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CONFIDENTIAL 1 Grade 8 Pre-Algebra Factoring x 2 + bx + c.

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Presentation on theme: "CONFIDENTIAL 1 Grade 8 Pre-Algebra Factoring x 2 + bx + c."— Presentation transcript:

1 CONFIDENTIAL 1 Grade 8 Pre-Algebra Factoring x 2 + bx + c

2 CONFIDENTIAL 2 1) x 3 + 2x 2 + 5x + 10 2) 2x 3 - 8x 2 - 3x + 12 3) 2x 3 - 4x 2 + 7x - 14 4) x 3 - 4x 2 + x - 4 Warm Up Factor each polynomial by grouping:

3 CONFIDENTIAL 3 Introduction (x + 2)(x + 5) = x 2 + 7x + 10 When we multiply (x + 2)(x + 5), the constant term of the trinomial is the product of the constants in the binomials. You can use this fact to factor a trinomial into its binomial factors. Look for two terms that are the factors of the constant term in the trinomial. Write two binomials with those numbers and then multiply to see if you are correct.

4 CONFIDENTIAL 4 Factor x 2 + 19x + 60 by guess and check: Factoring trinomials by guess and check Write two sets of parentheses.( + )( + ) (x + )(x + ) The first term is x 2, so the variable terms have a coefficient of 1. The constant term in the trinomial is 60. (x + 1)(x + 60) = x 2 + 61x + 60 Try factors of 60 for the constant term in the binomials.

5 CONFIDENTIAL 5 (x + 4)(x + 15) = x 2 + 19x + 60 (x + 2)(x + 30) = x 2 + 32x + 60 (x + 3)(x + 20) = x 2 + 23x + 60 The factors x 2 + 19x + 60 are (x + 4)(x + 15). x 2 + 19x + 60 = (x + 4)(x + 15)

6 CONFIDENTIAL 6 Factor each trinomial by guess and check: Now you try! 1) x 2 + 10x + 24 2) x 2 + 7x + 12

7 CONFIDENTIAL 7 The guess and check method is usually not the most efficient method of factoring a trinomial. Look at the product of (x + 3)(x + 4). The coefficient of the middle term is the sum of 3 and 4. The third term is the product of 3 and 4. (x + 3)(x + 4) = x 2 + 7x + 12 x2x2 12 3x 4x

8 CONFIDENTIAL 8 x 2 + bx + c Factoring x 2 + bx + c when c is positive Factor the trinomial. Check your answer. (x + )(x + ) x 2 + 6x + 8 b = 6 and c = 8; look for factors of 8 whose sum is 6. Factors of 8 sum 1 and 8 2 and 4 9696 (x + 2)(x + 4). The factors needed are 2 and 4. Check: (x + 2)(x + 4) = x 2 + 4x + 2x + 8 = x 2 + 6x + 8 When c is positive, its factors have the same sign. The sign of b tells you whether the factors are positive or negative. When b is positive, the factors are positive, and when b is negative the factors are negative.

9 CONFIDENTIAL 9 Now you try! 1) x 2 + 5x + 6 2) x 2 - 10x + 16 Factor the trinomial. Check your answer.

10 CONFIDENTIAL 10 x 2 + bx + c Factoring x 2 + bx + c when c is negative Factor the trinomial. Check your answer. (x + )(x + ) x 2 + 7x - 18 b = 7 and c = -18; look for factors of -18 whose sum is 6. The factor with the greater absolute value is positive. The factors needed are -2 and 9. Check: (x - 2)(x + 9) = x 2 + 9x - 2x - 18 = x 2 + 7x - 18 Factors of 18 sum -1 and 18 -2 and 9 -3 and 6 963963 (x - 2)(x + 9).

11 CONFIDENTIAL 11 Now you try! 1) x 2 - 5x - 24 2) x 2 + 2x - 15 Factor the trinomial. Check your answer.

12 CONFIDENTIAL 12 A polynomial and the factored form of polynomial are equivalent expressions. When you evaluate these two expressions for the same value of variable, the results are the same. Evaluating polynomials. Factor x 2 + 11x + 24. Show that the original polynomial and the factored form have the same value for 0, 1, 2, 3, and 4. x 2 + 11x + 24 (x + )(x + ) b = 11 and c = 24; look for factors of 24 whose sum is 11. Factors of 8 sum 1 and 24 2 and 12 3 and 8 4 and 6 25 14 11 10 The factors needed are 3 and 8. Next page

13 CONFIDENTIAL 13 (x + 3)(x + 8). Evaluate the original polynomial and the factored form for 0, 1, 2, 3, and 4. xx 2 + 11x + 24 00 2 + 11(0) + 24 = 24 11 2 + 11(1) + 24 = 36 22 2 + 11(2) + 24 = 50 33 2 + 11(3) + 24 = 66 44 2 + 11(4) + 24 = 84 x(x + 3)(x + 8) 0(0 + 3)(0 + 8) = 24 1(1 + 3)(1 + 8) = 36 2(2 + 3)(2 + 8) = 50 3(3 + 3)(3 + 8) = 66 4(4 + 3)(4 + 8) = 84 The original polynomial and the factored form have the same value for the given values of x.

14 CONFIDENTIAL 14 Now you try! Factor x 2 - 7x + 10. Show that the original polynomial and the factored form have the same value for 0, 1, 2, 3, and 4.

15 CONFIDENTIAL 15 The area of a rectangle in square feet can be represented by x 2 + 8x + 12. The length is (x + 6) ft. What is the width of the rectangle? x 2 + 8x + 12 (x + )(x + ) b = 8 and c = 12; look for factors of 12 whose sum is 8. Factors of 8 sum 1 and 12 2 and 6 13 8 The factors needed are 2 and 6. (x + 2)(x + 6). Area of rectangle = lw =(x + 6)(x + 2) Hence, width of the rectangle = Area = (x + 6)(x + 2) length (x + 6) Width of the rectangle = (x + 2)

16 CONFIDENTIAL 16 Now you try! The rectangle has area x 2 + 6x + 8. The length is (x + 4) ft. What is the width of the rectangle? Could the rectangle be a square? Explain why or why not.

17 CONFIDENTIAL 17 BREAK

18 CONFIDENTIAL 18

19 CONFIDENTIAL 19 Assessment 1) x 2 + 8x + 12 Factor the trinomial. Check your answer. 2) x 2 - 5x + 6 3) x 2 + 2x - 15 4) x 2 - 6x + 8

20 CONFIDENTIAL 20 5) Factor x 2 + 9x + 14. Show that the original polynomial and the factored form have the same value for 0, 1, 2, 3, and 4. 6) x 2 + 4x +3 7) x 2 + 13x + 36 8) x 2 - 4x - 45 9) x 2 + x - 12

21 CONFIDENTIAL 21 10) The rectangle has area x 2 - 12x + 32. The length is (x - 4) ft. What is the width of the rectangle?

22 CONFIDENTIAL 22 Let’s review (x + 2)(x + 5) = x 2 + 7x + 10 When we multiply (x + 2)(x + 5), the constant term of the trinomial is the product of the constants in the binomials. You can use this fact to factor a trinomial into its binomial factors. Look for two terms that are the factors of the constant term in the trinomial. Write two binomials with those numbers and the multiply to see if you are correct.

23 CONFIDENTIAL 23 Factor x 2 + 19x + 60 by guess and check: Factoring trinomials by guess and check Write two sets of parentheses.( + )( + ) (x + )(x + ) The first term is x 2, so the variable terms have a coefficient of 1. The constant term in the trinomial is 60. (x + 1)(x + 60) = x 2 + 61x + 60 Try factors of 60 for the constant term in the binomials.

24 CONFIDENTIAL 24 (x + 4)(x + 15) = x 2 + 19x + 60 (x + 2)(x + 30) = x 2 + 32x + 60 (x + 3)(x + 20) = x 2 + 23x + 60 The factors x 2 + 19x + 60 are (x + 4)(x + 15). x 2 + 19x + 60 = (x + 4)(x + 15)

25 CONFIDENTIAL 25 The guess and check method is usually not the most efficient method of factoring a trinomial. Look at the product of (x + 3)(x + 4). The coefficient of the middle term is the sum of 3 and 4. The third term is the product of 3 and 4. (x + 3)(x + 4) = x 2 + 7x + 12 x2x2 12 3x 4x When c is positive, its factors have the same sign. The sign of b tells you whether the factors are positive or negative. When b is positive, the factors are positive, and when b is negative the factors are negative.

26 CONFIDENTIAL 26 x 2 + bx + c Factoring x 2 + bx + c when c is positive Factor the trinomial. Check your answer. (x + )(x + ) x 2 + 6x + 8 b = 6 and c = 8; look for factors of 8 whose sum is 6. Factors of 8 sum 1 and 8 2 and 4 9696 (x + 2)(x + 4). The factors needed are 2 and 4. Check: (x + 2)(x + 4) = x 2 + 4x + 2x + 8 = x 2 + 6x + 8

27 CONFIDENTIAL 27 x 2 + bx + c Factoring x 2 + bx + c when c is negative Factor the trinomial. Check your answer. (x + )(x + ) x 2 + 7x - 18 b = 7and c = -18; look for factors of -18 whose sum is 6. The factor with the greater absolute value is positive. The factors needed are -2 and 9. Check: (x - 2)(x + 9) = x 2 + 9x - 2x - 18 = x 2 + 7x - 18 Factors of 18 sum -1 and 18 -2 and 9 -3 and 6 963963 (x - 2)(x + 9).

28 CONFIDENTIAL 28 A polynomial and the factored form of polynomial are equivalent expressions. When you evaluate these two expressions for the same value of variable, the results are the same. Evaluating polynomials. Factor x 2 + 11x + 24. Show that the original polynomial and the factored form have the same value for 0, 1, 2, 3, and 4. x 2 + 11x + 24 (x + )(x + ) b = 11and c = 24; look for factors of 24 whose sum is 11. Factors of 8 sum 1 and 24 2 and 12 3 and 8 4 and 6 25 14 11 10 The factors needed are 3 and 8. Next page

29 CONFIDENTIAL 29 (x + 3)(x + 8). Evaluate the original polynomial and the factored form for 0, 1, 2, 3, and 4. xx 2 + 11x + 24 00 2 + 11(0) + 24 = 24 11 2 + 11(1) + 24 = 36 22 2 + 11(2) + 24 = 50 33 2 + 11(3) + 24 = 66 44 2 + 11(4) + 24 = 84 x(x + 3)(x + 8) 0(0 + 3)(0 + 8) = 24 1(1 + 3)(1 + 8) = 36 2(2 + 3)(2 + 8) = 50 3(3 + 3)(3 + 8) = 66 4(4 + 3)(4 + 8) = 84 The original polynomial and the factored form have the same value for the given values of x.

30 CONFIDENTIAL 30 The area of a rectangle in square feet can be represented by x 2 + 8x + 12. The length is (x + 6) ft. What is the width of the rectangle? x 2 + 8x + 12 (x + )(x + ) b = 8 and c = 12; look for factors of 12 whose sum is 8. Factors of 8 sum 1 and 12 2 and 6 13 8 The factors needed are 2 and 6. (x + 2)(x + 6). Area of rectangle = lw =(x + 6)(x + 2) Hence, width of the rectangle = Area = (x + 6)(x + 2) length (x + 6) Width of the rectangle = (x + 2)

31 CONFIDENTIAL 31 You did a great job today!


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