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Chapter 4 Introduction to Alkenes. Structure and Reactivity
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Alkenes Hydrocarbons containing one or more carbon-carbon double bonds
Sometimes called olefins Classified as unsaturated hydrocarbons Ethylene is the simplest alkene
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Physical Properties Very similar to corresponding alkanes: Flammable
Non-polar Insoluble in Water Low melting and boiling points Low density compared to water 5
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Bond Length Carbon-carbon multiple bonds are shorter than their carbon-carbon single bond counterparts 133.9 pm 153.6 pm
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Dipole moments and polarization
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Structure and Bonding in Alkenes
Carbons involved in the carbon-carbon double bond exhibit trigonal planar geometry
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Carbon Hybridization in Alkenes
sp2-hybridization Trigonal planar geometry
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sp2 = 33% s character, 66% p character
More s character → electrons are held closer to the nucleus
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Carbon Hybridization in Alkanes
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Carbon-carbon single bond in propene = 150 pm
Carbon-carbon single bond in propane = 154 pm Due to sp2 vs. sp3 hybridization Bonds with more s character are shorter
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Hybrid Orbital Picture of Ethylene
4.1 Structure and Bonding in Alkenes
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s bond: head-to-head overlap of orbitals
Cylindrically symmetric
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bond: side-to-side overlap of p orbitals
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p Orbital System in Ethylene
4.1 Structure and Bonding in Alkenes
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The filled molecular orbital is the bond
EPM of Ethylene The filled molecular orbital is the bond Most of the important reactions of alkenes involve the electrons of the bond 4.1 Structure and Bonding in Alkenes
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Rules for Naming Alkenes
Find the longest chain that includes the double bond and name this as the parent chain by changing the ending from “-ane” to “-ene” Hexane Hexene If there are two possibilities, choose the principle chain to be the one with the greatest number of double bonds Number the chain so that the double bond has the lowest number possible and place that number before the parent chain The double bond takes precidence over the substituents when numbering the chain Identify the substituents with number and name
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Problems Name the following:
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If there are more than one double bonds in the parent chain, identify each double bond’s position by number and indicate how many are present using Greek prefixes preceded by the letter “a.” Example: -adiene, -atriene, etc.
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Problems Name the following:
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Substituents Containing Alkenes
Some common groups with alkenes Nonsystematic traditional names 4.2 Nomenclature of Alkenes
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Problems Name the following compounds:
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Name the following compounds:
Problems Name the following compounds: CH3CH=CHCH3
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Stereoisomers: Molecules that have the same molecular formula, same atom connectivity, but a different spatial arrangement Cis-trans isomers: Recall: Constitutional/Structural Isomers: same molecular formula, different atom connectivity
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Restricted Rotation of Alkenes
4.1 Structure and Bonding in Alkenes
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Properties of 2-butene Cis-2-Butene Trans-2-Butene M.P. = -139°C
B.P. = 3.7°C Density = g/mL Trans-2-Butene M.P. = - 105°C B.P. = 1°C Density = g/mL
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Requirements for Cis-Trans Isomerism
Only when both carbons are bonded to two different groups are cis-trans isomers possible Compounds that have one of their carbons bonded to two identical groups can’t exist as cis-trans isomers
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Problems Which of the following compounds can exist as pairs of cis-trans isomers? Draw each cis-trans pair. CH3CH=CH2 CH3CH2CH=CHCH3 (CH3)2C=CHCH3 ClCH=CHCl There are two isomers for 3-methyl-2-pentene. Draw both of them. Which one is cis and which one is trans?
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E,Z Nomenclature System
cis vs trans is not always clear Cahn-Ingold-Prelog system: Assign priorities Z (zusammen): “together” On Zee Zame Zide E (entgegen): “across” E = Enemies = On Opposite Sides 4.2 Nomenclature of Alkenes
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Priority Assignment Rules
Examine each of the double bond carbons separately. Identify the two atoms directly attached to the C and rank them according to atomic #. Higher atomic # = higher priority Higher isotopic mass = higher priority
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If the first atoms connected to the double bond carbon are the same, continue moving outward until the first point of difference
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Multiple-bonded atoms are equivalent to the same number of single bonded atoms
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Problems Using the Cahn-Ingold-Prelog rules, identify whether the following molecules are E or Z:
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Problems Give the IUPAC names for each of the following molecules, including the E, Z designation.
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What’s the Structure of C6H10?
Saturated is C6H14 Therefore 4 H's are not present So, what does it look like? Double bond(s)? Triple bond(s)? Ring(s)? Ring and double bond?
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Degree of Unsaturation
Gives info on number of rings and/or p bonds Maximum # of H’s in a hydrocarbon: CnH2n+2 Each ring and/or p bond reduces number of hydrogens by 2 aka: unsaturation number
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For C6H10 the unsaturation # is 2
Two double bond Two rings One double bond and a ring One triple bond
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Halogens are counted as 1 H:
Calculating Degree of Unsaturation for Compounds Containing Elements Other than Carbon and Hydrogen Halogens are counted as 1 H: 4.3 Unsaturation Number
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Nitrogen increases H count by 1:
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Ignore Oxygens O’s form two bonds, don’t affect the formula of an equivalent hydrocarbon No change in number of H atoms if insert an O into a hydrocarbon compound
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Calculate the degree of unsaturation for the following molecules
Problems Calculate the degree of unsaturation for the following molecules C12H20 C4H6 C6H5N C6H5NO2 C8H9Cl3 Draw as many structures as you can for #2
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Alkene Stability Who’s more stable?
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Product Ratio Interconversion between cis and trans isomers can be made to happen using a strong acid catalyst More stable product is favored
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Heats of combustion ΔH°combustion = kJ/mol ΔH°combustion = kJ/mol The cis configuration is more strained = higher energy
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Heats of Hydrogenation
More stable alkene gives off less heat
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Effects of Branching on Alkene Stability
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Relative Stabilities of Alkene Isomers
From heats of hydrogenation (DH°hydrog): More alkyl substituents on double bond → more stable alkene In general, the number of alkyl groups is more important than the identity
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Hyperconjugation A stabilizing interaction between a vacant p orbital or anti-bonding π orbital on one atom with the electrons in a neighboring σ bond (usually C-H or C-C) In alkenes, occurs between the unfilled anti-bonding C=C π bond orbital and the electrons of a C-H σ bond of a neighboring substituent More substituents present = more opportunities for hyperconjugation = more stable alkene
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Bond Strength sp2-sp3 bond is stronger than sp3-sp3
More highly substituted alkenes have higher ratio of sp2-sp3 to sp3-sp3
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Addition Reactions of Alkenes
Characteristic reaction of alkenes The p bond of carbon-carbon double bond is: Broken Nucleophilic Three main types of alkene addition rxns: Rxn with hydrogen halides (ex: HCl) Catalytic hydrogenation Hydration
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Alkene Reactions with Hydrogen Halides
Called “Electrophilic Addition of Alkenes” HF, HCl, HBr, HI add to alkenes → alkyl halides HF is rarely used due to its extreme toxicity Lung and cornea damage Eventual cardiac arrest and death
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Electrophilic Addition Energy Path
Two step process First transition state is high energy point
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Problems Draw the mechanism for the following reactions
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Writing Organic Reactions
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Markovnikov’s Rule In the addition of HX to an alkene:
the H attaches to the carbon with fewer alkyl substituents the carbocation forms on the more substituted carbon of the C=C the X attaches to the more substituted carbon When one of the possible isomer products predominates, the reaction is said to be regiospecific or regioselective
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Problems Complete the following reaction showing the complete mechanism What alkene would you start with to prepare the following alkyl halide?
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Regioselectivity of Addition
Unsymmetrical alkenes can give regioisomers If both carbons of the C=C have similar substitution, then reaction is not regiospecific
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Carbocation Structure and Stability
The more highly substituted carbocation is more stable Formation of more substituted carbocation intermediate is favored
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Why? Inductive Effect Electrons from groups neighboring the carbocation can shift toward the positive charge Larger groups can “donate” electrons more easily than H can
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Hyperconjugation Carbocations are planar and the tricoordinate carbon is surrounded by only 6 electrons in sp2 orbitals The fourth orbital on carbon is a vacant p-orbital Alkyl groups can share electrons with the empty neighboring p orbital
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Problems Predict the products of the following reactions:
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Problems Which alkenes would you start with to prepare the following alkyl halides?
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Carbocation Rearrangements
Sometimes, we get an unexpected product In a Carbocation Rearrangement, a group (alkyl, aryl, or hydride) moves to a different position so that a more stable carbocation can form
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Alkyl Shift
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Hydride Shift
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Hydride shifts in biological molecules
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Problem On treatment with HBr, vinylcyclohexane undergoes addition and rearrangement to yield the following product. Propose a mechanism to account for this result
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Catalysis Catalyst: A substance that increases the reaction rate without being consumed Lowers the Ea Heterogeneous Homogeneous 4.9 Catalysis
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Catalytic Hydrogenation of Alkenes
Catalyst: Pt or Pd as In powdered form on carbon Heterogeneous catalyst
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Aromatic bonds are less reactive
Example: Aromatic bonds are less reactive 4.9 Catalysis
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Problems What product would you obtain from the catalytic hydrogenation of (CH3)2C=CHCH2CH3? What product would you obtain from the reaction of 3,3-Dimethylcyclopentene with Palladium on Carbon in the presence of H2?
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Hydration of Alkenes Alkene Acid-catalyzed addition of H2O across an double bond Homogeneous catalyst
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Problems Draw out the mechanism and products for the following reactions:
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Problems What alkenes might the following alcohols have been prepared from?
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Nature produces catalysts called enzymes
Enzymes Catalysis Nature produces catalysts called enzymes Most biological mechanisms would be too slow to be useful without enzymes 4.9 Catalysis
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Principle of Microscopic Reversibility
Generally, the reverse reaction follows the exact reverse of forward mechanism Dehydration is the reverse of hydration 4.9 Catalysis
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Commonly, two or more reactions are in competition
Reaction Rates Commonly, two or more reactions are in competition 4.8 Reaction Rates
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Forward and reverse reaction have same transition state (‡)
The Transition State Forward and reverse reaction have same transition state (‡) 4.8 Reaction Rates
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Molecules must possess enough energy to get over the transition state
The Energy Barrier Molecules must possess enough energy to get over the transition state Maxwell-Boltzmann distribution 4.8 Reaction Rates
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Intermediates are formed in many reactions
Multistep Reactions Intermediates are formed in many reactions Rate-determining step: Controls reaction rate 4.8 Reaction Rates
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Hammond’s Postulate The structure and energy of the transition state can be approximated by the structure and energy of the intermediate 4.8 Reaction Rates
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