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Electrochemical Cells (Galvanic, Voltaic, Electric)
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the “half cell” reactions are occurring separately and are joined by a wire the e - transfer occurs through this external circuit the PE difference (voltage) is manifested as usable energy
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CathodeAnode mass of electrode Solution electrical charge Ions from salt bridge As the cell proceeds: increases decreases -ve as Y + Y+ve as X X + +ve “cations” -ve “anions”
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Cell Shorthand Notation eg. For the Zn/Cu cell: Zn│ Zn 2+ ║ Cu 2+ │Cu Conventions: the │ notation indicates a phase boundary where the electrode and electrolyte are in physical contact. the ║ notation represents the salt bridge or porous barrier if additional reactants are required or specific products are formed, they are written with the solution separated by a comma or a semicolon.
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if the cell has no metal for the electrode, inert electrodes C (s) or Pt (s) are used: Mg │ Mg 2+ ║ MnO 4 ¯, H + ; Mn 2+ │ C (s) standard cells are 1.0 M at SATP all three sets of information – REDOX equation, cell diagram and the cell notation are related and if 1 is provided, the other 2 should be able to be created.
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Calculating Cell Potential, E°cell for each half reaction the reduction potential is listed on the chart on p. 805 or the reference sheet. the complete cell is a combination of the reduction and oxidation half reactions - the sum of the two is the Cell potential, E° cell this is the usable energy given by: E° cell = E° red (cathode) + E° ox (anode)
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as all half reactions are listed as reduction rxns, the oxidation reaction flips the sign, so: E° cell = E° red (cathode) - E° red (anode) eg. Calculate the E° cell for: Br 2 + Cu 2 Br¯ + Cu + ox: Cu Cu + + e¯ E° ox = -(+0.52) V red: Br 2 + 2 e¯ 2 Br¯ E° red = +1.07 V Br 2 + 2 Cu 2 Br¯ + 2Cu + E° cell = + 0.55 V Spontaneous ( +ve) Or E° cell = +1.07 V – (+0.52 V) = +0.55 V 2x222
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eg. a)Determine the anode, cathode and calculate the standard cell potential produced by a galvanic cell consisting of a Sn electrode in contact with a solution of Sn 2+ ions and a Cr electrode in contact with a solution of Cr 3+ ions. b)Write the shorthand cell notation. Sn 2+ + 2e- SnE° = -0.14 V (lesser flip) Cr 3+ + 3e- CrE° = -0.74 V Anode:Cr Cr 3+ + 3e- E° = +0.74 V Cathode:Sn 2+ + 2e- SnE° = - 0.14 V E cell ° = +0.60 V Cr | Cr 3+ (aq) || Sn 2+ (aq) | Sn
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eg.Use complete half-reactions and potentials to predict whether the following reaction is spontaneous or non-spontaneous in aqueous solutions. If the cell is spontaneous, write the cell shorthand notation. cat(red): O 2 + 4 H + + 4 e- 2 H 2 O E° = +1.23 V an(ox): 2 SO 2 + 2 H 2 O 2 SO 4 2- + 4 H + + 4 e- E° = -0.18 V E cell ° = +1.05 V O 2 + 2 SO 2 + 4 OH - 2 SO 4 2- + 2 H 2 O 0 -2 +4 +6 | || Pt (s) | SO 2 (g),4 H + ;SO 4 2- (aq)O 2 (g),4 H + ;Pt (s)
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