1. Problem 2.131 y C D A container of weight W = 1165 N is supported O
600 mm
320 mm
450 mm
360 mm
500 mm D O C B A x y z
A container of weight
W = 1165 N is supported
by three cables as shown.
Determine the tension in
each cable.

2. F d y Solving Problems on Your Own C D A container of weight O
600 mm
320 mm
450 mm
360 mm
500 mm D O C B A x y z
Problem
Solving Problems on Your Own
A container of weight
W = 1165 N is supported
by three cables as shown.
Determine the tension in
each cable.
1. Draw a free-body diagram of the particle. This diagram shows
the particle and all the forces acting on it.
2. Resolve each of the forces into rectangular components.
Follow the method outlined in the text.
F = F l = (dx i + dy j + dz k) F d

3. Solving Problems on Your Own
600 mm
320 mm
450 mm
360 mm
500 mm D O C B A x y z
Problem
Solving Problems on Your Own
A container of weight
W = 1165 N is supported
by three cables as shown.
Determine the tension in
each cable.
3. Set the resultant, or sum, of the forces exerted on the particle
equal to zero. You will obtain a vectorial equation consisting
of terms containing the unit vectors i, j, and k. Three scalar
equations result, which can be solved for the unknowns.

4. S F = 0 TAB + TAC + TAD + W = 0 AB = (450 mm)i + (600 mm)j AB = 750 mm
Problem Solution
600 mm
320 mm
450 mm
360 mm
500 mm D C B A x y z
TAD
TAB
TAC
W = _ (1165 N) j O
Draw a free-body diagram of the particle.
S F = 0
TAB + TAC + TAD + W = 0
AB = (450 mm)i + (600 mm)j AB = 750 mm
AC = (600 mm)j _ (320mm)k AC = 680 mm
AD = (_500 mm)i + (600 mm)j + (360 mm)k AD = 860 mm

5. ( ) ( ) ( ) ( ) ( ) 450 750 i 600 j TAB = (0.6 i + 0.8 j) TAB
600 mm
320 mm
450 mm
360 mm
500 mm D C B A x y z
TAD
TAB
TAC
W = _ (1165 N) j O
Problem Solution
Resolve each of the forces
into rectangular components.
( )
450
750 i +
600 j
TAB
= (0.6 i j) TAB
TAB = TAB lAB = AB =
TAC AC
( )
600
320
680 k
( ) 15 8
TAC = TAC lAC = = j
TAC = j j
TAC
680 _ _ 17 17
TAD AD
( )
500
860 i +
600
j +
360 k
TAD = TAD lAD = =
TAD =
( ) 25 43 i + 30
j + 18 k =
TAD

6. 0.6 TAB _ 25 43 TAD = 0 TAB = 0.9690 TAD 15 17 30 43 TAD 0.8 TAB + TAC
600 mm
320 mm
450 mm
360 mm
500 mm D C B A x y z
TAD
TAB
TAC
W = _ (1165 N) j O
Problem Solution
Set the resultant, or sum, of
the forces exerted on the
particle equal to zero.
Substitution into S F = 0,
factor i, j, k and set their
coefficients to zero:
0.6 TAB _ 25 43
TAD = 0
TAB = TAD
(1) 15 17 30 43
TAD
0.8 TAB +
TAC +
_ 1165 N = 0 +
(2) 8 17 18 43
TAD = 0
_ TAC +
TAC = TAD
(3)

7. 600 mm
320 mm
450 mm
360 mm
500 mm D C B A x y z
TAD
TAB
TAC
W = _ (1165 N) j O
Problem Solution
Substitution for TAB and
TAC from (1) and (3)
into (2): 15 17 30 43
( 0.8 x x )TAD _ 1165 N = 0
TAD _ 1165 N = 0
TAD = 516 N
TAB = 500 N
TAC = 459 N
From (1): TAB = (516 N)
From (3): TAC = (516 N)