Download presentation
Presentation is loading. Please wait.
Published byLenard Tucker Modified over 8 years ago
1
ASTROPHYSICS Yr 2 Session 3 – Orbits & the Solar System 1
2
Solar System Contents One star
3
Inner planets (not to scale) Mercury Mars Earth Venus
4
Asteroids
5
Outer (gas giant) planets Jupiter Saturn Uranus Neptune
6
Kuiper Belts objects Pluto & Charon
7
Comets
8
Meteoroids
9
The whole Solar System
10
L =3.826×10 26 Watts r L /4 r 2 Wm -2 1 A.U. 1.36×10 3 Wm -2 The Solar constant Solar radiation
11
Apparent brightness of the Planets Albedo A = Fraction of solar radiation reflected by planet Venus & crescent Moon
12
Example: Saturn’s moon Iapetus High albedo Low albedo
13
r (A.U.’s) R Cross sectional Area = R 2 S 0 = Solar constant. S mars = ‘solar constant’ for Mars S mars = S 0 /r 2 Wm -2 Total radiation reflected by Mars = A × S mars × R 2
14
Planet positions & motion
15
Principal planet positions ° = elongation
16
Retrograde motion
18
Eclipses
19
Moon at perigee & apogee
21
Lunar eclipses
22
Earth’s orbit as seen from the Sun Sun’s apparent orbit as seen from the Earth The Ecliptic (again) Celestial Equator
23
North pole of the ecliptic North celestial pole is here
24
Ecliptic coordinates
25
Johannes Kepler 1571 - 1630 Kepler’s laws of planetary motion
26
The Epicycle Planetary motion problems
27
Tycho Brahe 1546 - 1601
28
Kepler’s Laws First Law: The orbit of each planet is an ellipse with the Sun at one focus. Second Law: The rate at which the radius vector sweeps out an area on the ellipse is a constant. Third Law: The ratio of the semi-major axis cubed to the orbital period squared is the same constant for all the planets. i.e. is a constant, where P is the planet’s orbital period.
29
The Ellipse Directrix Area = ab GF 1 /GZ 1 = GF 2 /GZ 2 = e e = eccentricity (<1) Cartesian equation
30
F 1 PA = Periapsis r 1 F 1 AA = Apapsis r 2 Line of apsides For an orbiting body at P
31
r = Radius vector = True anomaly For an orbiting body at P
32
Important ellipse properties Polar form of Ellipse equation
33
Example: Proof of OF 1 = ae OF1F1 P1P1 P2P2 Z P 1 P 2 = 2a P 1 F 1 = eP 1 Z: P 2 F 1 = eP 2 Z P 2 F 1 – P 1 F 1 = e(P 2 Z - P 1 Z) = e × 2a Also: P 2 F 1 = a + OF 1 & P 1 F 1 = a – OF 1 P 2 F 1 – P 1 F 1 = 2OF 1 = e × 2a: Hence OF 1 = ea aa
34
Kepler’s Third Law = 1 if… a is in A.U.’s P in sidereal years (365.257 days) We need to determine a for the Earth.
35
Finding the Astronomical Unit Jeremiah Horrocks 1619 - 1641
36
The 2004 transit of Venus
38
The Asteroid Eros
39
Venus
40
Next time – Orbits & the Solar System 2
41
Logarithms Quick Notes
44
The number ‘e’ = 2.718 Same basic properties as for logs to base 10
46
See ‘Serious Logarithm Notes’ on Blackboard for full details
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.