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Chapter 3 Material Balance Applied to Oil Reservoirs

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1 Chapter 3 Material Balance Applied to Oil Reservoirs
§ 3.1 Introduction -The Schilthuis material balance equation - Basic tools of reservoir engineering => Interpreting and predicting reservoir performance. -Material balance 1. zero dimension – this chapter 2. multi-dimension (multi-phase) – reservoir simulation

2 § 3.2 General form of the material balance equation for a hydrocarbon reservoir
Underground withdrawal (RB) = Expansion of oil and original dissolved gas (RB)………(A) + Expansion of gascap gas (RB) ……………… ………(B) + Reduction in HCPV due to connate water expansion and decrease in the pore volume (RB)……………………… …….……(C)

3

4 Expansion of oil & originally dissolved gas

5 Expansion of the gascap gas
Expansion of the gascap gas =gascap gas (at p) –gascap (at pi)

6 Change in the HCPV due to the connate water expansion & pore volume reduction

7 Underground withdrawal

8 The general expression for the material balance as

9 where

10 No initial gascap, negligible water influx
With water influx eq(3.12) becomes Eq.(3.12) having a combination drive-all possible sources of energy.

11 § 3.4 Reservoir Drive Mechanisms
- Solution gas drive - Gascap drive Natural water drive - Compaction drive In terms of reducing the M.B to a compact form to quantify reservoir performance determining the main producing characteristics, for example, GOR; water cut determining the pressure decline in the reservoir - estimating the primary recovery factor

12 § 3.5 Solution gas drive (a) above the B.P. pressure (b) below the B.P. pressure

13 Above the B.P. pressure - no initial gascap, m=0 - no water flux, We=0 ; no water production, Wp=0 - Rs=Rsi=Rp from eq.(3.7)

14 Exercise3.1 Solution gas drive, undersaturated oil reservoir Determine R.F.
FromTable2.4(p.65) Eq(3.18)

15 Table 2.4 Field PVT P(psia) Bo (Rb/STB) Rs(SCF/STB) Bg( Rb/SCF)
4000 (pi) 3300 (pb)

16 Bo as Function of Pressure

17 Rs as Function of Pressure

18 Bg and E as Function of Pressure

19 Producing Gas-oil Ratio (R) as Function of Pressure

20

21 Below B.P. pressure (Saturation oil) P<Pb =>gas liberated from saturated oil

22 Exercise3.2 Solution gas drive; below bubble point pressure Reservoir-described in exercise Pabandon = 900psia (1) R.F = f(Rp)? Conclusion? (2) Sg(free gas) = F(Pabandon)? Solution: (1) From eq(3.7)

23 Eq(3.7) becomes Conclusion:

24

25 (2) the overall gas balance
liberated gas in the reservoir total amount of gas gas produced at surface gas still dissolved in the oil = − −


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