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Chapter 5 Digital Image Processing Fundamentals. Learning Goals The human visual system Digitizing images Display of Images.

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Presentation on theme: "Chapter 5 Digital Image Processing Fundamentals. Learning Goals The human visual system Digitizing images Display of Images."— Presentation transcript:

1 Chapter 5 Digital Image Processing Fundamentals

2 Learning Goals The human visual system Digitizing images Display of Images

3 Trading an eye for an ear

4 An eye is a Multi-mega pixel camera It has a lens (adjustable zoom) It has an automatic f-stop (iris 2-8 mm) It has a sensor plane (100 million pixels) The sensor has a transfer function senstive to mesopic range; 380 to about 700 nm

5 The eyes have a USB2 data rate! 250,000 neurons in the optic nerve variable voltage output on EACH nerve 17.5 million neural samples per second 12.8 bits per sample 224 Mbps, per eye (a 1/2 G bps system!). Compression using lateral inhibition between the retinal neurons

6 Response curves Eye has Gaussian response to light. Gives rise to biologically motivated image processing

7 Quantization of an Image Computers use digital cameras -> quantization

8 Sampling an Image

9 Sampling=convolution w pulse train

10 Quantization Error is visible

11 Displays Color Monitors are made for people

12 Chapter 6-7 Opening and Saving Images

13 Chapter 8 Convolution with a kernel, g(x)

14 Region of Support The region of support is defined as that area of the.kernel which is non-zero linear convolution:=signal has infinite extent but kernel has finite support If function has finite region of support we have compact support

15 Real images have finite region of support But we treat them as periodic and infinite! We repeat kernels so that they have the same period as the images. We call this cyclic convolution.

16 Convolution in 2D

17 Avoid the Mod op

18 What is wrong with avoiding the mod op? How do I find the center of the kernel?

19 Cyclic Convolution

20 Implementing Convolution for(int y = 0; y < height; y++) { for(int x = 0; x < width; x++) { sum = 0.0; for(int v = -vc; v <= vc; v++) for(int u = -uc; u <= uc; u++) sum += f[cx(x-u) ][cy(y-v)] * k[ u+uc][v+vc]; if (sum < 0) sum = 0; if (sum > 255) sum = 255; h[x][y] = (short)sum; }

21 What happens to the image if you ignore the wrap?

22 Cyclic Convolution keeps the edges

23 Can you think of a better way to implement convolution? Keep the edges! Don’t use the mod operation. How about growing the image by the size of the kernel*2?

24 Convolution is slow, how can I speed it up? JAI! FFT!? Other ideas?

25


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