Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 5 (part 2) Enzyme Kinetics. Rate constant (k) measures how rapidly a rxn occurs AB + C k1k1 k -1 Rate (v, velocity) = (rate constant) (concentration.

Similar presentations


Presentation on theme: "Chapter 5 (part 2) Enzyme Kinetics. Rate constant (k) measures how rapidly a rxn occurs AB + C k1k1 k -1 Rate (v, velocity) = (rate constant) (concentration."— Presentation transcript:

1 Chapter 5 (part 2) Enzyme Kinetics

2 Rate constant (k) measures how rapidly a rxn occurs AB + C k1k1 k -1 Rate (v, velocity) = (rate constant) (concentration of reactants) v= k 1 [A] 1 st order rxn (rate dependent on concentration of 1 reactant) v= k -1 [B][C] 2 nd order rxn (rate dependent on concentration of 2 reactants) Zero order rxn (rate is independent of reactant concentration) Rate constants and reaction order

3 Michaelis-Menton Kinetics Sucrose + H20  Glucose + Fructose Held [S] constant and varied the amount of enzyme added E + S ES E + P

4 Michaelis-Menton Kinetics Sucrose + H20  Glucose + Fructose Held [E] constant and varied the amount of substrate added V max/2 =Km (Michaelis Constant) [S] @ ½ Vmax (units moles/L=M)

5 Michaelis-Menton Equation Vo = Vmax [S] Km + [S] M-M equation describes the equation of a rectangular hyperbolic curve.

6 1)Measurements made to measure initial velocity (v o ). At v o very little product formed. Therefore, the rate at which E + P react to form ES is negligible and k -2 is 0. Therefore Also since [S] >>>[E], [S] can be assumed to be constant. Initial Velocity Assumption Instead of E + S ESE + P k1k1 k -1 k cat k -2 We assume E + S ESE + P k1k1 k -1 k cat

7

8 Steady State Assumption E + S ESE + P k1k1 k -1 k cat Steady state Assumption = [ES] is constant. The rate of ES formation equals the rate of ES breakdown Rate of ES formation = k 1 [E][S] Rate of ES break down = k -1 [ES] + k cat [ES] = [ES](k -1 + k cat )

9

10 Therefore………. 1) k 1 [E][S] = [ES](k -1 + k cat ) 2) (k -1 + k cat ) / k 1 = [E][S] / [ES] 3) (k -1 + k cat ) / k 1 = K m (Michaelis constant)

11 What does Km mean? 1.Km = [S] at ½ V max 2.Km is a combination of rate constants describing the formation and breakdown of the ES complex 3.Km is usually a little higher than the physiological [S]

12 What does Km mean? 4.Km represents the amount of substrate required to bind ½ of the available enzyme (binding constant of the enzyme for substrate) 5.Km can be used to evaluate the specificity of an enzyme for a substrate (if obeys M-M) 6.Small K m means tight binding; high K m means weak binding GlucoseKm = 8 X 10 -6 AlloseKm = 8 X 10 -3 MannoseKm = 5 X 10 -6 Hexose Kinase Glucose + ATP Glucose-6-P + ADP

13 What does k cat mean? 1.k cat is the 1 st order rate constant describing ES  E+P 2.Also known as the turnover # because it describes the number of rxns a molecule of enzyme can catalyze per second under optimal condition. 3.Most enzyme have k cat values between 10 2 and 10 3 s -1 4.For simple reactions k 2 = k cat, for multistep rxns k cat = rate limiting step E + S ESE + P k1k1 k -1 k cat

14

15 What does k cat /K m mean? It measures how the enzyme performs when S is low k cat /K m describes an enzymes preference for different substrates = specificity constant The upper limit for k cat /K m is the diffusion limit - the rate at which E and S diffuse together (10 8 to 10 9 m -1 s -1 ) Catalytic perfection when k cat /K m = diffusion rate More physiological than kcat

16

17 Limitations of M-M 1.Some enzyme catalyzed rxns show more complex behavior E + S ES EZ EP E + P With M-M can look only at rate limiting step 2.Often more than one substrate E+S 1 ES 1 +S 2 ES 1 S 2 EP 1 P 2 EP 2 +P 1 E+P 2 Must optimize one substrate then calculate kinetic parameters for the other 3.Assumes k -2 = 0 4.Assume steady state conditions


Download ppt "Chapter 5 (part 2) Enzyme Kinetics. Rate constant (k) measures how rapidly a rxn occurs AB + C k1k1 k -1 Rate (v, velocity) = (rate constant) (concentration."

Similar presentations


Ads by Google