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Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4.

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Presentation on theme: "Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4."— Presentation transcript:

1 Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4 Mathe III Lecture 4

2 2 There is no lecture on December 3rd There is an additional lecture on Friday 28 th November 16:00 – 19:00 HS C

3 3 We have shown that: Hence: If we have two independent solutions, then we have ALL.

4 4 The nonhomogeneous equation

5 5 Lemma: Proof:

6 6 We have shown that:

7 7 Or equivalently:

8 8 A simple geometric analogue Consider the equation: and the associated homogeneous equation: The set of solutions to the homogeneous equation is a linear space

9 9 A simple geometric analogue x y y = 5x + = y = 5x +15 1 20

10 10 Second Order equations with Constant coefficients.

11 11 Second Order equations with Constant coefficients.

12 12 Second Order equations with Constant coefficients.

13 13 Second Order equations with Constant coefficients. {{ 0 0

14 14 Second Order equations with Constant coefficients.

15 15 Second Order equations with Constant coefficients. This can be worked out directly by looking at the complex solutions m 1 t, m 2 t or by using trigonometry to show that the two expressions above are solutions and are independent

16 16 Second Order equations with Constant coefficients. Summary: The general solution of a second order equation is: (for arbitrary A,B)

17 17 Second Order equations with Constant coefficients. Nonhomogeneous equations We need to find one particular solution The general solution will be: Consider the case c t is a constant Search, first, for a constant solution:

18 18 Second Order equations with Constant coefficients. Nonhomogeneous equations Consider the case c t is a constant What if Search for a linear solution:

19 19 Second Order equations with Constant coefficients. Nonhomogeneous equations Consider the case c t is a constant What if Search for a quadratic solution:

20 20 Consider the case c t is a linear combination of terms of the form a t, t m Undetermined Coefficients Example: Look for a solution of the form:

21 21

22 22 is a particular solution

23 23 A general solution to the homogeneous equation Solve: A general solution of the equation is:

24 24 Stability: In the long run, the solution should be independent of the initial conditions. The general solution of is: if : The system is stable.

25 25 if 1 m


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