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Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4
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2 There is no lecture on December 3rd There is an additional lecture on Friday 28 th November 16:00 – 19:00 HS C
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3 We have shown that: Hence: If we have two independent solutions, then we have ALL.
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4 The nonhomogeneous equation
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5 Lemma: Proof:
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6 We have shown that:
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7 Or equivalently:
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8 A simple geometric analogue Consider the equation: and the associated homogeneous equation: The set of solutions to the homogeneous equation is a linear space
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9 A simple geometric analogue x y y = 5x + = y = 5x +15 1 20
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10 Second Order equations with Constant coefficients.
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11 Second Order equations with Constant coefficients.
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12 Second Order equations with Constant coefficients.
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13 Second Order equations with Constant coefficients. {{ 0 0
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14 Second Order equations with Constant coefficients.
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15 Second Order equations with Constant coefficients. This can be worked out directly by looking at the complex solutions m 1 t, m 2 t or by using trigonometry to show that the two expressions above are solutions and are independent
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16 Second Order equations with Constant coefficients. Summary: The general solution of a second order equation is: (for arbitrary A,B)
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17 Second Order equations with Constant coefficients. Nonhomogeneous equations We need to find one particular solution The general solution will be: Consider the case c t is a constant Search, first, for a constant solution:
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18 Second Order equations with Constant coefficients. Nonhomogeneous equations Consider the case c t is a constant What if Search for a linear solution:
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19 Second Order equations with Constant coefficients. Nonhomogeneous equations Consider the case c t is a constant What if Search for a quadratic solution:
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20 Consider the case c t is a linear combination of terms of the form a t, t m Undetermined Coefficients Example: Look for a solution of the form:
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22 is a particular solution
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23 A general solution to the homogeneous equation Solve: A general solution of the equation is:
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24 Stability: In the long run, the solution should be independent of the initial conditions. The general solution of is: if : The system is stable.
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25 if 1 m
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