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CLT for Degrees of Random Directed Geometric Networks Yilun Shang Department of Mathematics, Shanghai Jiao Tong University May 18, 2008
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Context Background and Motivation Model Central limit theorems Degree distributions Miscellaneous
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(Static) sensor network Large-scale networks of simple sensors
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Static sensor network Large-scale networks of simple sensors Usually deployed randomly Use broadcast paradigms to communicate with other sensors
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Static sensor network Large-scale networks of simple sensors Usually deployed randomly Use broadcast paradigms to communicate with other sensors Each sensor is autonomous and adaptive to environment
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Static sensor network Sensor nodes are densely deployed
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Static sensor network Sensor nodes are densely deployed Cheap
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Static sensor network Sensor nodes are densely deployed Cheap Small size
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Communication Radio Frequency omnidirectional antenna directional antenna
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Communication Radio Frequency omnidirectional antenna directional antenna Optical laser beam need line of sight for communication
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An illustration
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Graph Models Random (directed) geometric network Scatter n points on R 2 (n large), X 1,X 2, …,X n, i.i.d. with density function f and distribution F Given a communication radius r n, two points are connected if they are at distance ≤r n.
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Random geometric network
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r
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Random directed geometric network Fix angle ∈ (0,2 ]. X n ={X 1,..,X n } i.i.d. points in R 2, with density f,distribution F. Let Y n ={Y 1,..,Y n } be a sequence of i.u.d. angles, let {r n } be a sequence tends to 0. G (X n,Y n,r n ) is a kind of random directed geometric network, where (X i, X j ) is an arc iff X j in S i =S(X i,Y i,r n ). D.,Petit,Serna, IEEE Trans. Mobi. Comp. 2003
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Random directed geometric network YiYi SiSi XiXi rnrn Each sensor X i covers a sector S i, defined by r n and with inclination Y i.
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Random directed geometric network G ( X n,Y n,r n ) is a digraph If x 5 is not in S 1, to communicate from x 1 to x 5 :
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Random directed geometric network
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Notations and basic facts For any fixed k ∈ N, define r n =r n (t) by nr n (t) 2 =t, for t>0. Here, t is introduced to accommodate the areas of sectors. For A in R 2, X is a finite point set in R 2 and x ∈ R 2, let X(A) be the number of points in X located in A, and X x =X ∪ {x}. For >0, let H be the homogeneous Poisson point process on R 2 with intensity. For k ∈ N and A is a subset of N, set (k)=P[Poi( )=k] and (A)=P[Poi( ) ∈ A].
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Notations and basic facts Let Z n (t) be the number of vertices of out degrees at least k of G ( X n,Y n,r n ), then Z n (t)=∑ n i=1 I {X n (S(X i,Y i,r n (t)))≥ k+1} Let W n (t) be the number of vertices of in degrees at least k of G ( X n,Y n,r n ), then W n (t)=∑ n i=1 I { # {X j ∈ X n |X i ∈ S(X j,Y j,r n (t))}≥ k+1}
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Central limit theorems Theorem
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Central limit theorems Theorem Suppose k is fixed. The finite dimensional distributions of the process n - 1/2 [Z n (t) - EZ n (t)], t>0 converge to those of a centered Gaussian process (Z ∞ (t),t>0) with E[Z ∞ (t)Z ∞ (u)]=∫ R 2 tf(x)/2 ([k, ∞))f(x)dx +
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Central limit theorems (1/4 2 ) ּ∫ 0 2 ∫ 0 2 ∫ R 2 ∫ R 2 g( z, f(x 1 ), y 1, y 2 ) ּ f 2 (x 1 )dz dx 1 dy 1 dy 2 - h(t) h(u), where g( z,, y 1, y 2 )= P[{H z (S(0,y 1,t 1/2 )) ≥k}∩{H 0 (S(z,y 2,u 1/2 ))≥k}] - P[H (S(0,y 1,t 1/2 ))≥ k] ּ P[H (S(z,y 2,u 1/2 )) ≥k ], and h(t)= ∫ R 2 { tf(x)/2 (k - 1) ּ tf(x)/2 + tf(x)/2 ([k, ∞))} f(x)dx.
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Central limit theorems Sketch of the proof Compute expectation Compute covariance Poisson CLT through a dependency graph argument Depoissionization
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Central limit theorems W n (t) k(n) tends to infinity X n −→P n, where P n ={X 1,..,X N n } is a Poisson process with intensity function n f(x). Here, N n is a Poisson variable with mean n. Corresponding central limit theorems are obtained
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Degree distributions For k ∈ N ∪ 0, let p(k) be the probability of a typical vertex in G (X n,Y n,r n ) having out degree k Theorem
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Degree distributions For k ∈ N ∪ 0, let p(k) be the probability of a typical vertex in G (X n,Y n,r n ) having out degree k Theorem p(k)=∫ R 2 tf(x)/2 (k) f(x)dx ( * )
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Degree distributions Example 1 f=I [0,1] 2 uniform
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Degree distributions Example 1 f=I [0,1] 2 uniform p(k)=exp( - t ּ t k /k! The out degree distribution is Poi( t )
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Degree distributions Example 2 f(x 1,x 2 )=(1/2 exp( - (x 1 2 +x 2 2 )/2) normal
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Degree distributions Example 2 f(x 1,x 2 )=(1/2 exp( - (x 1 2 +x 2 2 )/2) normal p(k)=4 t - exp( - t/4 ) ∑ k i=0 ( t/4 i - 1 /i! a skew distribution
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Degree distributions
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If f is bounded, the degree distribution will never be power law because of fast decay
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Degree distributions If f is bounded, the degree distribution will never be power law because of fast decay Given p(k)≥0, ∑ ∞ k=0 p(k)=1, it’s very hard to solve equation ( * ) for getting a f(x)
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Miscellaneous High dimension Angles not uniformly at random Dynamic model (Brownian, Random direction, Random waypoint, Voronoi, etc.)
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