Download presentation
Presentation is loading. Please wait.
Published byEthel Morris Modified over 9 years ago
1
Lab Notebooks Courtesy of Pleasant Valley High School Chemistry
2
Title Determination of Molar Mass of an Unknown by Freezing Point Depression Joe E. Student Partners: Ima Dude and Fairly Shallow 01-11-02
3
Purpose The molar mass of an unknown substance will be determined by freezing point depression in a solution of benzophenone. Using the known freezing point depression constant of 9.80 °C/m for benzophenone, the molality of the mixture containing the unknown can be determined using the equation ΔT f = k f m.
4
Experimental Setup Ring & Stand Temperature Probe Reaction Tube Water Bath
5
Data
6
Analysis Calculations Mass of Benzophenone Sample Mass of Benzophenone Sample = Mass Test Tube and Benzophenone - Mass Test Tube Mass of Benzophenone Sample = 48.764 g - 38.362 g Mass of Benzophenone Sample = 10.402 g Mass of Unknown Solute Mass of Unknown Solute = Mass Test Tube, Benzophenone, and Unknown - Mass Test Tube and Benzophenone Mass of Unknown Solute = 49.649 g - 48.764 g Mass of Unknown Solute = 0.985 g Freezing Point Depression (ΔΔTf) Freezing Point Depression = Benzophenone Freezing Point - Mixture Freezing Point ΔTf = 48.2 °C - 38.0 °C ΔTf = 10.2 °C Molality of the Mixture (m) ΔTf = kf m m = ΔTf / kf m = 10.2 °C / 9.80 °C/m m = 1.04 moles solute / kg solvent Moles of Unknown in Mixture Moles of Unknown = Mass Benzophenone x molality of solution Moles of Unknown = 10.402 g x 1.04 moles unknown / 1000 g benzophenone Moles of Unknown = 0.0108 moles unknown Molar Mass of Unknown Molar Mass of Unknown = Mass Unknown / Moles Unknown Molar Mass of Unknown = 0.985 g Unknown / 0.0108 moles Unknown Molar Mass of Unknown = 91.1 g / mole
7
Analysis
8
Conclusion This experiment used freezing point depression in a solution of benzophenone to determine the molar mass of an unknown substance. When a solute is dissolved in the pure liquid, and the temperature is dropped to the freezing point of the pure liquid, the liquid will not freeze. The solute particles disrupt the liquid molecules from settling down into an orderly solid array. The system must get colder, & lose more energy, before the solvent freezes. By using the equation for freezing point depression and the number of particles in solution the molar mass of the unknown solute was found to be 91.1 g / mole. The accuracy of the calculated molar mass is limited by the accuracy of the temperature and mass measurements, however, far more significant errors arise as a result of visually estimating the beginning and ending points for freezing. The accepted value is given as 98.5 g/mole, 7.5 g/mole greater than our calculated molar mass. This would be an error of almost 10% by the equation.
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.