Presentation is loading. Please wait.

Presentation is loading. Please wait.

Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Written.

Similar presentations


Presentation on theme: "Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Written."— Presentation transcript:

1 Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Written Ex. P 35.

2 2-1 Written Ex. P 34. Underline the hypothesis and box the conclusion. 1. If 3x – 7 = 32, then x = 13. 2. I can’t sleep if I am tired. 3. I’ll try if you will.

3 Underline the hypothesis and box the conclusion. 4. If, then is a right angle. 5. a + b = a implies b = 0. 6. x = - 5 only if x 2 = 25.

4 Rewrite each pair of conditionals as a biconditional. 7.If B is between A and C, then AB + BC = AC. If AB + BC = AC, then B is between A and C. 8.If, then is a straight angle. If is a straight angle, then. B is between A and C if and only if AB + BC = AC if and only if is a straight angle.

5 Write each biconditional as a pair of conditionals. 9. Points are collinear if and only if they all lie in one line. 10. Points lie in on plane if and only if they are coplanar. If points are collinear, then they all lie in one line. If all points lie in one line, then they are collinear. If points lie in on plane, then they are coplanar. If points are coplanar, then they lie in on plane.

6 Provide a counter example to show that each statement is false. 11. If ab < 0, then a < 0. 12. If n 2 = 5n, then n = 5. 13. If point G is on, then G is on. When trying these algebraic us negative numbers, 1, 0, 1, 10, and fractions between 0 and 1 as test values. Let a = 1 and b = -1 (-1)(1) 0 n = 0 n 2 = 5n but n is not = 5 ABG

7 Provide a counter example to show that each statement is false. 14. If xy > 5y, then x > 5. 15. If a four-sided figure has 4 right angles, then it has four congruent sides. 15. If a four-sided figure has four congruent sides, then it has 4 right angles. Let x = - 1 and y = -1 (-1)(-1) > 5(-1) 1 > -5 But – 1 is not > 5 A rectangle. Diamond or rhombus.

8 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 17. If x = - 6, then. If, then x = - 6. True False x could = + 6

9 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 18. If, then x = - 2. False x could = + 2 Quadratic equations have 2 roots. 18. If x = - 2, then. True

10 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 19. If b > 4, then 5b > 20. True If 5b > 20, then b > 4. True

11 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 20. If, then is not obtuse. True If is not obtuse, then. False T could = 90, 80,..

12 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 21. If Pam lives in Chicago, then she lives in Illinois. True If Pam lives in Illinois, then she lives in Chicago. False, there are a lot of other cities in Illinois.

13 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 22. If, then. If, then. True True: all definitions are reversible.

14 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 23. If, then. 23. if. True False a could be -10.

15 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 24. x = 1 only if. If then x = 1. Note “only if” is not the same as “if”. Only if means “then” False x could be 0. True

16 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 25. n > 5 only if n > 7. Note “only if” is not the same as “if”. Only if means “then” If n > 7, then n > 5. False n could be 6. True

17 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 26. ab = 0 implies that a = 0 or b = 0. a = 0 or b = 0 implies that ab = 0. True

18 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 27. If points D, E, and F are collinear, then DE + EF = DF. D FE If DE + EF = DF, then points D, E, and F are collinear. D E F False Counterexample False

19 Tell whether each statement is true or false. Then write the converse and tell whether the converse is true of false. 28. P is the midpoint of implies that GH = 2 PG. True GH = 2 PG. implies that P is the midpoint of False Counterexample P HG 1 2

20 29. Write a definition of congruent angles as a biconditional. 30. Write a definition of a right angle as a biconditional. is a right angle if and only if

21 C’est fini. Good day and good luck.


Download ppt "Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Written."

Similar presentations


Ads by Google