1. Section 9.2 Hypothesis Testing Proportions P-Value

6. What type of test is it?

8. %Left-tailedRight-tailedTwo-tailed.2080-.84.841.28.1585-1.031.031.44.1090-1.281.281.645.0595-1.6451.6451.96.0298-2.052.052.33.0199-2.332.332.575

11. Steps to Solve the Problem: Step 1: Define the hypothesis Step 2: Compute the value of the z test statistic or the P-value Step 3: Determine if the hypothesis is one-tailed or two-tailed Step 4: Compare the z-test statistic to the z for the α or compare the P-value of the z- test statistic to the α. Step 5: Make the decision based on the decision rules. Step 6: Determine the conclusion. State the decision in terms of the claim being tested.

14. Step 3: One-tailed or two-tailed? Since the problem states “less than” the hypothesis is one-tailed. Step 4: Since the confidence level is 95% we can use an α of.05 or the z-score of -1.645. (this is negative since it is left tailed) Since the test statistic is -0.88, we can compare this to -1.645, or we can find the p-value of.1894 and compare it to.05. In both situations the test statistic is greater than the confidence level.

15. Step 5: Since the test statistic is greater than the confidence level, we will fail to reject the null. Meaning there is not sufficient evidence to support the claim.

16. The z-score for the.10 significance level is 1.645. Since 2.23 is greater it falls in the rejection region. The P-value for 2.33 is 0.0129. Since this value is less than.10 it falls in the rejection region. NOTE: Since this is two-tailed, for comparing the p-values you must divide the significance level by 2.