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REU 2004 Population Models Day 2 Predator Prey. REU’04—Day 2 Today we have 2 species; one predator y(t) (e.g. wolf) and one its prey x(t) (e.g. hare)

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Presentation on theme: "REU 2004 Population Models Day 2 Predator Prey. REU’04—Day 2 Today we have 2 species; one predator y(t) (e.g. wolf) and one its prey x(t) (e.g. hare)"— Presentation transcript:

1 REU 2004 Population Models Day 2 Predator Prey

2 REU’04—Day 2 Today we have 2 species; one predator y(t) (e.g. wolf) and one its prey x(t) (e.g. hare)

3 Actual Data

4 Model Want a DE to describe this situation dx/dt= ax-bxy = x(a-by) dy/dt=-cx+dxy = y(-c+dx) Could get rid of __________constants 3

5 Called Lotka-Volterra Equation, Lotka & Volterra independently studied this post WW I. Fixed points: (0,0), (c/d,a/b)

6 The ANSWER:

7 Solution vs time

8 What are you going to do? Try to use analysis to argue that this is indeed the phase portrait.

9 OK what now? 3 species food chain! – x = worms; y= robins; z= eagles dx/dt = ax-bxy dy/dt= -cy+dxy-eyz dz/dt= -fz+gyz

10 New tools Invariant sets & trapping regions!


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