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Lecture 7 Dustin Lueker
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2 Point Estimate ◦ A single number that is the best guess for the parameter Sample mean is usually at good guess for the population mean Interval Estimate ◦ Point estimator with error bound A range of numbers around the point estimate Gives an idea about the precision of the estimator The proportion of people voting for A is between 67% and 73% STA 291 Winter 09/10 Lecture 7
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3 Inferential statement about a parameter should always provide the accuracy of the estimate ◦ How close is the estimate likely to fall to the true parameter value? Within 1 unit? 2 units? 10 units? ◦ This can be determined using the sampling distribution of the estimator/sample statistic ◦ In particular, we need the standard error to make a statement about accuracy of the estimator STA 291 Winter 09/10 Lecture 7
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4 Range of numbers that is likely to cover (or capture) the true parameter Probability that the confidence interval captures the true parameter is called the confidence coefficient or more commonly the confidence level ◦ Confidence level is a chosen number close to 1, usually 0.90, 0.95 or 0.99 ◦ Level of significance = α = 1 – confidence level STA 291 Winter 09/10 Lecture 7
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5 To calculate the confidence interval, we use the Central Limit Theorem ◦ Substituting the sample standard deviation for the population standard deviation Also, we need a that is determined by the confidence level Formula for 100(1-α)% confidence interval for μ STA 291 Winter 09/10 Lecture 7
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90% confidence interval ◦ Confidence level of 0.90 α=.10 Z α/2 =1.645 95% confidence interval ◦ Confidence level of 0.95 α=.05 Z α/2 =1.96 99% confidence interval ◦ Confidence level of 0.99 α=.01 Z α/2 =2.576 6STA 291 Winter 09/10 Lecture 7
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This interval will contain μ with a 100(1-α)% confidence ◦ If we are estimating µ, then why it is unreasonable for us to know σ? Thus we replace σ by s (sample standard deviation) This formula is used for large sample size (n≥30) If we have a sample size less than 30 a different distribution is used, the t-distribution, we will get to this later 7STA 291 Winter 09/10 Lecture 7
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Compute a 95% confidence interval for μ if we know that s=12 and the sample of size 36 yielded a mean of 7 8STA 291 Winter 09/10 Lecture 7
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“Probability” means that in the long run 100(1-α)% of the intervals will contain the parameter ◦ If repeated samples were taken and confidence intervals calculated then 100(1-α)% of the intervals will contain the parameter For one sample, we do not know whether the confidence interval contains the parameter The 100(1-α)% probability only refers to the method that is being used 9STA 291 Winter 09/10 Lecture 7
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Incorrect statement ◦ With 95% probability, the population mean will fall in the interval from 3.5 to 5.2 To avoid the misleading word “probability” we say that we are “confident” ◦ We are 95% confident that the true population mean will fall between 3.5 and 5.2 11STA 291 Winter 09/10 Lecture 7
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Changing our confidence level will change our confidence interval ◦ Increasing our confidence level will increase the length of the confidence interval A confidence level of 100% would require a confidence interval of infinite length Not informative There is a tradeoff between length and accuracy ◦ Ideally we would like a short interval with high accuracy (high confidence level) 12STA 291 Winter 09/10 Lecture 7
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The width of a confidence interval ◦ as the confidence level increases ◦ as the error probability decreases ◦ as the standard error increases ◦ as the sample size n decreases Why? 13STA 291 Winter 09/10 Lecture 7
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Start with the confidence interval formula assuming that the population standard deviation is known Mathematically we need to solve the above equation for n 14STA 291 Winter 09/10 Lecture 7
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15 About how large a sample would have been adequate if we merely needed to estimate the mean to within 0.5, with 95% confidence? Assume Note: We will always round the sample size up to ensure that we get within the desired error bound. STA 291 Winter 09/10 Lecture 7
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To account for the extra variability of using a sample size of less than 30 the student’s t- distribution is used instead of the normal distribution 16STA 291 Winter 09/10 Lecture 7
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t-distributions are bell-shaped and symmetric around zero The smaller the degrees of freedom the more spread out the distribution is t-distribution look much like normal distributions In face, the limit of the t-distribution is a normal distribution as n gets larger STA 291 Winter 09/10 Lecture 717
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Need to know α and degrees of freedom (df) ◦ df = n-1 α=.05, n=23 ◦ t α/2 = α=.01, n=17 ◦ t α/2 = α=.1, n=20 ◦ t α/2 = 18STA 291 Winter 09/10 Lecture 7
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A sample of 12 individuals yields a mean of 5.4 and a variance of 16. Estimate the population mean with 98% confidence. 19STA 291 Winter 09/10 Lecture 7
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The sample proportion is an unbiased and efficient estimator of the population proportion ◦ The proportion is a special case of the mean 20STA 291 Winter 09/10 Lecture 7
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As with a confidence interval for the sample mean a desired sample size for a given margin of error (ME) and confidence level can be computed for a confidence interval about the sample proportion ◦ This formula requires guessing before taking the sample, or taking the safe but conservative approach of letting =.5 Why is this the worst case scenario? (conservative approach) 21STA 291 Winter 09/10 Lecture 7
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ABC/Washington Post poll (December 2006) ◦ Sample size of 1005 ◦ Question Do you approve or disapprove of the way George W. Bush is handling his job as president? 362 people approved Construct a 95% confidence interval for p What is the margin of error? 22STA 291 Winter 09/10 Lecture 7
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If we wanted B=2%, using the sample proportion from the Washington Post poll, recall that the sample proportion was.36 ◦ n=2212.7, so we need a sample of 2213 What do we get if we use the conservative approach? 23STA 291 Winter 09/10 Lecture 7
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