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The Natural Exponential Function. Natural Exponential Function Any positive number can be used as the base for an exponential function. However, some.

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Presentation on theme: "The Natural Exponential Function. Natural Exponential Function Any positive number can be used as the base for an exponential function. However, some."— Presentation transcript:

1 The Natural Exponential Function

2 Natural Exponential Function Any positive number can be used as the base for an exponential function. However, some are used more frequently than others. We will see in the remaining sections of the chapter that the bases 2 and 10 are convenient for certain applications. However, the most important is the number denoted by the letter e.

3 Number e The number e is defined as the value that (1 + 1/n) n approaches as n becomes large. In calculus, this idea is made more precise through the concept of a limit.

4 Number e The table shows the values of the expression (1 + 1/n) n for increasingly large values of n. It appears that, correct to five decimal places, e ≈ 2.71828

5 Number e The approximate value to 20 decimal places is: e ≈ 2.71828182845904523536 It can be shown that e is an irrational number. So, we cannot write its exact value in decimal form.

6 Number e Why use such a strange base for an exponential function? It may seem at first that a base such as 10 is easier to work with. However, we will see that, in certain applications, it is the best possible base.

7 Natural Exponential Function—Definition The natural exponential function is the exponential function f(x) = e x with base e. It is often referred to as the exponential function.

8 Natural Exponential Function Since 2 < e < 3, the graph of the natural exponential function lies between the graphs of y = 2 x and y = 3 x.

9 Natural Exponential Function Scientific calculators have a special key for the function f(x) = e x. We use this key in the next example.

10 E.g. 6—Evaluating the Exponential Function Evaluate each expression correct to five decimal places. (a) e 3 (b) 2e –0.53 (c) e 4.8

11 E.g. 6—Evaluating the Exponential Function We use the e x key on a calculator to evaluate the exponential function. (a) e 3 ≈ 20.08554 (b) 2e –0.53 ≈ 1.17721 (c) e 4.8 ≈ 121.51042

12 E.g. 7—Transformations of the Exponential Function Sketch the graph of each function. (a) f(x) = e –x (b) g(x) = 3e 0.5x

13 E.g. 7—Transformations We start with the graph of y = e x and reflect in the y-axis to obtain the graph of y = e –x. Example (a)

14 E.g. 7—Transformations We calculate several values, plot the resulting points, and then connect the points with a smooth curve. Example (b)

15 E.g. 8—An Exponential Model for the Spread of a Virus An infectious disease begins to spread in a small city of population 10,000. After t days, the number of persons who have succumbed to the virus is modeled by:

16 (a)How many infected people are there initially (at time t = 0)? (b)Find the number of infected people after one day, two days, and five days. (c)Graph the function v and describe its behavior. E.g. 8—An Exponential Model for the Spread of a Virus

17 E.g. 8—Spread of Virus We conclude that 8 people initially have the disease. Example (a)

18 E.g. 8—Spread of Virus Using a calculator, we evaluate v(1), v(2), and v(5). Then, we round off to obtain these values. Example (b)

19 E.g. 8—Spread of Virus From the graph, we see that the number of infected people: First, rises slowly. Then, rises quickly between day 3 and day 8. Then, levels off when about 2000 people are infected. Example (c)

20 Logistic Curve This graph is called a logistic curve or a logistic growth model. Curves like it occur frequently in the study of population growth.

21 Compound Interest

22 Exponential functions occur in calculating compound interest. Suppose an amount of money P, called the principal, is invested at an interest rate i per time period. Then, after one time period, the interest is Pi, and the amount A of money is: A = P + Pi + P(1 + i)

23 Compound Interest If the interest is reinvested, the new principal is P(1 + i), and the amount after another time period is: A = P(1 + i)(1 + i) = P(1 + i) 2 Similarly, after a third time period, the amount is: A = P(1 + i) 3

24 Compound Interest In general, after k periods, the amount is: A = P(1 + i) k Notice that this is an exponential function with base 1 + i.

25 Compound Interest Now, suppose the annual interest rate is r and interest is compounded n times per year. Then, in each time period, the interest rate is i = r/n, and there are nt time periods in t years. This leads to the following formula for the amount after t years.

26 Compound Interest Compound interest is calculated by the formula where: A(t) = amount after t years P = principal t = number of years n = number of times interest is compounded per year r = interest rate per year

27 E.g. 9—Calculating Compound Interest A sum of $1000 is invested at an interest rate of 12% per year. Find the amounts in the account after 3 years if interest is compounded: Annually Semiannually Quarterly Monthly Daily

28 E.g. 9—Calculating Compound Interest We use the compound interest formula with: P = $1000, r = 0.12, t = 3

29 Compound Interest We see from Example 9 that the interest paid increases as the number of compounding periods n increases. Let’s see what happens as n increases indefinitely.

30 Compound Interest If we let m = n/r, then

31 Compound Interest Recall that, as m becomes large, the quantity (1 + 1/m) m approaches the number e. Thus, the amount approaches A = Pe rt. This expression gives the amount when the interest is compounded at “every instant.”

32 Continuously Compounded Interest Continuously compounded interest is calculated by A(t) = Pe rt where: A(t) = amount after t years P = principal r = interest rate per year t = number of years

33 E.g. 10—Continuously Compounded Interest Find the amount after 3 years if $1000 is invested at an interest rate of 12% per year, compounded continuously.

34 E.g. 10—Continuously Compounded Interest We use the formula for continuously compounded interest with: P = $1000, r = 0.12, t = 3 Thus, A(3) = 1000e (0.12)3 = 1000e 0.36 = $1433.33 Compare this amount with the amounts in Example 9.


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