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What Does the Likelihood Principle Say About Statistical Process Control? Gemai Chen, University of Calgary Canada July 10, 2006
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It is well know that given a random sample X 1, X 2, …, X n from, then is independent of and
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Therefore, inference for and can be done using and separately.
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From a statistical theory point of view, this supports the practice that process mean and variability are usually monitored by two different control charts.
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For this presentation, let’s consider the widely used X-bar chart and the S chart.
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Now let X denote a certain quality characteristic of a process, let denote the process mean and let denote the process standard deviation.
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Suppose that X ij, i = 1, 2, … and j = 1, …, n, are measurements of X arranged in sub-groups of size n with i indexing the sub-group number.
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We assume that X i1,…,X in is a random sample from a normal distribution with mean + a and standard deviation b , where a = 0 and b = 1 indicate that the process is in control.
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Define sample mean and sample variance by
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The 3-sigma X-bar chart plots the sample means against
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with a Type I Error probability 0.0027 when the process is in control. For the S chart, we use a version with probability control limits, where
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a probability 0.00135 is assigned to each tail so that the Type I Error probability is also 0.0027 when the process is in control.
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The joint behaviour of the (X-bar, S) combination judged by average run length (ARL) is summarized in the following table.
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a 0.00.51.02.0 b 0.254.8 1.1 0.5051.451.212.31.3 1.00185.430.74.51.6 1.507.35.22.71.6 2.002.32.11.71.4 ARL of (X-bar, S) Combination When n = 5
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Some efforts have been made to use one chart by combining two existing charts, one for the mean and one for the variability.
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For example, the Max chart by Chen & Cheng plots
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where
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Under the same in control ARL of 185.4, the Max chart has the identical ARL performance to the (X-bar,S) combination.
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Can we design a control chart which by nature is meant to monitor both mean and variability simultaneously?
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Here we report what we have tried. First, as any test of uniformity can be turned into a chart.
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a 0.00.51.02.0 b 0.25Inf54.5 1.2 1.0 0.50 8333.3 41.5 2.61.0 1.00185.229.95.61.1 1.5044.519.86.61.6 2.0021.113.96.72.1 ARL Based on Kolmogorov Test When n = 5
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a 0.00.51.02.0 b 0.25Inf 2083.3 1.3 1.0 0.50 50000 84.0 2.51.0 1.00185.226.04.61.1 1.5043.418.35.81.6 2.0022.314.16.52.1 ARL Based on Cramer-von Mises Test When n = 5
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a 0.00.51.02.0 b 0.25Inf 3.3 1.0 0.50 Inf 408.2 4.21.0 1.00185.222.33.71.1 1.5013.37.02.91.2 2.003.83.12.11.2 ARL Based on Anderson-Darling Test When n = 5
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It looks that the popular tests of uniformity do not lead to efficient monitoring of the mean and variability changes, especially when the variability of the process decreases.
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Next, we consider Fisher’s method of combining tests. Let
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Then
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a 0.00.51.02.0 b 0.25Inf 50000 1.0 0.50Inf 50000 35.31.0 1.00185.220.13.91.1 1.506.53.52.01.1 2.002.31.81.51.1 ARL Based on Fisher’s Test When n = 5
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We see that Fisher’s test leads to a chart that is better than the (X-bar, S) combination for monitoring mean changes and variability increases.
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However, this chart can hardly detect any variability decreases.
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Finally, we consider the likelihood ration test of the simple null H 0 : Mean and SD versus the composite alternative H 1 : Mean and/or SD .
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a 0.00.51.02.0 b 0.253.22.31.21.0 0.5027.616.14.01.0 1.00185.247.97.31.2 1.5015.89.13.71.3 2.003.32.92.11.3 ARL Based on Likelihood Ratio Test When n = 5
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We see that the likelihood ratio test leads to a chart that has more balanced performance monitoring the mean and variability changes than the (X-bar, S) combination or any of the cases considered.
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To understand better, let’s have a look at the likelihood ratio statistic
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Conclusion : Mean and standard deviation are functionally related under the normality assumption, even though and are statistically independent.
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