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Published byAugusta Harrell Modified over 9 years ago
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Chapter 8 The Operational Amplifier (Part I) ~ Using PSpice
The Ideal Op Amp Noninverting Ideal Op Amp Op Amp Giving Voltage Difference Output Frequency Response of the Op Amp Using a Subcricuit for the Op Amp Op Amp differentiator Circuit Op Amp Integrator Circuit Response to Unit Step Function Double Op Amp Circuit
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The Ideal Op Amp High input resistance, zero output resistance, and high voltage gain
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The Ideal Inverting Op Amp
Negative feedback connection PSpice version of the circuit
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Input File Ideal Operational Amplifier VS 1 0 1V E 3 0 0 2 200E3
RI 2 0 1G R K R K .OP .OPT nopage .TF V(3) VS .END
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Run the Analysis and Verify
Run V(3)/VS=-9.999 Verify Vo/Vs=-R2/R1=-10K/1K=-10
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Noninverting Ideal Op Amp
Noninverting ideal op amp model
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Input File Ideal Operational Amplifier, Noninverting VS 1 0 1V
E E3 RI 1 2 1G R k R k .op .opt nopage .TF V(3) VS .END
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Run and Verify V(3)/VS=10, Vo/Vs=1+R2/R1=1+9K/1K=10
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Op Amp Giving Voltage Difference Output
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Input File Op Amp Giving Voltage Difference Output VA 1 0 3V
VB V E E3 RI 2 3 1G R k R k R k R k .OP .OPT nopage .TF V(5) VB .END
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Run and Verify Verify that Vo=R2(Vb-Va)/R1=10k(10v-3v)/5k=14v V(5)=14V
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Frequency Response of the Op Amp
Model for the frequency response of an op amp fc=10Hz
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Input File Op Amp Model with 3-dB frequency at 10 Hz for Open-Loop Gain VS 2 0 AC 1mV EG E5 E RI k RO R k RL k RIN 1 2 1MEG C uF .AC DEC MEG .PROBE .END
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Run and View Output
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Modify Input File Op Amp Model with 3-dB frequency at 10 Hz for Open-Loop Gain VS 2 0 AC 1mV EG E5 E RI k RO R k R k RL k RIN 1 2 1MEG C uF .AC DEC MEG .PROBE .END
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Parameter Setting
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Run and View Output
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Using a Subcircuit for the Op Amp
.subckt opamp m p vo eg a 0 p m 1e5 e c 0 b 0 1 rin m p 1meg ril a b 1k c b uF rol c vo 50 .ends
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Op Amp Analysis Using Subcircuit
VS 2 0 AC 1mV R k R k X opamp .AC DEC MEG .PROBE .subckt opamp m p vo eg a 0 p m 1e5 e c 0 b 0 1 rin m p 1meg ril a b 1k c b uF rol c vo 50 .ends .END
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Op Amp Differentiator Circuit
Vo=-dv/dt
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Input File Differentiator Circuit V 1 0 PWL (0, 0 1s, 1V 2s, 0)
C 1 2 2F R X iop .subckt iop m p vo ri m p 1meg e vo 0 p m 2e5 .ends .TRAN 0.05s 2s .PROBE .END
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Run and View Outputs V(1) Vo
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Op Amp Integrator Circuit
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Input File Integrator Circuit
V 1 0 PWL ( ms, -1V 1s, -1V ms, 0V 2s, 0V ms, 1V 3s, 1V) R C 2 3 2 X iop .subckt iop m p vo ri m p 1meg e vo 0 p m 2e5 .ends .TRAN 0.05s 3s .PROBE .END
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Run and View Output V(1) Vo
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Response to Unit Step Function
By definition, it remains at zero volts until t=0, and from that time forward it is 1V.
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Response of first-order circuit to unit step function
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Input File Vo(t)=(3-2e-4t)u(t) Response to Unit Step Function
Vs 1 0 PWL (0, 0 1us, 1v 5s, 1v) C R 2 3 2 R X iop .subckt iop m p vo ri m p 1meg e vo 0 p m 2e5 .ends .TRAN 0.05s 3s .PROBE .END Vo(t)=(3-2e-4t)u(t)
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Run and View Outputs
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Double Op Amp Circuit
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Input File Double Op Amp Circuit for Gain-Bandwidth Analysis
VS1 2 0 AC 1mV R k R k X opamp VS2 5 0 AC 1mV R k R k X OPAMP .AC DEC MEG .PROBE .subckt opamp m p vo eg a 0 p m 1e5 e c 0 b 0 1 rin m p 1meg ril a b 1k c b uF rol c vo 50 .ends .END
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Run and View Outputs OP Amp 1 OP Amp 2
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Chapter 8 The Operational Amplifier (Part II) ~ Using Capture
Noninverting Ideal Op Amp Op Amp for Voltage-Difference Output Frequency Response of the Op Amp Frequency Response of the uA741 The uA741 as a Level Detector
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Noninverting Ideal Op Amp
Ideal op amp in Capture Ideal op amp
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Run and View Output
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Op Amp for Voltage-Difference Output
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Run and View Output
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Frequency Response of the Op Amp
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Op amp model for fc=10Hz
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Simulation Setting
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Run and View Output 20*log10(V(5)/V(2))
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DB(V(5)/V(2))
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Frequency Response of the uA741
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Run and View Output Frequency response of the uA741
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The uA741 as a Level Detector
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V1 (VPWL) Settings (0v, 0s), (3v, 0.2s), (5v, 0.4s), (-5v, 0.6s), (-3v, 0.8v), (0v, 1s)
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Simulation Settings
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Run and View Output V(1) input V(5) Output
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Question & Answer
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