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Example 15.6: Find the pH of 0.200 M HNO 2 (aq) 25 °C 9 Tro, Chemistry: A Molecular Approach, 2/e.

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Presentation on theme: "Example 15.6: Find the pH of 0.200 M HNO 2 (aq) 25 °C 9 Tro, Chemistry: A Molecular Approach, 2/e."— Presentation transcript:

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9 Example 15.6: Find the pH of 0.200 M HNO 2 (aq) solution @ 25 °C 9 Tro, Chemistry: A Molecular Approach, 2/e

10 Example 15.6: Find the pH of 0.200 M HNO 2 (aq) solution @ 25 °C 10 Tro, Chemistry: A Molecular Approach, 2/e

11 Practice – What is the pH of a 0.012 M solution of nicotinic acid, HC 6 H 4 NO 2 ? (K a = 1.4 x 10 −5 @ 25 °C) 11 Tro, Chemistry: A Molecular Approach, 2/e

12 Practice – What is the pH of a 0.012 M solution of nicotinic acid, HC 6 H 4 NO 2 ? (K a = 1.4 x 10 −5 @ 25 °C) 12 Tro, Chemistry: A Molecular Approach, 2/e

13 Example 15.7: Find the pH of 0.100 M HClO 2 (aq) solution @ 25 °C 13 K a for HClO 2 = 1.1 x 10 −2 Tro, Chemistry: A Molecular Approach, 2/e

14 Example 15.7: Find the pH of 0.100 M HClO 2 (aq) solution @ 25 °C 14 K a for HClO 2 = 1.1 x 10 −2 Tro, Chemistry: A Molecular Approach, 2/e

15 Example 15.8: What is the K a of a weak acid if a 0.100 M solution has a pH of 4.25? HA + H 2 O  A  + H 3 O + Tro, Chemistry: A Molecular Approach, 2/e

16 Example 15.8: What is the K a of a weak acid if a 0.100 M solution has a pH of 4.25? HA + H 2 O  A  + H 3 O + Tro, Chemistry: A Molecular Approach, 2/e

17 Practice – What is the K a of nicotinic acid, HC 6 H 4 NO 2, if a 0.012 M solution of nicotinic acid has a pH of 3.40? 17 Tro, Chemistry: A Molecular Approach, 2/e

18 Practice – What is the K a of nicotinic acid, HC 6 H 4 NO 2, if a 0.012 M solution of nicotinic acid has a pH of 3.40? 18 Tro, Chemistry: A Molecular Approach, 2/e

19 Practice – What is the percent ionization of a 0.012 M solution of nicotinic acid, HC 6 H 4 NO 2 ? (K a = 1.4 x 10 −5 @ 25 °C) 19 Tro, Chemistry: A Molecular Approach, 2/e

20 Practice – What is the percent ionization of a 0.012 M solution of nicotinic acid, HC 6 H 4 NO 2 ? (K a = 1.4 x 10 −5 @ 25 °C) 20 Tro, Chemistry: A Molecular Approach, 2/e


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