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Published byEdwin Boyd Modified over 9 years ago
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Pointers, Variables, and Memory
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Variables and Pointers When you declare a variable, memory is allocated to store a value. A pointer can be used to hold the address to a chunk of memory. The operator & is used to return a variable’s memory address int intVar;// allocate memory by // declaring a variable cout << " Address = " << &intVar << endl;
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Variables and Pointers A pointer variable is used to hold an address to a memory location. A pointer variable has a type associated with it, and the memory address it points to, should hold data of that type int myInt = 0;// Allocates memory, stores 0 int *pMyInt;// Declares an empty pointer // variable
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Dereferencing Pointers If we want to set or get the value that is stored at the memory address in the pointer then we have to use operator* int myInt = 0;//Allocates memory, stores 0 int *pMyInt;//Declares an empty pointer pMyInt = &myInt;//Puts address in the ptr variable name myInt pMyInt 3000 3004 3008 0 3004 valuememory address 3012
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Dereferencing Pointers If we want to set or get the value that is stored at the memory address in the pointer then we have to use operator* int myInt = 0;//Allocates memory, stores 0 int *pMyInt;//Declares an empty pointer pMyInt = &myInt;//Puts address in the ptr *pMyInt = 5;//puts 5 into myInt variable name myInt pMyInt 3000 3004 3008 5 3004 valuememory address 3012
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Dereferencing Pointers If we want to set or get the value that is stored at the memory address in the pointer then we have to use operator* int myInt = 0;//Allocates memory, stores 0 int *pMyInt;//Declares an empty pointer pMyInt = &myInt;//Puts address in the ptr *pMyInt = 5;//puts 5 into myInt cout << myInt << endl;//Prints 5 cout << *pMyInt << endl;//Also prints 5 cout << pMyInt << endl;//What prints? variable name myInt pMyInt 3000 3004 3008 5 3004 valuememory address 3012
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Where are the errors? int main(){ int m; int *pm; *pm = 5; int n; int *pn = &n; pn = 5; }
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Where are the errors? int main(){ int m; int *pm; *pm = 5; int n; int *pn = &n; pn = 5; } ERROR! No address in pm //Correction pm = &m; *pm = 5;
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Where are the errors? int main(){ int m; int *pm; *pm = 5; int n; int *pn = &n; pn = 5; } ERROR! No address in pm //Correction pm = &m; *pm = 5; ERROR! Missing operator* //Correction *pn = 5;
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Pointers & Arrays Pointers are simply, by definition, variables that hold addresses. A name of an array also holds the address of the first element in the array. This value cannot change. Therefore, an array name can be considered to be a pointer constant.
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Pointers & Arrays const int CAPACITY = 5; int myArray[CAPACITY];//Declare an array cout << myArray;//Prints its address for( int i=0; i<CAPACITY; ++i ) myArray[i] = i;//initialize the elements cout << *myArray << endl;//Prints 0 cout << myArray[0] << endl;//Prints 0 01234 01234 myArray
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Pointer Arithmetic Pointer arithmetic allows a few arithmetic operators for manipulating the addresses in pointers. In an array a, a is a constant pointer to the first element and a+1 is a constant to the second element. In the same way, if p points to the second element in an array, then p-1 point to the preceding element in that array, and p+1 points to the succeeding element.
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Pointer Arithmetic int a[5] = {2, 4, 6, 8, 10}; int *p; p = &a[1]; cout << a[0] << ", " << p[-1]<< ", " << *(p - 1) << endl; cout << a[1] << ", " <<p[0]<< ", " << *(p) << endl; cout << a[2] << ", " << p[1]<< ", " << *(p + 1) << endl; Output: 2, 2, 2 4, 4, 4 6, 6, 6
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Incrementing and Decrementing Addresses with Postfix and Prefix Operators Adding 1 to a pointer causes the pointer to point to the next element of the type being pointed to. Therefore p++ should point to the next element. However, when a combination of indirection and postfix operators are used ( as is often done), use the precedence table to figure out what gets executed first. Postfix operators have higher precedence than the indirection operator.
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Incrementing and Decrementing Addresses with Postfix and Prefix Operators int *p; int a[5] = {12, 4, 16, 98, 50}; p = a; cout << (*p)++ << endl;// prints 12 cout << *p << endl;// print 4 cout << *++p << endl;// prints 16 cout << *p << endl; // prints 16 cout << (*p)-- << endl; // prints 16 cout << *p << endl; // prints 4 cout << *--p << endl; // prints 12 cout << *p << endl; // prints 12 Is this the same as *p++? Is this the same as *(--p) ?
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Dynamically Allocating Arrays An array can be created “dynamically” with “new” “new” allocates a section of memory for the array, and then returns a pointer to it. This is a major advantage when you don’t know how large the array will be until the program is running int capacity, *myData; cin >> capacity; myData = new int[capacity];//Creates the array for( int i=0; i<capacity; ++i ) //Initialize it myData[i] = i; cout << myData[0] << endl; //Prints 0 delete [] myData;
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Using delete Memory allocated with “new” must always be recovered by “delete” Always “delete” an array when you don’t need it anymore if you created it with “new” delete [] myData;
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Function Arguments The variables that are used to pass data into a function or to return results Example bool isPalindrome( string forw, string rev ){ if( forw == rev ) return true; } Arguments can be passed – By value – the default in C++ – By reference arguments or parameters function name return type
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Passing Arguments by Value Used to pass data only into a function When a variable is passed by value, a copy of it is made inside the function. The copy is destroyed when the function returns. Example: passing an argument by value void noChange( int n ){ n = n + n; } int main() { int num = 5; noChange( num ); cout << num << endl; //prints 5 }
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Reference Argument Syntax int &count Indicates that an alias for the argument is used inside the function
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Using References Used primarily for function arguments to implement “passing by reference” Advantage: Efficiency – Passing variables to functions by reference is very useful if you want to change or update a variable through a function. – If your variable is a relatively large variable, or a whole class or struct or array, it is always advisable to pass the variable by reference since big amounts of data need not be copied when evaluating them.
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Passing Arguments by Reference # include void Square(int &pVal); main() { int Number=10; printf("Number is %d\n", Number); Square(Number); printf("Number is %d\n", Number); } void Square(int &pVal) { pVal *= pVal; printf("Number is %d\n", pVal); }
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Passing Arguments by Pointer #include void Square(int *pVal); main() { int Number=10; printf("Number is %d\n", Number); Square(&Number); printf("Number is %d\n", Number); } void Square(int *pVal) { *pVal *= *pVal; printf("Number is %d\n", *pVal); }
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Reference vs. Pointers References cannot be re-assigned. They are like constant pointers. A good rule of the thumb is to use references when you can, and pointers when you ‘have to’
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Passing an Array to a Function Since an array name is actually a pointer to its first element, when an array is passed to a function, an address operator is not needed. int findMax ( int [], int ); int main() { int a[5] = {12, 4, 16, 98, 50}; cout << "The maximum value is " << findMax(a, 5) << endl; return 1; } int findMax ( int vals[], int numElem ) { int max = vals[0]; for (int i=1; i<numElem; i++ ) if (max < vals[i] ) max = vals[i]; return max; }
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Passing an Array to a Function However, since an address is actually passed, the code can also be written thus: int findMax ( int [], int ); int main() { int a[5] = {12, 4, 16, 98, 50}; cout << "The maximum value is " << findMax(a, 5) << endl; return 1; } int findMax ( int *vals, int numElem ) { int max = vals[0]; for (int i=1; i<numElem; i++ ) if (max < vals[i] ) max = vals[i]; return max; }
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Passing an Array to a Function Here are two other versions of findMax, this time using pointers instead of array subscripts: int findMax ( int *vals, int numElem ) { int max = *vals; for (int i=1; i<numElem; i++ ) if (max < *(vals + i) ) max = *(vals + i); return max; }
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Passing an Array to a Function int findMax ( int *vals, int numElem ) { int max = *vals++;// gets the first element and // then increments for (int i=1; i<numElem; i++, vals++ ) if (max < *vals ) max = *vals; return max; }
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Dynamically Allocated structs We can dynamically create a structure with “new” Use “new” to allocate memory and return a pointer Person *pDonald = new Person; When a pointer is used to set values stored in a structure, each field must be accessed by the “ -> ” operator pDonald->ID = 1005; pDonald->firstName = "Donald"; pDonald->lastName = "Knuth"; cout firstName << endl; delete pDonald;//Always delete after new Optional syntax: cout << (* pDonald ).firstName;
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Dynamic Memory Allocation Data structures that use arrays, structs, and objects to store their data often use dynamic memory allocation to create the storage space More efficient – We don’t need to know in advance how much space to set aside – Pointers can be passed to functions more efficiently because pointer parameters are passed by reference
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Struct Constructors Creating a structure that initializes itself struct Person{ int ID; string name; Person(int i = 0000, string n = "Adam") : ID(i), name(n) { } }; Constructor is called whenever a Person is declared Person adam;//Default values used cout << adam.name << endl;//Prints Adam Person david(1002,"David");//Arguments used Person *pFrank = new Person;//Default values used pFrank->name = "Frank"; Initializer list Default value Parameter Constructor name
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