Download presentation
1
Building a System of Geometry Knowledge 2.4
2
Algebraic properties
3
Addition Property Subtraction Property If a = b , then a + c = b + c
Homework
4
Multiplication Property
If a = b , then ac = bc Division Property If a = b and c ≠ 0 , then a/c = b/c Homework
5
Substitution Property
If a = b, you may replace a with b in any true equation that has a in it, and the resulting equation will still be true. Homework
6
Equivalence Properties
Reflexive Property for any number a, a = a Symmetric Property if a = b , b = a Transitive Property if a = b and b = c, then a = c Homework
7
Overlapping SegmentsTheorem
Overlapping segment theorem: Given a segment with points A, B, C, and D arranged as shown, the following statements are true: If AB = CD then AC = BD If AC = BD then AB = CD Homework
8
Overlapping Angles Theorem
Given AED with points B and C in its interior as shown, the following statements are true: 1. If mAEB = mCED, then mAEC = mBED. 2. If mAEC = mBED, then mAEB = mCED. Homework
9
Equality and Congruency
For all these properties, you can change the equal sign to a congruent sign and they are still true. In the Reasons column of the proof write Definition of Congruence. Homework
10
Two Column Proof Homework Statement Reason
Given: AB = CD Prove: AC = BD Statement Reason 1. AB = CD 1. Given 2. AB + BC = BC + CD 2. Addition Property 3. AB + BC = AC 3. Segment Addition Postulate 4. BC + CD = BD 4. Segment Addition Postulate 5. AC = BD 5. Substitution Property Homework
11
Two Column Proof Homework Statement Reason
Given: a = b Prove: a + c = b + c Statement Reason 1. a = b 1. Given 2. a + c = a + c 2. Reflexive Property of Equality 3. a + c = b + c 3. Substitution Property of Equality Homework
12
Two Column Proof Homework Statement Reason
Given: 2x − 5 = Prove: x = 4 Statement Reason 1. 2x − 5 = 3 1. Given 2. 2x − = 3 + 5 2. Addition Property of Equality 3. 2x = 8 3. Simplify 4. 2x ÷ 2 = 8 ÷ 2 4. Division Property of Equality 5. x = 4 5. Simplify Homework
13
Two Column Proof Homework Statement Reason Given: B C Prove: x = 7
2. mB = mC 2. Definition of Congruence 3. 5x + 12 = 47 3. Substitution Property of Equality 4. 5x = 35 4. Subtraction Property of Equality 5. x = 7 5. Division Property of Equality Homework
14
Two Column Proof Homework Statement Reason Given: m1 + m3 = 180
Prove: 1 2 Statement Reason 1. m1 + m3 = 180 1. Given 2. m2 + m3 = 180 2. Linear Pair Property 3. m1 + m3 = m2 + m3 3. Substitution Property of Equality 4. m1 = m2 4. Subtraction Property of Equality 5. 1 2 5. Definition of Congruence Homework
15
Two Column Proof Homework Statement Reason Given: mHGK = mJGL
Prove: 1 3 Statement Reason 1. mHGK = mJGL 1. Given 2. m∠HGK = m∠1 + m∠2 2. Angle Addition Postulate 3. m∠JGL = m∠3 + m∠2 3. Angle Addition Postulate 4. m∠1 + m∠2 = m∠3 + m∠2 4. Substitution Property of Equality 5. m∠1 = m∠3 5. Subtraction 6. ∠1 ∠3 6. Definition of Congruence Homework
16
Given: PQ = 2x + 5 QR = 6x – 15 PR = 46 Prove: x = 7
Two Column Proof Given: PQ = 2x QR = 6x – PR = Prove: x = 7 P Q R Statement Reason 1. PQ = 2x + 5, QR = 6x – 15, PR = 46 1. Given 2. PQ + QR = PR 2. Segment Addition Postulate 3. 2x x – 15 = 46 3. Substitution Property of Equality 4. 8x – 10 = 46 4. Simplify 5. 8x = 56 5. Addition Property of Equality Homework 6. x = 7 6. Division Property of Equality
17
Two Column Proof Homework Statement Reason PR PR
Given: Q is the midpoint of PR. Prove: PQ = and QR = 2 2 Statement Reason 1. Q is midpoint of PR 1. Given 2. PQ = QR 2. Definition of midpoint 3. PQ + QR = PR 3. Segment Addition Postulate 4. QR + QR = PR & PQ + PQ =PR 4. Substitution Property of Equality 5. 2QR = PR PQ = PR 5. Simplify PR 2 6. Division Property of Equality Homework 6. QR = PQ =
18
Two Column Proof Homework Statement Reason
Given: 2(3x + 1) = 5x Prove: x = 12 Statement Reason 1. 2(3x + 1) = 5x + 14 1. Given 2. 6x + 2 = 5x + 14 2. Distributive property 3. x + 2 = 14 3. Subtraction Property of Equality 4. x = 12 4. Subtraction Property of Equality Homework
19
Two Column Proof Homework Statement Reason
Given: 55z – 3(9z + 12) = – Prove: z = –1 Statement Reason 1. 55z – 3(9z + 12) = – 64 1. Given 2. 55z – 27z – 36 = – 64 2. Distributive Property 3. 28z – 36 = – 64 3. Simplify 4. 28z = –28 4. Addition Property of Equality 5. z= – 1 5. Division Property of Equality Homework
20
Summary of Properties Homework
21
Assignment Geometry: 2.4A and 2.4B Section
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.