrigeration Reversed Brayton cycle
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Some nomenclature before starting internal combustion engine cycles
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More terminology
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Terminology Bore = d Stroke = s Displacement volume =DV = Clearance volume = CV Compression ratio = r
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Mean Effective Pressure Mean Effective Pressure (MEP) is a fictitious pressure, such that if it acted on the piston during the entire power stroke, it would produce the same amount of net work.
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The net work output of a cycle is equivalent to the product of the mean effect pressure and the displacement volume
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Real Otto cycle
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Real and Idealized Cycle
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Otto Cycle P-V & T-s Diagrams Pressure-VolumeTemperature-Entropy
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Otto Cycle Derivation Thermal Efficiency: For a constant volume heat addition (and rejection) process; Assuming constant specific heat:
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For an isentropic compression (and expansion) process: where: γ = C p /C v Then, by transposing, Otto Cycle Derivation Leading to
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Differences between Otto and Carnot cycles
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The compression ratio (r v ) is a volume ratio and is equal to the expansion ratio in an otto cycle engine. Compression Ratio where Compression ratio is defined as Otto Cycle Derivation
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Then by substitution, The air standard thermal efficiency of the Otto cycle then becomes: Otto Cycle Derivation
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Summarizing where andthen Isentropic behavior Otto Cycle Derivation
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Heat addition (Q) is accomplished through fuel combustion Q = Lower Heat Value (LHV) BTU/lb, kJ/kg Otto Cycle Derivation also
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Effect of compression ratio on Otto cycle efficiency
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Sample Problem – 1 The air at the beginning of the compression stroke of an air-standard Otto cycle is at 95 kPa and 22C and the cylinder volume is 5600 cm 3. The compression ratio is 9 and 8.6 kJ are added during the heat addition process. Calculate: (a) the temperature and pressure after the compression and heat addition process (b) the thermal efficiency of the cycle Use cold air cycle assumptions.
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Draw cycle and label points T 1 = 295 K P 1 = 95 kPa r = V 1 /V 2 = V 4 /V 3 = 9 Q 23 = 8.6 kJ
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Carry through with solution Calculate mass of air: Compression occurs from 1 to 2: But we need T 3 !
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Get T 3 with first law: Solve for T 3 :
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Thermal Efficiency
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Sample Problem – 2
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Solution
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Diesel Cycle P-V & T-s Diagrams
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Sample Problem – 3
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Gasoline vs. Diesel Engine
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