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Lecture 14 Redox Titrations. aA nalyte + bT itrant  cC + dD products Requirements: -One reaction with integer coefficients a and b - The reaction is.

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Presentation on theme: "Lecture 14 Redox Titrations. aA nalyte + bT itrant  cC + dD products Requirements: -One reaction with integer coefficients a and b - The reaction is."— Presentation transcript:

1 Lecture 14 Redox Titrations

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3 aA nalyte + bT itrant  cC + dD products Requirements: -One reaction with integer coefficients a and b - The reaction is fast enough to perform the whole procedure in 20-40 min - Titrant solutions are stable and their concentrations can be easily established by the simple procedures -There is an easy way to establish the end point of titration (that is, the convenient indicator is available)

4 Titrant solutions are stable and their concentrations can be easily established by the simple procedures K 2 Cr 2 O 7 - no change in 30 years Primary standard -chemical compound that you can weigh and disolve to prepare solution of known concentration without standartization Requirements: - Purity of at least 99.9% - Stable and easy to purify if necessary - Convenient to weigh - Well soluble and stable in solution - non-toxic, non-expensive Secondary standard -solution of known concentration which was established by titration of the primary standard

5 Oxidants: Ce IV MnO 4 - Cr 2 O 7 2- BrO 3 - IO 3 - I 2 strong Weak, selective

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7 E min =0.77 + 0.06  3= 0.95 -E(SCE) E max =1.5-0.06  0.06=1.32 -E(SCE) Any potential in this range is be satisfactory 99.9% 100.1%

8 E min =0.77 + 0.06  3= 0.95 0.01 M K 2 Cr 2 O 7 [Cr 3+ ]=10 -2 M [Cr 2 O 7 2- ]=10 -5 M [H + ]=1 M E  1.3V 1.0 1.3 0.8 99.9% 100.1%

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10 E min = 0.77+0.03  3=0.86 -E(SCE) E max = 1.24-0.015  3=1.19 -E(SCE) @ 1M HCl

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12 BrO 3 - + 5Br - + 6H +  3Br 2 + 3H 2 O

13 Starch

14 I

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