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Published byAbigail Spencer Modified over 9 years ago
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5.9.1 – The Quadratic Formula and Discriminant
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Recall, we have used the quadratic formula previously Gives the location of the roots (x-intercepts) of the graph of a parabola Function must be in standard form; f(x) = ax 2 + bx + c
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Example. Find the roots for the function f(x) = 2x 2 + 5x - 7
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Example. Find the roots for the function f(x) = x 2 - 2x - 4
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All of the solutions we have covered though are real Possible to have imaginary roots = roots of the form a + bi Problem: cannot visualize the imaginary roots Still may find them algebraically
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Since we cannot graph imaginary solutions, it can be difficult to tell what kind of solutions we could expect Discriminant = a way to determine the number(s) and type of solutions b 2 – 4ac The following cases could occur; If b 2 – 4ac > 0, two real solutions If b 2 – 4ac = 0, one real solution If b 2 – 4ac < 0, two imaginary solutions No mix and match
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Example. Find the discriminant and given the number(s) and type of solutions for the following functions. A) x 2 – 6x + 8 = 0 B) x 2 – 6x + 9 = 0 C) x 2 – 6x + 10 = 0
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Example. Find the discriminant and solution(s) to the following quadratic using the quadratic equation. f(x) = x 2 + 2x + 3
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Example. Find the discriminant and solution(s) to the following quadratic using the quadratic equation. f(x) = x 2 – 4x + 4
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Assignment Pg. 278 37-45 odd 51-59 odd
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