1. Section 2.4 Solving Linear Equations in One Variable Using the Addition-Subtraction Principle

2. 2.4 Lecture Guide: Solving Linear Equations in One Variable Using the Addition-Subtraction Principle Objective 1: Solve linear equations in one variable using the addition-subtraction principle. Algebraically A linear equation in one variable x is an equation that can be written in the form, where A and B are real constants and. Verbally A linear equation in one variable is _________ degree in this variable. Algebraic Example Linear Equation in One Variable

3. (a) 3x + 1 =10 (b) 3x + y =10 (c)(d) 3x+1 – 10 1. Which of the following choices are linear equations in one variable?

4. Verbally If the same number is added to or subtracted from both sides of an equation, the result is an _______________ equation. Algebraically If a, b, and c are real numbers, then a = b is equivalent to a + c = _______ and to a – c = ________. Numerical Example Addition-Subtraction Principle of Equality

5. 2.3. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

6. 4.5. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

7. 6.7. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

8. 8.9. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

9. 10. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

10. 11. Use the addition-subtraction principle of equality to solve each equation. Note that we can check our solution of each equation.

11. Based on the limited variety of equations we have examined, a good strategy to solve a linear equation in one variable is: 1) Use the __________________ property to remove any __________________ symbols. 2) Use the addition-subtraction principle of equality to move all __________________terms to one side. 3) Use the addition-subtraction principle of equality to move all __________________ terms to the other side.

12. Objective 2: Use graphs and tables to solve a linear equation in one variable. The solution of a linear equation in one variable is an x- value that causes both sides of the equation to have the same value. To solve a linear equation in one variable using graphs or tables, let Y 1 equal the left side of the equation and let Y 2 equal the right side of the equation. Using a graph, look for the ______-coordinate of the point of __________________ of the two graphs. Using a table of values, look for the ______-value where the two ______- values are equal. Note that the solution of a linear equation in one variable is an x-value and not an ordered pair.

13. 12. Use the graph shown to determine the solution of the equation. The point where the two lines intersect has an x-coordinate of ______. Solution: __________ Verify your result by solving algebraically.

14. 13. Use the table shown to determine the solution of the equation. The x-value in the table at which the two y values are equal is ______. Solution: _____________ Verify your result by solving algebraically.

15. Solve each equation using a table or a graph from your calculator by letting Y 1 equal the left side of the equation and Y 2 equal the right side of the equation. See Technology Perspective 2.3.2 for help. 14. Solution: ____________ 15. Solution: ____________ Once the viewing window has been adjusted so you can see the point of intersection of two lines, the keystrokes required to find that point of intersection are ______ ______ ______ ______ ______ ______. To view a graph in the standard viewing window, press ZOOM ______.

16. Objective 3: Identify a linear equation as a conditional equation, an identity, or a contradiction. There are three classifications of linear equations: conditional equations, identities, and contradictions. Each of the equations in problems 2-11 is called a __________________ __________________ because it is only true for certain values of the variable and untrue for other values.

17. Algebraic Example Graphical Example Numerical Example 2x = x + 3 Solution: x = 3 The only value of x that checks is x = 3. The lines intersect at an x-value of 3. The table values of and are equal for x = 3. Conditional Equation: A conditional equation is true for some values of the variable and false for other values. x -22 003 124 245 366 487

18. Identity: An identity is an equation that is true for all values of the variable. Algebraic Example Graphical Example Numerical Example 2x = x + x Solution: All real numbers. All real numbers will check. x + x is always 2x. You see only one line because the lines coincide for all values of x. The table values of and are equal for all values x. x -2 000 122 244 366 488

19. Algebraic Example Graphical Example Numerical Example x = x + 3 Solution: No Solution. No real numbers will check because no real number is 3 greater than its own value. These lines have no points in common. The table values of and will never be equal for any value of x. Contradiction: A contradiction is an equation that is false for all values of the variable. x 11 11 2 003 114 225 336 447

20. Tip: If the solution process for solving a linear equation in one variable produces a unique solution, then the original equation is a conditional equation. If the solution process results in the variable disappearing from both sides of the equation, then the equation you are trying to solve is either a contradiction or an identity Identify each equation as a contradiction or identity and write the solution of the equation. 16. 3x + 2 – x = 4 + 2x

21. Tip: If the solution process for solving a linear equation in one variable produces a unique solution, then the original equation is a conditional equation. If the solution process results in the variable disappearing from both sides of the equation, then the equation you are trying to solve is either a contradiction or an identity Identify each equation as a contradiction or identity and write the solution of the equation. 17. 5x + 3 – 2x = 3x + 3

22. Tip: If the solution process for solving a linear equation in one variable produces a unique solution, then the original equation is a conditional equation. If the solution process results in the variable disappearing from both sides of the equation, then the equation you are trying to solve is either a contradiction or an identity Identify each equation as a contradiction or identity and write the solution of the equation. 18. 4(2x – 3) = 7x – 12 + x

23. Tip: If the solution process for solving a linear equation in one variable produces a unique solution, then the original equation is a conditional equation. If the solution process results in the variable disappearing from both sides of the equation, then the equation you are trying to solve is either a contradiction or an identity Identify each equation as a contradiction or identity and write the solution of the equation. 19. 3x + 4 + 2x = 5(x –1)

24. Simplify vs Solve Simplify the expression in the first column by combining like terms, and solve the equation in the second column. 20. Simplify 7x + 3 + 6x – 5 21. Solve 7x +3 = 6x – 5

25. 22. Simplify 3x + 4 – (2x – 8) 23. Solve 3x + 4 = 2x – 8 Simplify vs Solve Simplify the expression in the first column by combining like terms, and solve the equation in the second column.

26. Translate each verbal statement into algebraic form. 24. Eight more than three times a number is equal to three less than the number. 25. Seven less than six times a number equals two times the quantity of eight less than a number.

27. 26. Write an algebraic equation for the following statement, using the variable m to represent the number, and then solve for m. Verbal Statement: Five less than three times a number is equal to two times the sum of the number and three. Algebraic Equation: Solve this equation:

28. a cm 8 cm a cm 27. The perimeter of the parallelogram shown equals (26 + a) cm. Find a.