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Published byVictor Bridges Modified over 9 years ago
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Drill: A 0.100 M solution of HZ ionizes 20.0 %. Calculate: K aHZ
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Buffer Solutions
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Buffer Solution A solution that resists changes in pH
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Buffer Solution Made from the combination of a weak acid & its salt
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Buffer Solution Made from the combination of a weak base & its salt
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Buffer Examples Mix acetic acid & sodium acetate Mix ammonia & ammonium chloride
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Buffer Solution A buffer solution works best when the acid to salt ratio is 1 : 1
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Buffer Solution A buffer solution works best when the base to salt ratio is 1 : 1
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Buffer Solution The buffering capacity of a solution works best when the pH is near the pK a
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pK a or pK b pK a = - log K a pK b = - log K b
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Buffer Equilibria
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To solve buffer equilibrium problems, use the same 5 steps
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5 Steps of Equilibrium Problems 1) Set up & balance reaction
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5 Steps of Equilibrium Problems 2) Assign Equilibrium amounts in terms of x (ICE)
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5 Steps of Equilibrium Problems 3) Write the equilibrium expression (K = ?)
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5 Steps of Equilibrium Problems 4) Substitute Equilibrium amounts into the K
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5 Steps of Equilibrium Problems 5) Solve for x
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Buffer Problems Calculate the pH of a solution containing 0.10 M HAc in 0.10 M NaAc: K a = 1.8 x 10 -5
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Buffer Problems Calculate the pH of 0.10 M NH 3 in 0.20 M NH 4 NO 3 : K b = 1.8 x 10 -5
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Buffer Problems Calculate the pH of a solution containing 0.10 M HBz in 0.20 M NaBz: K a = 6.4 x 10 -5
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Drill: Calculate the pH of a solution containing 0.30 M HZ in 0.10 M NaZ: K a = 3.0 x 10 -5
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Buffer Problem Calculate the pH of a solution containing 0.50 M R-NH 2 in 0.10 M R-NH 3 I: K b = 4.0 x 10 -5
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Derivations from an equilibrium constant
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HAH + + A - [ H + ][ A - ] [ HA ] K a =
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HAH + + A - [ H + ][ A - ] [ HA ] K a = Cross multiply to isolate [H + ]
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HAH + + A - [ K a ][ HA ] [ A - ] [H + ]=
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HAH + + A - [ HA ] [ A - ] [H + ] = (K a )
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HAH + + A - [ HA ] [ A - ] [H + ] = (K a ) Take –log of each side
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pH = [ HA ] [ A - ] pK a - log
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Henderson- Hasselbach Eq [A - ] [HA] pH = pK a + log
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Henderson- Hasselbach Eq [B + ] [B] pOH = pK b + log
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Buffer Problems Calculate the salt to acid ratio to make a buffer solution with pH = 5.0 K a for HBZ = 2.0 x 10 -5
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Derivations from an equilibrium constant
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HAH + + A - [ H + ][ A - ] [ HA ] K a =
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[ H + ][ A - ] [ HA ] K a = Divide both sides by [H + ]
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K a [ A - ] [ H + ] [ HA ] = You Get the Salt to Acid Ratio
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Drill: Calculate the salt to acid ratio to make a buffer solution with pH = 5.0 K a for HBZ = 2.0 x 10 -5
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Buffer Problems Calculate the salt to base ratio to make a buffer solution with pH = 9.48 K b for MOH = 2.0 x 10 -5
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Equivalence Point Point at which the # of moles of the two titrants are equal
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Titration Curves
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[HA]=[A - ] [HA]=[OH - ]
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Drill: Calculate the pH of a buffer solution containing 0.50 M HX in 0.25 M KX. Ka = 2.5 x 10 -5
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Calculate the HCO 3 - to H 2 CO 3 ratio in blood with pH = 7.40 K a1 for H2CO3 = 4.4 x 10 -7
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150 ml of 0.10 M NaOH is added to 100.0 ml of 0.10 M H 2 CO 3. Calculate pH. K a1 for H2CO3 = 4.4 x 10 -7 K a2 for H2CO3 = 4.8 x 10 -11
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