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Unit 14: ElectrochemLPChem: Wz
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Unit 14: Electrochemistry
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LPChem: Wz Unit 14: Electrochemistry + 2 e - oxidation 2 e - + reduction The electrons produced here… …Are used up here.
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LPChem: Wz Unit 14: Electrochemistry + 2 e - Loss of Electrons is Oxidation 2 e - + Gain of Electrons is Reduction
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LPChem: Wz Unit 14: Electrochemistry + 2 e - Oxidation Is Loss (of electrons) 2 e - + Reduction Is Gain (of electrons)
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LPChem: Wz Unit 14: Electrochemistry + 2 e - 2 e - + oxidation (half- reaction) reduction (half- reaction) 2 Na 0 + + 2 e - + Cl 2 0 2 NaCl + 2 e -
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LPChem: Wz Unit 14: Electrochemistry 2 Na 0 + Cl 2 0 2 NaCl Redox Reaction +1 0 0 oxidation reduction Elements in their “elemental state” have a oxidation # of zero. Elements in compounds have oxidation #s based on periodic table location.
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LPChem: Wz Unit 14: Electrochemistry 2 Na 0 + Cl 2 0 2 NaCl Redox Reaction +1 0 0 oxidation reduction +1 Ions have an oxidation number equal to their charge. +1 = +1 -1 = -1
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Unit 14: Electrochemistry LPChem: Wz 0 0 -2 +2 -2 +2 Zn (0 +2) Cu (+2 0) Zn (0 +2)
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Unit 14: Electrochemistry LPChem: Wz
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Unit 14: Electrochemistry LPChem: Wz
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu e-
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu KCl Cl - K+K+
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu KCl Cl - K+K+ Anode Bridge Cathode At the Anode is Oxidation At the Cathode is Reduction
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu KCl Cl - K+K+ Anode Bridge Cathode At the Anode is Oxidation At the Cathode is Reduction The cathode (-) attracts cations. The anode (+) attracts anions.
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu KCl Cl - K+K+ Separating half-reactions makes galvanic reactions into batteries. Now let’s calculate its voltage!
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu
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Unit 14: Electrochemistry LPChem: Wz Voltage (AKA Electrochem. Potential) is found on a chart like this. The chart is all REDUCTION half-reactions.
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Unit 14: Electrochemistry LPChem: Wz The REDUCTION half-reactions from our battery was: Cu 2+ + 2e - Cu
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Unit 14: Electrochemistry LPChem: Wz The chart is in order of potential/ voltage. E o (V) Elements at the top are most desperate to reduce (gain electrons). Reactions with the most positive voltages are the most spontaneous reductions. Reactions with the least positive (most negative) voltages are least spontaneous reductions. Hydrogen is zero.
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Unit 14: Electrochemistry LPChem: Wz If charts are always of reduction potential, how do we find the voltage for our oxidation half-reaction? If oxidation is the opposite of reduction, then the opposite of the original chart should do the trick!
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Unit 14: Electrochemistry LPChem: Wz The OXIDATION half-reactions from our battery was: Zn Zn 2+ + 2e - Its opposite would be: Zn 2+ + 2e - Zn
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Unit 14: Electrochemistry LPChem: Wz The reduction potential of: Zn 2+ + 2e - Zn = - 0.76 V Its opposite Zn Zn 2+ + 2e - would be worth the opposite voltage: = 0.76 V
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Unit 14: Electrochemistry LPChem: Wz Zn Zn 2+ + 2e - 2e - + Cu 2+ Cu0.34 V 0.76 V + 1.10 V
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Unit 14: Electrochemistry LPChem: Wz The further apart the two half reactions are on the chart, the greater the voltage of the overall reaction. Voltage is a potential– like gravitational potential energy. Larger separation between the half-reactions means the electrons have further to “fall.” More potential!
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Unit 14: Electrochemistry LPChem: Wz The anode (oxidation) half reaction will always need to be “flipped” because the chart is for reductions. That means changing the sign on its voltage.
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Unit 14: Electrochemistry LPChem: Wz If the anode (oxidation) half-reaction were above the cathode half-reaction on the chart, what would happen?? Things don’t fall “up.” No reaction would take place. Unless… …external current were applied. (Electrolysis.)
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