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SERIES RESISTORS AND VOLTAGE DIVISION In Fig. 2.29 the two resistors are in series, since the same current i flows in both of them. Applying Ohm’s law.

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Presentation on theme: "SERIES RESISTORS AND VOLTAGE DIVISION In Fig. 2.29 the two resistors are in series, since the same current i flows in both of them. Applying Ohm’s law."— Presentation transcript:

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2 SERIES RESISTORS AND VOLTAGE DIVISION In Fig. 2.29 the two resistors are in series, since the same current i flows in both of them. Applying Ohm’s law to each of the resistors, we obtain v1 = iR1, v2 = iR2 (2.24) If we apply KVL to the loop (moving in the clockwise direction), we have −v + v1 + v2 = 0 (2.25)

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4 Combining Eqs. (2.24) and (2.25), we get v = v1 + v2 = i(R1 + R2) (2.26) or Notice that Eq. (2.26) can be written as v = i Req Since Req = R1 + R2

5 The equivalent resistance of any number of resistors connected in series is the sum of the individual resistances.

6 Principle of voltage division The source voltage v is divided among the resistors in direct proportion to their resistances; the larger the resistance, the larger the voltage drop.

7 PARALLEL RESISTORS AND CURRENT DIVISION Consider the circuit in Fig. 2.31, where two resistors are connected in parallel and therefore have the same voltage across them. From Ohm’s law, v = i1R1 = i2R2

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9 Applying KCL at node a gives the total current i as i = i1 + i2 (2.34) Substituting Eq. (2.33) into Eq. (2.34), we get where Req is the equivalent resistance of the resistors in parallel:

10 The equivalent resistance of two parallel resistors is equal to the product of their resistances divided by their sum.

11 Thus Therefore

12 Principle of current division The total current i is shared by the resistors in inverse proportion to their resistances. This is known as the principle of current division.

13 Calculation of Req

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17 The End


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