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Acids And Bases
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Class question Where can acids be found? –Sodas –Stomach –Vinegar –Citrus fruits Where can bases be found? –Soap –Drano –Antacid tablets –Windex –detergent
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Properties of Acids Taste sour React with bases Litmus paper test – turn blue litmus paper red Electrolytic – conduct electricity
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Properties of Bases Taste bitter Feels slippery React with acids Litmus paper test – turn red litmus paper blue electrolytic
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Nomenclature of Acids Acids are composed of a(n) ________________ followed by a(n)_______ Hydrogen ion (H + ) anion Ex: H + + Cl 1- H + + SO 4 2- HCl H 2 SO 4
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Binary Acids H + + anion H + + anion with –ide ending acid name is __________________ HCl anion? _______ acid name ________________ Hydro _____ic acid Hydrochloric acid chloride
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Binary Acids H + + anion H + + anion with –ide ending acid name is __________________ HF anion? _______ acid name ________________ Hydro _____ic acid Hydrofluoric acid fluoride
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Oxyacids H + + anion H + + anion with –ate ending acid name is __________________ HNO 3 anion? _______ acid name ________________ _____ic acid nitric acid nitrate
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Oxyacids H + + anion H + + anion with –ate ending acid name is __________________ H 2 SO 4 anion? _______ acid name ________________ _____ic acid sulfuric acid sulfate
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Oxyacids H + + anion H + + anion with –ite ending acid name is __________________ HNO 2 anion? _______ acid name ________________ _____ous acid nitrous acid nitrite
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Oxyacids H + + anion H + + anion with –ite ending acid name is __________________ HClO 2 anion? _______ acid name ________________ _____ous acid chlorous acid chlorite
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Writing acid formulas Hydrobromic acid anion? ___________ formula ______ Acetic acid anion? ___________ formula ______ Nitrous acid anion? ___________ formula ______ HBr HC 2 H 3 O 2 HNO 2 Bromide (Br 1- ) acetate(C 2 H 3 O 2 1- ) nitrite (NO 2 1- )
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Nomenclature of Bases Bases are composed of a(n) _______ followed by a(n) ________________ cation hydroxide (OH 1- )
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Writing Base Names Rule: name the cation and add “hydroxide” NaOH Mg(OH) 2 Fe(OH) 3 sodium hydroxide magnesium hydroxide Iron (III) hydroxide Memorize: NH 3 = ammonia
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Writing base formulas potassium hydroxide cation? ______ formula ______ Calcium hydroxide cation? ______ formula ______ Aluminum hydroxide cation? ______ formula ______ KOH Ca(OH) 2 Al(OH) 3 K+K+ Ca 2+ Al 3+
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Ions In Solution Why are some solutions acidic, basic, or neutral? It depends on number of H + and OH - ions present.
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Ions In Solution Acidic solution – contain more H + ions than OH - ions 4000 H + and 0 OH - is acidic 1000 H + and 500 OH - is acidic 5 H + and 3 OH - is acidic
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Ions In Solution Basic Solution – contain more OH - ions than H + ions 4000 OH - and 0 H + is basic 1000 OH - and 500 H + is basic 5 OH - and 3 H + is basic
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Ions In Solution Neutral Solution – equal amounts of H + and OH - ions 4000 OH - and 4000 H + is neutral 1000 OH - and 1000 H + is neutral 5 OH - and 5 H + is neutral
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Self Ionization of Water Proper ionization H 2 O + H 2 O hydronium ion O HH H H O HH O HH O + + H 3 O + + OH -
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Self Ionization of Water simplified version H 2 O → H + + OH -
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Types of Acids/Bases Arrhenius Model Bronsted-Lowry Model Lewis Model
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Arrhenius Model of Acids and Bases Arrhenius Acids –D–Defn: contain H + and ionizes to form H + –E–Examples HCl HNO 3 H + + Cl - H + + NO 3 - makes solution ACIDIC
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Arrhenius Model of Acids and Bases Arrhenius Bases –Defn: –contain OH - and ionizes to produce OH - ions –Examples NaOH Ca(OH) 2 Na + + OH - Ca 2+ + 2 OH - makes solution BASIC
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Flaw with Arrhenius model Not all bases contain hydroxide Ex: ammonia (NH 3 ) is basic Therefore a new type of acid/base must be determined
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Bronsted-Lowry Model Bronsted-Lowry Acid –Defn: proton/H + donor can give H + to another species Bronsted-Lowry Base –Defn: proton/H + acceptor can take H + from another species
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Bronsted-Lowry Model REMEMBER!!!! REMEMBER!!!! acids donate, bases accept protons Abigail doesn’t buy apples.
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Examples HCl + H 2 O Cl - + H 3 O + What is happening here? Acid (donates proton) Base (accepts proton) Which is the acid? base?
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Bronsted-Lowry Model Examples NH 3 + H 2 O NH 4 + + OH - What is happening here? Acid (donates proton) Base (accepts proton) Which is the acid? base?
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Lewis Model Lewis acid –an atom, ion, or molecule that accepts an electron pair to form a covalent bond Lewis base –An atom, ion, or molecule that donates an electron pair to form a covalent bond
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Lewis Model Lewis acid-base reaction –The formation of one or more covalent bonds between an electron-pair donor and an electron-pair acceptor
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Conjugate Acid/Base Pairs Conjugate acid – new species produced when base gains H + ion Conjugate base – new species produced when acid donates H + ion
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Conjugate Acid/Base Pairs general Bronsted-Lowry reaction acid + base conj. acid + conj. base conj. acid/base pair Every acid has a conjugate base. Every base has a conjugate acid.
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Conjugate Acid/Base Pairs Examples HNO 3 + H 2 O H 3 O + + NO 3 - What is the acid? base? acidbase What is the conjugate acid/base? C.A.C.B. conj. acid/base pair
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Conjugate Acid/Base Pairs Examples NH 3 + H 2 O NH 4 + + OH - What is the acid? base? acidbase What is the conjugate acid/base? C.B.C.A. conj. acid/base pair
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Conjugate acid-base pairs What is the conjugate base of: H 2 SO 4 _________ H 3 O + ________ What is the conjugate acid of: HPO 4 2- _________ OH 1- ________ HSO 4 1- H 2 PO 4 1- H2OH2O H2OH2O How can H 2 O be both acid and base?
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What is the conjugate base? AcidConjugate Base H 2 SO 4 HPO 4 2- NH 4 1+ H 3 O 1+ H 2 O HSO 4 1- PO 4 3- NH 3 H 2 O OH - How can H 2 O be both acid and base?
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Amphoteric Defn – substance that can act as both acids and bases HNO 3 + H 2 O H 3 O + + NO 3 - NH 3 + H 2 O NH 4 + + OH - base acid Water is amphoteric b/c it is acts as a base in one reaction and acts as an acid in the second Is H 2 O a base or acid? Is H 2 O a base or acid?
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Mono-, Di-, Triprotic Acids Defns –monoprotic (HA) – one ionizable proton ex: HF, HCl, HBr (= normality is 1) –diprotic (H 2 A) – two ionizable protons ex: H 2 SO 4, H 2 CO 3 (= normality is 2) –triprotic (H 3 A) – three ionizable protons ex: H 3 PO 4, H 3 BO 3 (= normality is 3)
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Polyprotic Acid Ionization Always forms ONE H + H 3 PO 4 H 2 PO 4 1- HPO 4 2- H 2 PO 4 1- + H + HPO 4 2- + H + PO 4 3- + H +
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Strong Acid/Base Defn – acid or base that completely ionizes HA H + + A - XOH X + + OH - 100% ionization every single HA molecule ionizes into H+ and A- 100% ionization
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Strong Acid Illustration H A H A H A H A H A H A + - + - + - All break into ions + + +
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Strength of Acids and Bases Acid/base strength is based on the degree to which they ionize 1) strong ( ) 2) weak ( )
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6 Strong Acids HCl – hydrochloric acid HBr – hydrobromic acid HI – hydroiodic acid HClO 4 – perchloric acid H 2 SO 4 – sulfuric acid HNO 3 – nitric acid
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Strong Bases Group I and II metal hydroxides LiOH NaOH KOH RbOH Mg(OH) 2 Ca(OH) 2 Sr(OH) 2 Ba(OH) 2 No need to memorize exact ones
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Weak Acid/Base Defn – acid or base that partially ionizes HA H + + A - XOH X + + OH - partial ionization Únot all will ionize; the weaker it is the less it ionizes
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Weak Acid Illustration H A H A H A H A H A H A + - Only some break into ions +
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What are the weak acids and bases? The ones that are NOT strong
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Strong or weak, concentrated or diluted For acids and bases, it is important to distinguish between concentrated and dilute from strong and weak. The words _________ and __________ have different meanings. Similarly, ___________ and ___________ are not the same either. strong weak concentrated dilute
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Strong or weak, concentrated or diluted Strong and weak refer to ____________________________ Concentrated and dilute refer to ____________________________ how much substance ionizes how much solute is present
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Example 1 M HCl 12 M HCl 1 M H 2 CO 3 12 M H 2 CO 3 Strong and dilute Strong and concentrated weak and dilute weak and concentrated
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Ion Product Constant for Water (K w ) Defn: equilibrium value for self ionization of water (H 2 O H + + OH - ) Formula K w = [H + ][OH - ] = 1 x 10 -14 ALWAYS
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Ion Product Constant for Water (K w ) in pure water [H + ] = [OH - ] = 1 x 10 -7 M in non pure water (acidic/basic conditions), value of [H + ] and [OH - ] differ Remember pure water is neutral But still [H + ][OH - ] = 1 x 10 -14
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Is solution acidic, basic, or neutral? Acidic Basic neutral [H + ] > [OH - ] [H + ] < [OH - ] [H + ] = [OH - ]
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pH and pOH pH a)Defn: pH = -log [H + ] b)Scale: range from 0 to 14 0714 ACIDICBASIC (neutral) pH
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c)change one pH unit represents a ten fold change in strength - ex: pH = 3 vs pH = 4 pH 3 is 10 1 or 10 times more acidic - ex: pH = 7 vs pH = 10 pH 7 is 10 3 or 1000 times more acidic
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pOH Formula: -log [OH - ]
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Relation of pH and pOH pH + pOH = 14 If given one variable, subtract to find the other
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Overall Relationship pHpOH [H + ][OH - ]
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Sample problem #1 Calculate the pH of a solution with [H + ] = 3.0 x 10 -6 M. pH = -log [H + ] = - log [3.0 x 10 -6 ] = 5.52
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Sample problem #2 Calculate the pH of a solution with [OH - ] = 8.2 x 10 -6. pOH= -log[OH - ] = -log [8.2 x 10 -6 ] = 5.09
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Sample problem #2 pH + pOH = 14 pH + 5.09 = 14 pH = 8.91
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Sample problem #2 Calculate the pH of a solution with [OH - ] = 8.2 x 10 -6. [H + ][OH - ] = 1 x 10 -14 [H + ][8.2 x 10 -6 ] = 1 x 10 -14 [H + ] = 1.22 x 10 -9 pH = -log[1.22 x 10 -9 ] = 8.91
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Sample problem #3 What is the [H + ] of a solution with pH = 2? pH = -log[H + ] [H + ] = 10 -pH = 10 -2 = 0.01 M
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Sample problem #4 (i) What is the [OH-] of a solution with pOH = 3.7? [OH - ] = 10 -pOH [OH - ] = 10 -3.7 = 1.995 x 10 -4 M = 2.0 x 10 -4 M
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Sample problem #4 (ii) What is the pH? pH + pOH = 14.0 pH + 3.7 = 14.0 pH = 10.3
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Sample problem #4 (iii) What is the [H + ] ? [H + ] = 10 -pH = 10 -10.3 = 5.01 x 10 -11 M
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Reaction between acids and bases Neutralization (defn) – reaction of acid and base to form a salt and water –The reaction is a double replacement Salt (defn) – ionic compound made of cation from base and anion from acid
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Reaction between acids and bases Ex reaction Mg(OH) 2 + HCl MgCl 2 + H 2 O baseacidsalt water Mg 2+ + OH - H + + Cl - Mg 2+ - cation from base Cl - - anion from acid
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Ex problems i) What is the salt formed from sulfuric acid (H 2 SO 4 ) and potassium hydroxide (KOH)? base cation? acid anion? K + SO 4 2- What is salt?K 2 SO 4
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ii) What is the salt formed when Al(OH) 3 and HBr react? base cation? acid anion? Al 3+ Br - What is salt?AlBr 3
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Is salt solution acidic, basic, or neutral? a)strong acid + strong base b)strong acid + weak base c) weak acid + strong base Neutral salt acidic salt basic salt
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Ex problem Determine if salt solution is acidic, basic, or neutral. a)LiBr acid? base? HBr LiOH (strong acid) (strong base) Salt is ____________ NEUTRAL Li + + Br -
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Ex problem Determine if salt solution is acidic, basic, or neutral. b)Fe(NO 3 ) 3 acid? base? HNO 3 Fe(OH) 3 (strong acid) (weak base) Salt is ____________ ACIDIC Fe 3+ + NO 3 -
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Acid-Base Indicator A compound that will change color as the pH changes –Phenolphthalein changes between clear and pink –Hydrangeas grow pink or blue depending on the pH of their soil
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How does an indicator work? Indicators are weak acids or weak bases. In the acid form they have one color. When they switch to the base form they have a different color.
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Titration The controlled addition and measurement of the amount of a solution of known concentration required to react completely with a measured amount of a solution of unknown concentration.
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Why do we use titrations? To experimentally determine the concentration of a solution –The bottle wasn’t labeled –The label faded –Your chemistry teacher is evil
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How do we conduct a titration? 1.Measure a volume of the solution of unknown concentration into a flask. 2.Add 3 to 5 drops of indicator. 3.While stirring slowly add a measured volume of the solution of known concentration to the flask. 4.Use math to find the concentration you don’t know. Read pages 500 – 501 for a more detailed explanation, including pictures showing this process.
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Equivalence point: Moles of hydrogen ions = moles of hydroxide ions M H+ V H+ = M OH- V OH-
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End Point When the indicator changes color This is when you stop adding the known into the unknown Use the volume at the end point for your calculations
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Sample Problem In a titration, 25.0 mL of 0.0350 M Ba(OH) 2 neutralizes 16.5 mL of HCl solution. What is the molarity of the HCl solution?
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Sample Problem In a titration, 25.0 mL of 0.0350 M Ba(OH) 2 neutralizes 16.5 mL of HCl solution. What is the molarity of the HCl solution? N b = 0.0350 * 2 = 0.0700 (2 hydroxides in each one)
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Sample Problem In a titration, 25.0 mL of 0.0350 M Ba(OH) 2 neutralizes 16.5 mL of HCl solution. What is the molarity of the HCl solution? N b = 0.0350 * 2 = 0.0700
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Sample Problem In a titration, 25.0 mL of 0.0350 M Ba(OH) 2 neutralizes 16.5 mL of HCl solution. What is the molarity of the HCl solution? N b = 0.0350 * 2 = 0.0700
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