1. Mark Dixon Page 1 05 – Problem Solving & Data Types

2. Mark Dixon Page 2 Question: Pseudo-code Write VBScript code that does the following: when btnDown is clicked read txtNum subtract 1 put in txtNum Sub btnDown_onClick() txtNum.value = txtNum.Value + 1 End Sub

3. Mark Dixon Page 3 Can't touch this Student work from last week: based on work done by Daniel Thornton & David Orrock

4. Mark Dixon Page 4 Questions name: event, object, property, event handler, operator, function, expression Sub window_onLoad() imgHammer.style.posLeft = 500 imgHammer.style.posTop = 100 imgHammer.style.height = 100 imgHammer.style.width = 75 sndPlayer.URL = "Hammer.wav" End Sub Sub imgHammer_onMouseOver() imgHammer.style.posLeft = Rnd() * (document.body.clientWidth - imgHammer.width) imgHammer.style.posTop = Rnd() * (document.body.clientHeight - imgHammer.height) End Sub

5. Mark Dixon Page 5 Session Aims & Objectives Aims –to introduce the idea of types of data –to provide a more explicit understanding of problem solving skills and strategies Objectives, by end of this week’s sessions, you should be able to: –recognise different types of data numeric string (text) –correct errors relating to data types –recognise the key aspects of a problem start state goal state operations –be able to use typical strategies to solve unfamiliar programming problems

6. Mark Dixon Page 6 Example: AddNum v1 Add Numbers Sub btnAdd_OnClick() lblResult.innerText = txtNum1.value + txtNum2.value End Sub Doesn't work!

7. Mark Dixon Page 7 Types of Information Numeric (numbers)29 (integer/whole) 56.23 (real/decimal) String (text)"Hello there!" "BOO" Pictures (numbers) Sound (numbers)

8. Mark Dixon Page 8 AddNum problem The + operator works with: –numbers, and –text 23 + 16 39 "23" + "16" "2316" double quotes enclose text Text input boxes store text: txtNum1.value + txtNum2.value We need to convert text to numbers

9. Mark Dixon Page 9 String Functions CInt("63") convert to integer result is 63 Left("boo",2) left stringresult is "bo" Right("hello",3) right stringresult is "llo" Mid("hello",2,3) middle stringresult is "ell" Len("S Smith") lengthresult is 7 Space(5) spacesresult is " "

10. Mark Dixon Page 10 String Expressions

11. Mark Dixon Page 11 String Expressions & Errors "What is " & txtN1.value & " times " "What is twice " txtN1.value & "?" "What is 6 minus " & & txtN1.value & "?" "This is a number & txtN1.value data operator data operator ERROR! missing data ERROR! missing operator ERROR! missing "

12. Mark Dixon Page 12 Questions: String Expressions a)What is the result of: Mid("what is the time?", 3, 4) b)What is the result of: Left("bob", 2) & Right("sal", 1) c)Write an expression to: convert "16" to a number d)Write an expression to: give the first two letters of "Mr John Smith" "at i" "bol" CInt("16") Left("Mr John Smith", 2)

13. Mark Dixon Page 13 Example: AddNum v2 Add Numbers Sub btnAdd_OnClick() lblResult.innerText = CInt (txtNum1.value) + CInt (txtNum2.value) End Sub

14. Mark Dixon Page 14 Nested functions nested functions (one inside another): Right(Left("Hello there", 5), 2) do what is in the brackets first Right(Left("Hello there", 5), 2) = Right( "Hello", 2) = "lo"

15. Mark Dixon Page 15 Types of problem two types of problem: –Known problems: which we have successfully dealt with before, and can remember the solution –Unknown problems: which we have never seen before, and therefore have to discover / invent a solution for ourselves

16. Mark Dixon Page 16 What is a problem? All problems different However, have key parts: –Start state –Goal state –set of available operations Problem solving is the process of searching for a sequence of operations that will take us from the start state to the goal state

17. Mark Dixon Page 17 Example: Light Start state: light is off Goal state: light on Set of operations: –Push switch up (turns light on) –Push switch down (turns light off) Solution: 1. Push switch up Simple problems – small number of operations to solve

18. Mark Dixon Page 18 Goal state Start state Operations –Move Up –Move Down –Move Left –Move Right Solution: Example: Movement 1.Move Up 2.Move Up 3.Move Up 4.Move Right 5.Move Right 6.Move Right 1.Move Up 2.Move Right 3.Move Up 4.Move Right 5.Move Up 6.Move Right or

19. Mark Dixon Page 19 Important steps It is essential to understand the problem (start state, goal state, and operations) prior to finding a solution It is also often essential to be able to break a problem down into smaller sub-problems, i.e. identify intermediate sub-goal states failure to solve a problem is often due to these

20. Mark Dixon Page 20 More Complex Problems More complicated problems involve –the use of multiple operations to get from the start to the goal state –conditional execution of operations only do this if… (future lecture) –repeated operations do this until… (future lecture) –abstraction – more general description

21. Mark Dixon Page 21 Example: Horizontal mid point Start state: an image on the screen Goal state: to calculate its horizontal mid point Set of operations: –posLeft: gives the position of its left edge –posTop: gives the position of its top edge –Width: gives the distance between its left and right edges –Height: gives the distance between it top and bottom edges Solution: 1. get the posLeft value 2. add half the Width

22. Mark Dixon Page 22 Example: First Character Start state: the piece of text (e.g. "Hello") Goal state: extract the first character of a piece of text Set of operations: –Len(s): gives the number of characters in s –Right(s, n): gives n characters from the right of s –Left(s, n): gives n characters from the left of s –Mid(s, p, n): gives n characters from s, starting at position p Solution: 1. Left(text, 1)

23. Mark Dixon Page 23 Concrete vs. Abstract problems People can solve concrete problems easily –what is the first letter of hello –what is the first letter of you surname –an object's left edge is at position 100 the object is 50 wide where is its mid point? It is often difficult for them to describe the general (abstract) process they use

24. Mark Dixon Page 24 Concrete vs. Abstract code we have: –posLeft –posTop right = left + width middle = left + (width / 2) concrete code (works for window 800px wide): picBall.style.posLeft = 400 vs. abstract code (works for all window widths): picBall.style.posLeft = document.body.clientWidth / 2

25. Mark Dixon Page 25 Humans vs. Computers Humans and Computers work very differently Humans –declarative (goals): flexible sequence –intelligent: adaptive, questioning, rational –instinctive (without conscious thinking) –easily deal with incomplete and incorrect data –error prone (especially mundane repetitive tasks) Computers –procedural / algorithmic: fixed sequence –do exactly what they are told –cannot deal with errors –no imagination or creativity

26. Mark Dixon Page 26 Algorithms algorithm: step-by-step sequence of instructions, to solve a problem it describes how input data is to be processed in order to produce a desired output similar to recipe –ingredients (similar to data) –method (is a type of algorithm)

27. Mark Dixon Page 27 Algorithms Making a cup of tea: 1. Fill the kettle with water 2. Plug the kettle in 3. Switch the kettle on 4. Wait for the kettle to boil 5. Put water in cup 6. Put a tea bag into the cup 7. Add sugar to the cup 8. Add milk to the cup 9. Stir 10. Take the tea bag out

28. Mark Dixon Page 28 What vs. How what vs. how: –What: increase value of a text box by 1 –How: read the current value add 1 put the result back in the text box For example: swap, search, sort

29. Mark Dixon Page 29 Example: Swap v1 Swap Sub btnSwap_onClick() txtA.value = txtB.value txtB.value = txtA.value End Sub put txtB into txtA put txtA into txtB does not work!

30. Mark Dixon Page 30 Example: Swap v1 (why?)

31. Mark Dixon Page 31 Example: Swap v2 Swap Sub btnSwap_onClick() txtTemp.value = txtA.value txtA.value = txtB.value txtB.value = txtTemp.value End Sub put txtA into temp put txtB into txtA put temp into txtB works!

32. Mark Dixon Page 32 Example: Swap v2 (Why?)

33. Mark Dixon Page 33 The Empty String Two double quotes (no space between) "" Used to clear contents: txtNum.value = ""

34. Mark Dixon Page 34 Example: Student Loan (Analysis) What: Calculate annual student load repayment from salary How: Algorithm: –read annual salary –deduct £15000 –calculate 9% –display result

35. Mark Dixon Page 35 Example: Student Loan (Design) When Calculate button is clicked: –read annual salary text box –deduct £15000 –calculate 9% –put result in paragraph Test Data: InputProcess Output –£1500015000-15000*0.09 =£0 –£1600016000-15000*0.09 =£90

36. Mark Dixon Page 36 Generating Assignment Code put "Hello" into txtA txtA.value = "Hello" get txtA and join it with txtB, and put the result in parRes parRes.innerText = txtA.value + txtB.value put into txtNum2, the result of multiplying txtNum1 by 2 txtNum2.innerText = txtNum1.value * 2

37. Mark Dixon Page 37 Questions: Assignment What is the code for: –put 0 into the posLeft property of picHouse –increase the posTop property of picHouse by 5 –decrease the posTop property of picCar by 9 picHouse.style.posLeft = 0 picHouse.style.posTop = picHouse.style.posTop + 5 picCar.style.posTop = picCar.style.posTop - 9

38. Mark Dixon Page 38 Errors txtTemp.value = "" + 5 type mismatch (cannot add "" to 5) txtTemp.value = "7" + 5 OK – VB converts "7" into 7 automatically txtTemp.value = 7 + 5 OK – 7 plus 5 is 12 value.txtTemp = 7 + 5 object required 'value' (object comes first)

39. Mark Dixon Page 39 Example: Text Shift Text Shift Sub window_onLoad() parH.innerText = "Hello There" & Space(100) window.setInterval "TextShift()", 50 End Sub Sub TextShift() parH.innerText = Mid(parH.innerText,2) & Left(parH.innerText,1) End Sub

40. Mark Dixon Page 40 Tutorial Exercises: AddNum LEARNING OBJECTIVE: use a function to convert string (text) to integer (number) data Task 1: get the addnum examples (v1 and v2) working

41. Mark Dixon Page 41 Tutorial Exercises: Swap LEARNING OBJECTIVE: use an algorithm to solve a problem Task 1: get the swap examples (v1 and v2) working Task 2: change v2 of the swap page so that the temporary text box is hidden

42. Mark Dixon Page 42 Tutorial Exercises: Student Loan LEARNING OBJECTIVE: implement an algorithm in code Task 1: Create the user interface (page design) for the Student Loan example (from the lecture), using HTML tags (you will need a text box, a button, and a paragraph). Task 2: Add code that implements the following algorithm: When the Calculate button is clicked: –read annual salary text box –deduct £15000 –calculate 9% –put result in paragraph Task 3: Modify your program so that it calculates and displays monthly income and repayment amounts (as well an annual).

43. Mark Dixon Page 43 Tutorial Exercises: Text Shift LEARNING OBJECTIVE: develop and implement an algorithm to solve a problem use string manipulation functions, and sound Task 1: get the Text Shift example (from the lecture) working Task 2: modify your program so that the text goes the other way. Task 3: modify your program so that a noise is made when the user moves the mouse over the text.