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Thermodynamic Properties Property Table w Property Table -- from direct measurement w Equation of State w Equation of State -- any equations that relates P,v, and T of a substance
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Ideal -Gas Equation of State w Any relation among the pressure, temperature, and specific volume of a substance is called an equation of state. The simplest and best-known equation of state is the ideal-gas equation of state, given as where R is the gas constant. Caution should be exercised in using this relation since an ideal gas is a fictitious substance. Real gases exhibit ideal-gas behavior at relatively low pressures and high temperatures.
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Universal Gas Constant Universal gas constant is given on R u = 8.31434 kJ/kmol-K = 8.31434 kPa-m 3 /kmol-k = 0.0831434 bar-m 3 /kmol-K = 82.05 L-atm/kmol-K = 1.9858 Btu/lbmol-R = 1545.35 ft-lbf/lbmol-R = 10.73 psia-ft 3 /lbmol-R
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Example Determine the particular gas constant for air and hydrogen.
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Ideal Gas “Law” is a simple Equation of State
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Percent error for applying ideal gas equation of state to steam
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Question …... Under what conditions is it appropriate to apply the ideal gas equation of state?
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Ideal Gas Law w Good approximation for P-v-T behaviors of real gases at low densities (low pressure and high temperature). w Air, nitrogen, oxygen, hydrogen, helium, argon, neon, carbon dioxide, …. ( < 1% error).
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Compressibility Factor w The deviation from ideal-gas behavior can be properly accounted for by using the compressibility factor Z, defined as Z represents the volume ratio or compressibility.
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Ideal Gas Z=1 Real Gases Z > 1 or Z < 1
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Real Gases w Pv = ZRT or w Pv = ZR u T, where v is volume per unit mole. w Z is known as the compressibility factor. w Real gases, Z 1.
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Compressibility factor w What is it really doing? w It accounts mainly for two things Molecular structureMolecular structure Intermolecular attractive forcesIntermolecular attractive forces
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Principle of corresponding states w The compressibility factor Z is approximately the same for all gases at the same reduced temperature and reduced pressure. Z = Z(P R,T R ) for all gases
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Reduced Pressure and Temperature where: P R and T R are reduced values. P cr and T cr are critical properties.
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Compressibility factor for ten substances (applicable for all gases Table A-3)
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Where do you find critical-point properties? Table A-7 Mol (kg-Mol) R (J/kg.K) Tcrit (K) Pcrit (MPa) Ar28,97287,0(---) O2O2 32,00259,8154,85,08 H2H2 2,0164124,233,31,30 H2OH2O18,016461,5647,122,09 CO 2 44,01188,9304,27,39
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Reduced Properties w This works great if you are given a gas, a P and a T and asked to find the v. w However, if you are given P and v and asked to find T (or T and v and asked to find P), trouble lies ahead. w Use pseudo-reduced specific volume.
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Pseudo-Reduced Specific Volume w When either P or T is unknown, Z can be determined from the compressibility chart with the help of the pseudo- reduced specific volume, defined as not v cr !
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Ideal-Gas Approximation w The compressibility chart shows the conditions for which Z = 1 and the gas behaves as an ideal gas: w (a) P R 1
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Other Thermodynamic Properties: Isobaric (c. pressure) Coefficient v T P
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Other Thermodynamic Properties: Isothermal (c. temp) Coefficient v P T
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Other Thermodynamic Properties: We can think of the volume as being a function of pressure and temperature, v = v(P,T). Hence infinitesimal differences in volume are expressed as infinitesimal differences in P and T, using and coefficients If and are constant, we can integrate for v:
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Other Thermodynamic Properties: Internal Energy, Enthalpy and Entropy
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Other Thermodynamic Properties: Specific Heat at Const. Volume u T v
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Other Thermodynamic Properties: Specific Heat at Const. Pressure h T P
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Other Thermodynamic Properties: Ratio of Specific Heat
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Other Thermodynamic Properties: Temperature s u v T 1
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Ideal Gases: u = u(T) Therefore, 0
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We can start with du and integrate to get the change in u: Note that C v does change with temperature and cannot be automatically pulled from the integral.
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Let’s look at enthalpy for an ideal gas: w h = u + Pv where Pv can be replaced by RT because Pv = RT. w Therefore, h = u + RT => since u is only a function of T, R is a constant, then h is also only a function of T w so h = h(T)
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Similarly, for a change in enthalpy for ideal gases:
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Summary: Ideal Gases w For ideal gases u, h, C v, and C p are functions of temperature alone. w For ideal gases, C v and C p are written in terms of ordinary differentials as
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For an ideal gas, w h = u + Pv = u + RT C p = C v + R
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Ratio of specific heats is given the symbol,
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Other relations with the ratio of specific heats which can be easily developed:
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For monatomic gases, Argon, Helium, and Neon
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For all other gases, w C p is a function of temperature and it may be calculated from equations such as those in Table A-5(c) in the Appendice w C v may be calculated from C p =C v +R. w Next figure shows the temperature behavior …. specific heats go up with temperature.
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Specific Heats for Some Gases w C p = C p (T) a function of temperature
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Three Ways to Calculate Δu and Δh w Δu = u 2 - u 1 (table) w Δu = w Δu = C v,av ΔT w Δh = h 2 - h 1 (table) w Δh = w Δh = C p,av ΔT
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Isothermal Process w Ideal gas: PV = mRT
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For ideal gas, PV = mRT We substitute into the integral Collecting terms and integrating yields:
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Polytropic Process w PV n = C
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Ideal Gas Adiabatic Process and Reversible Work w What is the path for process with expand or contract without heat flux? How P,v and T behavior when Q = 0? w To develop an expression to the adiabatic process is necessary employ: 1. Reversible work mode: dW = PdV 2. Adiabatic hypothesis: dQ =0 3. Ideal Gas Law: Pv=RT 4. Specific Heat Relationships 5. First Law Thermodynamics: dQ-dW=dU
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Ideal Gas Adiabatic Process and Reversible Work (cont) First Law: Using P = MRT/V Integrating from (1) to (2)
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Ideal Gas Adiabatic Process and Reversible Work (cont) Using the gas law : Pv=RT, other relationship amid T, V and P are developed accordingly:
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Ideal Gas Adiabatic Process and Reversible Work (cont) An expression for work is developed using PV = constant. i and f represent the initial and final states
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Ideal Gas Adiabatic Process and Reversible Work (cont) The path representation are lines where Pv = constant. For most of the gases, 1.4 w The adiabatic lines are always at the righ of the isothermal lines. w The former is Pv = constant (the exponent is unity) P v Q = 0 T=const. i f f
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Polytropic Process A frequently encountered process for gases is the polytropic process: PV n = c = constant Since this expression relates P & V, we can calculate the work for this path.
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Polytropic Process w Constant pressure 0 w Constant volume w Isothermal & ideal gas 1 w Adiabatic & ideal gas k=C p /C v Process Exponent n
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Boundary work for a gas which obeys the polytropic equation
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We can simplify it further The constant c = P 1 V 1 n = P 2 V 2 n
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Polytropic Process
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