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Can the Numerical Range of a Nilpotent Operator be a Disc? Akio Arimoto Department of Mathematics Musashi Institute of Technology.

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Presentation on theme: "Can the Numerical Range of a Nilpotent Operator be a Disc? Akio Arimoto Department of Mathematics Musashi Institute of Technology."— Presentation transcript:

1 Can the Numerical Range of a Nilpotent Operator be a Disc? Akio Arimoto Department of Mathematics Musashi Institute of Technology

2 : nilpotent linear operator with norm 1, i.e. Assumption 1: is a disc with the radius and the center at origin. Assumption 2: Conclusion : for some Assertion in this talk

3 Notation : Numerical Radius : Numerical range : a unit ball in a Hilbert space

4 Known results For a 2x2 matrix with eigenvalues is an elliptical disc with as foci minor axis major axis Chi-Kwong Li, Proceeding of AMS, 1996, vol 124, no.7, 1985-1986

5 Toeplitz- Hausdorff ‘s Theorem is a convex set in the Gauss plane. O.Toeplitz, Das algebraische Analogon zu einem Satz von Fejer, Math.Z.2(1918),187-197 F.Hausdorff, Der Wertvorat einer Bilinearform, Math.Z.(1919),314-316

6 Some Examples Ex.1.

7 Ex.2.

8 Ex.3.

9 Ex.4.

10 Ex.5.

11 Ex.6. My undergraduate student Aono found the following example. Counter example for Karaev’s paper(2004,Proceedings of AMS)

12

13 Ex.6. shows that nilpotency is not a sufficient condition for to be a disc. Indeed This is my motivation to start this study.

14 Haargerup and de la Harpe [HH] shown that for a nilpotent This is a consequence of a Fejer theorem :

15 Suppose and that there exists a unit vector with Let be the linear span of Theorem A.[HH p.375] satisfies

16 Thenis an n- dimensional subspace of and the restriction ofto is unitarily equivalent to the n-dimensional shift on We can restrict our problem to a finite matrix case even for the infinite dimensional space!

17 Lemma is a disc with the radius and the center at zero. See example 2

18 Proof of the Lemma

19

20 is unitary.

21

22 for where must be a discso because of Hausdorff-Toeplitz theorem.

23 If we take a unit vector The Haagerup - de la Harpe’s inequality must be the equality Q.E.D. we have

24 Theorem B.[HH,p.374] Let Ifthen

25 Theorem 1. (by Arimoto) is a disc.

26 Proof of Theorem For some ( from Theorem B)

27 are linearly independent, so

28 we now define by using the same

29 where we used

30 for any θ Apply again the Toeplitz-Hausdorff theorem, is a disc with the radius

31 References [HH] Uffe Haagerup and Pierre de la Harpe, The Numerical Radius of a Nilpotent Operator on a Hilbert Space, Proceedings of Amer.Math.Soc. 115,(1992) [K] Mubariz T. Karaev, The Numerical Range of a Nilpotent Operator on a Hilbert Space, Proc. Amer.Math.Soc.,2004 [Wu]Pey-Yuan Wu( 呉培元) Polygons and Numerical ranges,Mathematical Monthly,107(2000)pp.528-540 [Wu-Gau]P-Y.Wu and Hwa-Long Gau( 高) Numerical Range of S(Φ),Linear and Multilinear Algebra 45(1998),pp.49-73

32 Poncelet’s theorem Algebraic curves of order 2 (examples: ellipes)

33 Poncelet’s theorem If for some Then starting from any other on

34 nxn matrix then being unit circle center 0 and has Poncelet ‘s property

35 Starting from any point on We have an n+1-gon Also see Hwa-Long Gau and Pei Yuan Wu Numerical range and Poncelet property Taiwanese J.Math, vol.7,no2.173-193(2003)


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