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1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.III, IV, VIII, and IX 2.I, II, VI, and IX 3.II, III, VI,

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Presentation on theme: "1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.III, IV, VIII, and IX 2.I, II, VI, and IX 3.II, III, VI,"— Presentation transcript:

1 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.III, IV, VIII, and IX 2.I, II, VI, and IX 3.II, III, VI, and X 4.I, IV, VIII, and X 5.None of the first four responses is correct.

2 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.III, V, VIII, and X 2.III, V, VI, and X 3.I, VII, VIII, and X 4.I, V, VI, and IX 5.None of the first four responses is correct.

3 How many faradays (F) are passed through a cell if 4.50 amperes of current are passed through the cell for 2.50 hours? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.6.82 F 2.0.0207 F 3.302 F 4.0.420 F 5.6.99 x 10 -3 F

4 What mass of chromium could be deposited by electrolysis of an aqueous solution of Cr 2 (SO 4 ) 3 for 60.0 minutes using a steady current of 10.0 amperes? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.3.25 g 2.6.47 g 3.17.3 g 4.0.187 g 5.0.373 g

5 How many mL of chlorine gas can be obtained at STP by the electrolysis of molten NaCl using a 0.350 ampere current for 20.0 minutes? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.195 mL 2.48.7 mL 3.133 mL 4.97.5 mL 5.582 mL

6 A cell is constructed by immersing a strip of iron in a solution that is 1.0 M in Fe 2+ ions and connecting this electrode to a standard hydrogen electrode using a wire and a salt bridge. The following observations can be made. The strip of iron loses mass, and the concentration of Fe 2+ ions increases. In the standard hydrogen electrode, the concentration of hydrogen ions decreases. Which of the following is the strongest reducing agent? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.Fe 2+ 2.H + 3.Fe 4.H 2 5.Fe 3+

7 *************************************** A table of standard electrode potentials is necessary for many of the questions below. *************************************** Which of the following is the strongest oxidizing agent? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.Al 3+ 2.Al 3.F 2 4.F - 5.H 2

8 Which of the following species is the strongest oxidizing agent? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.Zn 2+ 2.Zn 3.Hg 2+ 4.Hg 5.Na

9 Which of the following species is the strongest reducing agent? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.Zn 2+ 2.Zn 3.Hg 2+ 4.Hg 5.Ag

10 Which of the following is the strongest reducing agent? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.Na 2.Au 3.Cu 2+ 4.F 2 5.Cd

11 What is the cell potential for a cell constructed by immersing a strip of copper in a 1.0 M CuSO 4 solution and a strip of tin in a 1.0 M SnSO 4 solution and completing the circuit by a wire and a salt bridge? 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.-0.19 V 2.+0.19 V 3.-0.48 V 4.+0.48 V 5.+0.54 V

12 Calculate the cell potential of the following voltaic cell. Zn|Zn 2+ (1.0 x 10 -8 M)||Cu 2+ (1.0 x 10 -6 M)|Cu 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.+1.06 V 2.+1.10 V 3.+1.03 V 4.+1.14 V 5.+1.16 V

13 A voltaic cell is constructed by immersing a strip of copper metal in 1.0 M CuSO 4 solution and a strip of aluminum in 0.50 M Al 2 (SO 4 ) 3 solution. A wire and a salt bridge complete the circuit. The aluminum strip loses mass, and the concentration of aluminum ions in the solution increases. The copper electrode gains mass, and the concentration of copper ions decreases. Calculate the equilibrium constant at 25°C for the cell reaction. (F = 96,500 J/V·mol e - and R = 8.314 J/mol·K) (Round off errors are large!!!) 1234567891011121314151617181920 2122232425262728293031323334353637383940 41424344454647484950 1.4 x 10 41 2.2 x 10 83 3.6 x 10 95 4.3 x 10 101 5.9 x 10 202


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