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Published byOscar Clark Modified over 8 years ago
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Exponential and Logarithmic Functions Section 5.4
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y = 2 x Jeff Bivin -- LZHS xy -21/4 ½ 01 12 24 38 xy 1/4-2 ½ 10 21 42 83 x = 2 y
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How do we solve this exponential equation for the variable y? y = 2 x x = 2 y Jeff Bivin -- LZHS
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LOGARITHMS exponentiallogarithmic b > 0 A > 0 Jeff Bivin -- LZHS
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Natural Logarithms exponentiallogarithmic Jeff Bivin -- LZHS
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exponentiallogarithmic Jeff Bivin -- LZHS
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Evaluate Jeff Bivin -- LZHS
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Evaluate Jeff Bivin -- LZHS
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Evaluate Jeff Bivin -- LZHS
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Evaluate Jeff Bivin -- LZHS
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Solve for x log 2 (x+5) = 4 2 4 = x + 5 16 = x + 5 11 = x Jeff Bivin -- LZHS
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Solve for x log x (32) = 5 x 5 = 32 x 5 = 2 5 x = 2 Jeff Bivin -- LZHS
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Evaluate log 3 (25) = u 3 u = 25 3 u = 5 2 ?????? Jeff Bivin -- LZHS find out how, tomorrow
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