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MATH 31 LESSONS Chapter 2: Derivatives 4. The Chain Rule
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Section 2.6: The Chain Rule Read Textbook pp. 96 - 102
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A. Composite Functions (Review) A composite function is defined as where g (x) is the “inside function” f is the “outside function”
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Ex. 1If f (x) = x 2 - 3x + 7 and g(x) = 4 - x 2, then find: Try this example on your own first. Then, check out the solution.
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f (x) = x 2 - 3x + 7 g(x) = 4 - x 2 g (x) is the inside function. Replace it with g (x) = 4 - x 2
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f (x) = x 2 - 3x + 7 g(x) = 4 - x 2 Wherever you see x in the f function, replace it with 4 - x 2
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f (x) = x 2 - 3x + 7 g(x) = 4 - x 2
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B. The Chain Rule For the composite function
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First, take the derivative of the outside function (and leave the inside function the same)...
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... then, take the derivative of the inside function
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The chain rule can also be expressed in Leibnitz notation:
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This is easy to remember, because if we treat these as true fractions, the du’s would cancel and you would be left with dy / dx. But of course, you would never do this.
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The Chain Rule Applied to Power Functions The most common application of the chain rule in this unit is when the outside function is a power. e.g. y = [ f (x) ] n
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First, take the derivative of the outside power function (and leave the inside function the same)...... then, take the derivative of the inside function
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or
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Ex. 2Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.
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Method 1: Leibnitz Let u = x 2 - 3x Assign u as the “inside function”
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Let u = x 2 - 3x Then, y = u 4 When you replace the inside function with u, you are left with just the outside function
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u = x 2 - 3x y = u 4 This is the Leibnitz formula for the chain rule. Remember, to ensure it is in the proper form, you can “cancel” the du’s and you are left with dy / dx
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u = x 2 - 3x y = u 4 Substitute y = u 4 and u = x 2 - 3x
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u = x 2 - 3x y = u 4
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u = x 2 - 3x y = u 4 Back substitute so that the answer is in terms of x
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Method 2: “Outside, Inside” The “inside function” is x 2 - 3x
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The “outside function” is the 4 th power
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First, do the derivative of the outside function. Be certain to keep the inside function the same
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Next, don’t forget to do the derivative of the inside function
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Since this method is much faster, we will use this method exclusively from now on.
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Ex. 3Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.
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Bring all the x’s to the top.
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First, do the derivative of the outside function. Be certain to keep the inside function the same
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Next, don’t forget to do the derivative of the inside function
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Ex. 4Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.
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Express in power notation.
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First, do the derivative of the outside function. Be certain to keep the inside function the same
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Next, don’t forget to do the derivative of the inside function
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Ex. 5Differentiate using the chain rule. No need to simplify. Try this example on your own first. Then, check out the solution.
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First, do the derivative of the outside function. Be certain to keep the inside function the same
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Next, don’t forget to do the derivative of the inside function
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Apply the derivative to each part of the inside function. You will be required to do the chain rule again.
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Derivative of “outside function” (leave inside same) Don’t forget the derivative of the “inside function”
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Ex. 6Find Try this example on your own first. Then, check out the solution.
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You read this as: “Find the derivative of y, and then evaluate it at x = 3”
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First, find the derivative using the chain rule:
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chain rule
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Next, evaluate the derivative at x = 3:
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Ex. 7If g (3) = 6, g (3) = 5, f (5) = 2, and f (6) = 8, then evaluate: Try this example on your own first. Then, check out the solution.
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Expand the function first in terms of x : First, do the derivative of the outside function. Be certain to keep the inside function the same
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Next, don’t forget to do the derivative of the inside function
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Now, evaluate the function: g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8
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g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8
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g (3) = 6 g (3) = 5 f (5) = 2 f (6) = 8
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Ex. 8Differentiate, using more than one rule. Fully factor your answer. Try this example on your own first. Then, check out the solution.
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Which rule do you use first?
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Take the derivative of the first and leave the second + Leave the first and take the derivative of the second (u v) = u v + u v Use the product rule first
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Next, use the chain rule
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Put in the same order.
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Let A = x 2 + 6 Use substitution to make the factoring easier.
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But A = x 2 + 6 After factoring, back substitute so that it is in terms of only x. Be certain to use brackets.
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But A = x 2 + 6 Simplify inside the bracket.
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But A = x 2 + 6
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Ex. 9Differentiate, using more than one rule. Fully simplify your answer. Try this example on your own first. Then, check out the solution.
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Which rule do you use first?
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Chain rule first First, do the derivative of the outside function. Be certain to keep the inside function the same
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Don’t forget to do the derivative of the “inside function”.
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Use the quotient rule Quotient Rule:
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This is another possible answer.
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