2. Hello, My name is Professor Duitt

3. I’m here to show you the method we REQUIRE for solving problems!

4. It’s called the

5. This method will help you with a systematic approach to solving even the most difficult problems.

6. Let’s look at a very simple problem to start with so we can focus on the different steps of the format.

7. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609m (one mile)?

8. Step#1: Read the problem! You may want to underline key terms.

9. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long

10. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long Step#2: List the knowns and unknowns in a COLUMN

11. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long t = ? v = 662 m/s s = 1609 m

12. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long t = ? v = 662 m/s s = 1609 m v = s t Step#3: Write the equation needed, to solve the problem, in the most familiar form. Equations as given on the NYS Regents Reference Tables are acceptable as “the most familiar form”.

13. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long t = ? v = 662 m/s s = 1609 m Step#4: Rearrange the equation solving for the variable you are looking for. v = s t s t t t s t v v = s t v

14. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long t = ? v = 662 m/s s = 1609 m Step#5: Substitute for the known quantities the numerical values along with their appropriate units. v = s t s t t t s t v v = s t v 1609 m = t 662 m s

15. How long would it take a F-15 Eagle jet fighter traveling at 662 m/s (Twice the speed of sound, 1481 mi/hr or Mach 2) to fly 1609 m (one mile)? 662 m/s 1609 m How long t = ? v = 662 m/s s = 1609 m Step#6: Solve! Remember to include units in your answer. v = s t s t t t s t v v = s t v 1609 m = t 662 m s t = 2.4 s

16. Let’s Review. 1. Read the problem. 2. List the knowns and unknowns. 3. Write an equation in the most familiar form. 5. Substitute with numbers and units. 6. Solve and include units in the answer. 4. Rearrange the equation solving for the unknown variable.

17. Sometimes it helps to draw a simple neat diagram of the problem instead of listing the information in columnar form.

18. I’ll demonstrate using a little more complicated problem how a diagram will help organize the information.

19. Keep in mind the steps to the as the problem is solved.

20. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? 1. Read the problem.

21. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v o = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s 2. List the knowns and unknowns. a 1 = 4 m s2s2 s T = ? v 2 = constant

22. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s 3. Write an equation in the most familiar form. s 1 = v o t + at 2 2 a 1 = 4 m s2s2 s T = ? v 2 = constant

23. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = v o t + at 2 2 0 s 1 = at 2 2 4. Rearrange the equation solving for the unknown variable. a 1 = 4 m s2s2 s T = ? v 2 = constant

24. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = v o t + at 2 2 0 s 1 = at 2 2 s 1 = 4 m (3 s) 2 2 s2s2 5. Substitute with numbers and units. a 1 = 4 m s2s2 s T = ? v 2 = constant

25. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = v o t + at 2 2 0 s 1 = at 2 2 s 1 = 4 m (3 s) 2 2 s2s2 s 1 = 18 m 6. Solve and include units in the answer. s 1 = 18 m a 1 = 4 m s2s2 s T = ? v 2 = constant

26. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m 3. Write an equation in the most familiar form. v 3 = v 0 + a 1 t a 1 = 4 m s2s2 s T = ? v 2 = constant

27. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = v 0 + a 1 t 0 4. Rearrange the equation solving for the unknown variable. v 3 = a 1 t a 1 = 4 m s2s2 s T = ? v 2 = constant

28. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = v 0 + a 1 t 0 v 3 = a 1 t v 3 = 4 m (3 s) s2s2 5. Substitute with numbers and units. a 1 = 4 m s2s2 s T = ? v 2 = constant

29. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = v 0 + a 1 t 0 v 3 = a 1 t v 3 = 4 m (3 s) s2s2 6. Solve and include units in the answer. v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 v 3 = 12 m s v 2 = constant background v 2 = 12 m s s T = ?

30. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 3. Write an equation in the most familiar form. s t v = background v 2 = 12 m s s T = ?

31. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s t v = 4. Rearrange the equation solving for the unknown variable. s = v t background v 2 = 12 m s s T = ?

32. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s t v = s = v t 5. Substitute with numbers and units. s = 12 m (20 s) s background v 2 = 12 m s s T = ?

33. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s t v = s = v t s = 12 m (20 s) s s = 240 m 6. Solve and include units in the answer. s 2 = 240 m background v 2 = 12 m s s T = ?

34. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s 2 = 240 m 3. Write an equation in the most familiar form. s total = s 1 + s 2 background v 2 = 12 m s s T = ?

35. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s 2 = 240 m s total = s 1 + s 2 4. Rearrange the equation solving for the unknown variable. background v 2 = 12 m s s T = ?

36. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s 2 = 240 m s total = s 1 + s 2 5. Substitute with numbers and units. s total = 18 m + 240 m background v 2 = 12 m s s T = ?

37. A car speeding away from a stop sign, accelerates at 4 m/s 2 for 3 sec. If the car then maintains this speed, how far is it from the stop sign 23 seconds after starting? t = 0 s t = 3 s t = 23 s v 0 = 0 s v 3 = ? v 23 = ? s 1 = ? s 2 = ? t 2 = 20 s s 1 = 18 m v 3 = 12 m s v 23 = 12 m s a 1 = 4 m s2s2 s 2 = 240 m s total = s 1 + s 2 s total = 18 m + 240 m 6. Solve and include units in the answer. s total = 258 m WOW! background v 2 = 12 m s s T = ? s total = 258 m

38. Let’s go over the six steps

39. Underline key information if needed Read the problem.

40. In a column or preferably a diagram. List the knowns and unknowns.

41. Write an equation in the most familiar form. c 2 = a 2 + b 2 examplenot a = (c 2 - b 2 ) 1 2

42. Rearrange the equation solving for the unknown variable.

43. Substitute in the numbers and units.

44. Solve and include units in the answer. Draw a box around the answer.