1. Equipment Design

2. Content: 2 Heat Exchanger ( 1 & 2 ) Cooler (E-100) Compressor (K-102) Trans-alkylation reaction

3. Shell and tube heat exchanger Objective : to cooled the stream out from reactor by exchange heat with benzene comes from benzene column.

4. Assumptions: Use shell and tube heat exchanger, one shell and two tube passes. The value of the overall heat transfer coefficient was assumed to be 535 w/m2.s. Assume the outer, the inner diameter and the length of the tube.

5. Main design procedure: 1-Heat load,(kW) Q = (m Cp Δ T) hot =(m Cp Δ T) cold 2- Tube side flow, (kg/hr)

6. 3-Log mean Temperature, (˚C) 4-Provisional Area, (m 2 )

7. Number of tube: Bundle and Shell Diameter

8. Tube side Heat Transfer Coefficient Shell side heat Transfer Coefficient

9. Overall Coefficient Tube Side pressure drop Shell side Pressure Drop

10. Thickness

11. Equipment Name Shell & tube heat exchanger Objective to cooled the stream out from reactor by exchange heat with benzene comes from benzene column Equipment NumberE-105 Material of Construction Carbon steel InsulationGlass wool Cost ($)111672

12. Operating Condition Shell Side Inlet temperature (oC)193Outlet temperature (oC)265 Tube Side Inlet temperature (oC)444Outlet temperature (oC) 361 Number of Tubes838.754Shell Diameter (m)1.264 Tube bundle Diameter (m)1.189LMTD (oC)173.44 Q total (kw)3.51e4Heat Exchanger Area (m2) 385.76 U (W/m2. oC)537.6

13. Assumptions: For second heat exchanger: Use shell and tube heat exchanger, one shell and two tube passes. The value of the overall heat transfer coefficient was assumed to be 800 w/m2.s. Assume the outer, the inner diameter and the length of the tube.

14. Results Equipment Name Shell & tube heat exchanger Objective to cooled the stream out from reactor by exchange heat with benzene comes from benzene column Equipment NumberE-107 Material of Construction Carbon steel InsulationGlass wool Cost ($)58752

15. Operating Condition Shell Side Inlet temperature (oC)193Outlet temperature (oC)260 Tube Side Inlet temperature (oC)361Outlet temperature (oC)271 Number of Tubes284.36Shell Diameter (m).788 Tube bundle Diameter (m).728LMTD (oC)89.005 Q total (kw)6.29e3Heat Exchanger Area (m2) 98.090 U (W/m2. oC)801.54

16. Assumptions: For cooler: Use shell and tube heat exchanger, one shell and two tube passes. The value of the overall heat transfer coefficient was assumed to be 221 w/m2.s. Assume the outer, the inner diameter and the length of the tube.

17. Results Equipment Name Shell & tube heat exchanger Objective to cooled the stream out from first bed reactor by using cold water Equipment NumberE-100 Material of Construction Carbon steel InsulationGlass wool Cost ($)69000

18. Operating Condition Shell Side Inlet temperature (oC)701.88Outlet temperature (oC)200 Tube Side Inlet temperature (oC)25Outlet temperature (oC)80 Number of Tubes211.48Shell Diameter (m).788 Tube bundle Diameter (m)1.135LMTD (oC)352.4 Q total (kw)15310Heat Exchanger Area (m2) 202.64 U (W/m2. oC)222.96

19. Compressor (K-102) Objective: Compressor is a device in which a gas is compressed to increase its pressure. Compressor (K-102) is employed to increase the pressure from Pin=(179.3psia) to (Pout=530.4psia)

20. Design procedure: 1.Calculate n from P1/P2 = ( T1/T2)^(n/n-1) 2. Calculate work done Btu/lb-mole W = (n*R*(T1-T2))/(1-n) R=Cp/Cv 3. Calculate horse power, ftlbf/lbm Hp=( (Z1*R*T1)/Mw)*(n/n-1)*(Rc^(n-1/n) – 1) P1 T1 P2 T2

21. where Rc = P2/P1 4. Calculate the efficiency from (n/n-1) = (K/K-1)*Ep, Where K = (Mw*Cp)/(Mw*Cp – 1.986) Ep=efficiency of the compressor Cp=heat capacity, Btu/lb o F

22. Results: K-102 837.6Inlet Temp.( o R) 968.1Outlet Temp.( o R) 179.3Inlet Pressure(Psia) 530.4Outlet Pressure(Psia) 44.85%Efficiency% 332.848Power(HP) Cost ($)= 251600 Type of compressor: reciprocating

23. Trans-alkylation reaction Objective : The aim from trans-alkylation reaction is to convert PEB to EB. PEB EB

24. Main design procedure: 1) Design Equation: 2) Rate Law: -r A = K C A Arrhenius equation

25. 3) Stoichiometry 4) Energy Balance 5) Dimensions of the Reactor Assuming L/D = 4

26. 6) Height of reactor= L+D+(2*space) 7) Weight of cat. = vol. of reactor (1- ϵ )* ρ cat 8) Area of reactor= 2*(3.14)* r *H 9) t = (P r i / (S E-0.6P) ) + Cc Where: t: shell thickness(in) P: internal pressure r i (Rs): internal radius of shell (in) E: efficiency of joint S: working stress stain Steel Cc: allowance for corrosion

27. Results: K = 37.6675 s-1 From Polymath the volume of reactor V = 13.3 m3 Dimensions of the Reactor D = 1.61764 m L = 6.470559 m

28. Material of Construction: 316 carbon steel Cost : 154800 $ H(reactor)=21.23 ft W= 232.0318 kgcat A = 353.309 ft^2 t= 1.38e-1 m

29. Thank you