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Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ): Progress of Rxn (Time) Energy of Products:

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Presentation on theme: "Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ): Progress of Rxn (Time) Energy of Products:"— Presentation transcript:

1 Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ): Progress of Rxn (Time) Energy of Products: Objectives -IWBAT identify the characteristics of exothermic and endothermic -IWBAT interpret a reaction energy diagram Agenda 1.Catalyst 2.Endo/Exo Reaction 3.Perform lab with understanding of heat transfer and endo/exo 4.Practice Homework: none Table of Contents on page 85 Catalyst page 86 3 minutes left A B C D E F

2 Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ) Progress of Rxn (Time) Energy of Products Objectives -IWBAT identify the characteristics of exothermic and endothermic -IWBAT interpret a reaction energy diagram Agenda 1.Catalyst 2.Endo/Exo Reaction 3.Perform lab with understanding of heat transfer and endo/exo 4.Practice Homework: none Table of Contents on page 85 Catalyst page 86 2 minutes left A B C D E F

3 Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ) Progress of Rxn (Time) Energy of Products: Objectives -IWBAT identify the characteristics of exothermic and endothermic -IWBAT interpret a reaction energy diagram Agenda 1.Catalyst 2.Endo/Exo Reaction 3.Perform lab with understanding of heat transfer and endo/exo 4.Practice Homework: none Table of Contents on page 85 Catalyst page 86 1 minute left A B C D E F

4 Catalyst 3/1/12 Match 6 terms to graph Enthalpy Change (ΔH) Energy of Reactants Activation Energy Heat/Energy(kJ) Progress of Rxn (Time) Energy of Products Objectives -IWBAT identify the characteristics of exothermic and endothermic -IWBAT interpret a reaction energy diagram Agenda 1.Catalyst 2.Endo/Exo Reaction 3.Perform lab with understanding of heat transfer and endo/exo 4.Practice Homework: none Table of Contents on page 85 Catalyst page 86 Catalyst Checkers! A B C D E F E. Enthalpy Change D. Energy of Reactants F. Activation Energy A. Heat Energy kJ B. Progress of Rxn (Time) C. Energy of Products

5 Amazing Science! You can be a pioneer in a field 40 years from now

6 Page 91 Feel the top of your desk. Then feel your chair leg. Noticing how they feel different, write down your explanation using specific heat. Hint: think of specific heat’s unit (J/g˚C) and how much energy it takes to change the temperature.

7 Specific Heat can be defined as: the amount of heat per unit mass required to raise the temperature by one degree Celsius.

8 Thermal Equation Q = (m)( ΔT)(Cp) or Heat Gained or Lost = (Mass) x (Change in Temperature) x (Specific Heat)

9 Water’s Specific Heat 1 calorie/gram °C = 4.186 joule/gram °C = 1 Calorie/ kilogram °C

10 Whiteboard Practice

11 The specific heat of aluminum is 0.890 J/g o C. How much heat is transferred when a 545 g aluminum sample is heated from 29 o C to 119 o C? Q = m = C p = ∆T = 119 – 29 = 90 o C ? 545 g 0.890 J/g o C (545)(0.890)(90)= 43654.5 J

12 Whiteboard Practice Determine the specific heat of a certain metal if a 220 gram sample of it loses 14,500 Joules of heat as its temperature drops by 54 o C. Q = m = C p = ∆T = ? J/g o C -54 o C 220 g - 14,500 J 1.22 J/g o C

13 Whiteboard Practice The specific heat of iron is 0.4494 J/g o C. How much heat is transferred when a 247 g iron sample is cooled from 180 o C to 13 o C? Q = m = C p = ∆T = 0.4494 J/g o C 13 – 180 = -167 o C 247 g ? J-18537 J

14 Whiteboard Practice N 2 + 2O 2  2NO 2 a.Calculate ΔH b.Endo or Exothermic? Endothermic (+ΔH) Heat is gained Products - Reactants 2(33.2) - (1(0)+ 2(0)) = 66.4 kJ/mol ProductsReactants

15 Whiteboard Practice N 2 + 2O 2  2NO 2 Rewrite the equation with ΔH Sketch a graph of what it would look like 66.4 kJ + N 2 + 2O 2  2NO 2 ΔH = 66.4 kJ/mol

16 Whiteboard Practice 4NH 3(g) + 7O 2  4NO 2(g) + 6H 2 O (l) a.ΔH b.Endo or Exothermic? (-1714.8) - (-184.4)= -1530.4 kJ/mol - ΔH so Exothermic. Heat is being released. Products - Reactants ProductsReactants 4(33.2) + 6(-285.8) - (4(-46.1) + 7(0)) =

17 Whiteboard Practice 4NH 3(g) + 7O 2  4NO 2(g) + 6H 2 O (l) Rewrite the equation with ΔH Sketch a graph of what it would look like 4NH 3(g) + 7O 2  4NO 2(g) + 6H 2 O (l) +1530.4 kJ ΔH = -1530.4 kJ/mol

18 a. Determine the heat of reaction, ΔH, for this reaction. b. Write the chemical equation with heat value 2MgCl 2 + O 2 2MgO + 2Cl 2 2(-601.7) + 2(0) - (2(-641.3) + 1(0)) = -1203.4 - (-1282.62)= 79.22 kJ/mol 79.22 kJ + 2MgCl 2 + O 2  2MgO + 2Cl 2 Products Reactants Products - Reactants

19 Whiteboard Practice Which equation(s) could be represented by graph? A.CH 4 +2 O 2  CO 2 + 2H 2 O + 890 kJ B.2NaHCO 3 + 129 kJ  Na 2 CO 3 + H 2 O + CO 2 C.Ca(OH) 2  CaO + H 2 O ΔH= 65.2 kJ Exothermic! Heat is released! -ΔH or kJ on Products side! Exothermic Endothermic (heat is absorbed)


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