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Splash Screen. WARM-UP PROBLEMS: Solve 4x + 8 = 32. Solve 15 – 3a = 45. Solve –9 + 7x = 68.

Published byKerry Evans Modified over 8 years ago

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Presentation on theme: "Splash Screen. WARM-UP PROBLEMS: Solve 4x + 8 = 32. Solve 15 – 3a = 45. Solve –9 + 7x = 68."— Presentation transcript:

1 Splash Screen

2 WARM-UP PROBLEMS: Solve 4x + 8 = 32. Solve 15 – 3a = 45. Solve –9 + 7x = 68.

3 1.A 2.B 3.C 4.D Five Minute Check 1 (over Lesson 3-5) A.4 B.6 C.8 D.10 Solve 4x + 8 = 32.

4 1.A 2.B 3.C 4.D Five Minute Check 2 (over Lesson 3-5) A.20 B.10 C.–10 D.–20 Solve 15 – 3a = 45.

5 1.A 2.B 3.C 4.D Five Minute Check 3 (over Lesson 3-5) A.12 B.11 C.9 D.8 Solve –9 + 7x = 68.

6 Lesson Menu Main Idea and Vocabulary Key Concept: Perimeter of a Rectangle Example 1:Find the Perimeter of a Rectangle Example 2:Real-World Example

7 Main Idea/Vocabulary Perimeter – the distance around a geometric figure. Area – the measure of the surface enclosed by a geometric figure’s perimeter. Find the perimeters and areas of figures (2.3.8D) (M7.B.2.1).

8 KC 1 Interactive Lab: Perimeter

9 Example 1 Find the Perimeter of a Rectangle Find the perimeter of the rectangle. P = 2ℓ + 2wPerimeter of a rectangle P = 2(18) + 2(2)Replace ℓ with 18 and w with 2. P = 36 + 4Multiply. P = 40Add. Answer: The perimeter is 40 feet.

10 1.A 2.B 3.C 4.D Example 1 A.15 cm B.27 cm C.30 cm D.36 cm Find the perimeter of a rectangle whose length is 12 centimeters and width is 3 centimeters.

11 Example 2 ART A painting has a perimeter of 68 inches. If the width of the painting is 13 inches, what is the length? Answer: The length of the painting is 21 inches. P =2ℓ + 2wPerimeter of a rectangle 68 =2ℓ + 2(13)Replace P with 68 and w with 13. 68 =2ℓ + 26Simplify. 42 =2ℓ Simplify. 21=ℓDivide each side by 2. – 26 = – 26Subtract 26 from each side.

12 1.A 2.B 3.C 4.D Example 2 A.3 feet B.4 feet C.5 feet D.6 feet GARDENS A tomato garden has a perimeter of 22 feet. If the length of the garden is 6 feet, find the width.

13 Guided Practice: 1.Find the perimeter of a rectangle that is 4 yards by 5 yards. 2.Find the perimeter of a rectangle that is 4.5 cm by 1.9 cm. 3. A photograph is 5 inches wide. The perimeter of the photograph is 24 inches. What is the length of the photograph? 2(4) + 2(5) = 8 + 10 = 18 yards 2(4.5) + 2(1.9) = 9 + 3.8 = 12.8 cm 24 – 2(5) = 24 – 10 = 14/2 = 7 inches

14 End of the Lesson

15 Resources Five-Minute Check (over Lesson 3–5) Image Bank Math Tools Solving Equations Using Models Perimeter Solving EquationsTwo-Step Equations

16 End of Custom Shows

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