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Barriers in Hamiltonian Complexity Umesh V. Vazirani U.C. Berkeley.

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Presentation on theme: "Barriers in Hamiltonian Complexity Umesh V. Vazirani U.C. Berkeley."— Presentation transcript:

1 Barriers in Hamiltonian Complexity Umesh V. Vazirani U.C. Berkeley

2 Quantum Complexity Theory Condensed Matter Theory Hamiltonian Complexity

3 ClassicalQuantum Constraint Satisfaction Problem Local Hamiltonian Solution Ground State

4 Condensed Matter Theory Describing ground states of local Hamiltonians, and understanding their properties. Problem: n qubit state described by 2 n complex numbers. Ground states of realistic systems have concise descriptions. Reason: Limited entanglement.

5 Area Laws Assuming area laws, beautiful sequence of results showing how to simulate quantum systems efficiently using tensor networks, MERAs and PEPs. [Vidal; Verstraete & Cirac,...]

6 Quantum Complexity Theory Quantum Classical Local Hamiltonian k-SAT NP-hard to find assignment min # UNSAT clauses [Kitaev] QMA-hard to find ground state

7 Quantum Complexity Theory Quantum Classical Local Hamiltonian k-SAT NP-hard to find assignment min # UNSAT clauses [Kitaev] QMA-hard to find ground state [Gottesman, Irani 09] Ground states of translationally invariant 1-D Hamiltonians hard unless BQEXP = QMA EXP

8 Quantum Complexity Theory Quantum Classical Local Hamiltonian k-SAT NP-hard to find assignment min # UNSAT clauses ?? QMA-hard to find any low energy state? PCP Theorem Classical approx

9 Two Major Challenges in Hamiltonian Complexity Prove or disprove a quantum PCP theorem. Prove the area law for 2-D and 3-D gapped local Hamiltonians.

10 Local Hamiltonians n qubit system Hamiltonian: H = 2 n x 2 n hermitian matrix. Energy operator: eigenstates of H are states with definite energy. Energy = eigenvalue. k-local if each term acts non-trivially on k qubits. Each term assigns energy penalty to state. Interested in structure and eigenvalue (energy) associated with lowest eigenstate (ground state).

11 3SAT as a local Hamiltonian Problem n bits ---> n qubits Clause c i = x 1 v x 2 v x 3 corresponds to 8x8 Hamiltonian matrix acting on first 3 qubits: Satisfying assignment is eigenvector with evalue 0. All truth assignments are eigenvectors with eigenvalue = # unsat clauses.

12 [Kitaev] Given a local hamiltonian H = H 1 +... + H m it is QMA-hard to determine the minimum eigenvalue (ground state energy) of H to within 1/poly(n) PCP Theorem: Polynomial time procedure to convert 3-SAT formula f into g: f satisfiable implies g satisfiable f unsatisfiable implies g < 1-c satisfiable.

13 [Kitaev] Given a local hamiltonian H = H 1 +... + H m it is QMA-hard to determine the minimum eigenvalue (ground state energy) of H to within 1/poly(n). PCP Theorem: Polynomial time procedure to convert 3-SAT formula f into g: f satisfiable implies g satisfiable f unsatisfiable implies g < 1-c satisfiable. Quantum PCP: Given a local hamiltonian H = H 1 +... + H m is it QMA-hard to determine the minimum eigenvalue (ground state energy) of 1/m H to within c for some constant c? i.e. Is there a quantum poly time alg that converts any local hamiltonian H into H’ such that |H’| = O(1) and if H has promise gap 1/poly(n) then H’ has promise gap constant c. Quantum PCP Formulation

14 Well balanced question: No strong intuition to call it a quantum PCP conjecture. [Aharonov, Arad, Landau, V 2008] Proof of quantum gap amplification using the detectability lemma. Dinur’s proof uses GA + degree reduction + alphabet reduction. Can define quantum PCP in terms of proof checking. i.e. is there a quantum state that can be checked by accessing only constant number of qubits. The two definitions are equivalent.

15 Area Law For gapped local Hamiltonians H = H 1 +... + H m, ground state has low entanglement. Gapped = e 1 - e 0 > c. [Hastings 2007] Proof of area law for 1-D systems. [Aharonov, Arad, Landau, V 2010] Simplified proof for frustration-free 1-D systems, using detectability lemma.

16 Area Law For gapped local Hamiltonians H = H 1 +... + H m, ground state has low entanglement. Gapped = e 1 - e 0 > c. How to quantify entanglement?

17 Quantifying Entanglement A B Schmidt decomposition: {|a i >}, {|b i >} orthonormal sets Entanglement rank = number of non-zero terms Entanglement rank = 1 iff product state. Entanglement entropy = classical entropy of {c i 2 }

18 Detectability Lemma H = H 1 +... + H m Assume H i = I - P i where P i is a projection matrix. Assume gap = e 1 - e 0. Frustration-free: Assume ground energy = 0. i.e. ground state satisfies all m constraints. The normalized operator G = (I - 1/m H) fixes the ground state, but shrinks all other evectors by a factor of (1 - gap/m). So if H is gapped, i.e. gap = constant, then shrinkage ~ 1/m. Can a local operator achieve constant shrinkage?

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20 Overall Idea of Proof (of 1D area law) Step 1: Show that there is a product state |a> x |b> which has constant overlap (inner product) with the ground state. Step 2: Show that this implies that the ground state has constant entanglement.

21 Overall Idea of Proof (of 1D area law) Step 1: Show that there is a product state |a> x |b> which has constant overlap (inner product) with the ground state. Step 2: Show that this implies that the ground state has constant entanglement. To prove step 2, repeatedly apply a transformation to |a> x |b> that moves it closer to the ground state without increasing its entanglement entropy much. The detectability lemma gives exactly such a transformation.

22 Overlap r implies entropy = O(1/e log 1/re log D)

23 To prove Step 1: Assume for contradiction that the maximum overlap between ground state and a product state is at most 2 -l for some large constant l. Consider the product state above corresponding to the ground state. Since it has small overlap with the ground state, there is a measurement that can distinguish the two with probability at least 1 - 2 -l. Use the detectability lemma to show that such a measurement can be done locally (on O(l) qudits). Conclude that the entanglement across the boundary is proportional to l.

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25 The Numbers Measurement on 2l qudits distinguishes product state from ground state with probability 1 - exp(-el), where e = gap. This implies entanglement entropy of el across this boundary. Now by monogamy of entanglement: el el/2 e l log l l < exp(1/e log D)

26 So overlap > exp(-el), with l < exp(1/e log D) Overlap r implies entropy = O(1/e log 1/re log D) So entanglement entropy = O(1/e log D exp(1/e log D))

27 Conclusions Proving area law in more than 1-D and quantum PCP theorem are two major challenges. To prove 2-D case sufficient to consider frustration-free Hamiltonians. i.e. detectability lemma applies. Would be interesting to know if area law breaks down for any interaction graph.


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