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  Charge – coulombs (Q)  Charge of an e - & p + = 1.6 x 10 -19 coulombs  F e = KQ 1 Q 2 /r 2 (Coulombs Law)  Current (I) – amperes (amps) = I = Q/sec.

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Presentation on theme: "  Charge – coulombs (Q)  Charge of an e - & p + = 1.6 x 10 -19 coulombs  F e = KQ 1 Q 2 /r 2 (Coulombs Law)  Current (I) – amperes (amps) = I = Q/sec."— Presentation transcript:

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2   Charge – coulombs (Q)  Charge of an e - & p + = 1.6 x 10 -19 coulombs  F e = KQ 1 Q 2 /r 2 (Coulombs Law)  Current (I) – amperes (amps) = I = Q/sec.  Resistance (R) – resistance to the flow of e - s  Voltage – volts – V = IR  Power – watts - P = VI  Conductors & insulators  Capacitance – pulses of electricity Electricity terms

3   Charge – the cause of the F e  Magnetism caused by moving charge – demo.  Electric field/Magnetic field – demo. Electricity & magnetism

4   See p. 597 of your text Circuit diagrams & symbols


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