Presentation is loading. Please wait.

Presentation is loading. Please wait.

Saeed Darvish Pazoki – MCSE, CCNA IP Subnetting 1.

Published byJane Harrell Modified over 9 years ago

Similar presentations

Presentation on theme: "Saeed Darvish Pazoki – MCSE, CCNA IP Subnetting 1."— Presentation transcript:

1 Saeed Darvish Pazoki – MCSE, CCNA IP Subnetting 1

2 Calculate Networks 2

3 Subnetting Examples Number of networks Process: 1. Determine The number of Networks and Convert to Binary 2. Reserve Bits in Subnet Mask and Find the INCREMENT 3. Use Increments to find the networks 3

4 Subnetting Examples Number of networks Class C Example #1: 198.200.100.0 Mask: 255.255.255.0 Required networks: 5 Binary: 0 0 0 0 0 1 0 1  3 bits Required Mask: 11111111.1111111.11111111.11100000  255.255.255.224 Increments Number: 32 (128 64 32 16 8 4 2 1) Networks: 198.200.100.0 198.200.100.32 198.200.100.64 198.200.100.96 198.200.100.128 198.200.100.160 198.200.100.192 198.200.100.224 4

5 Subnetting Examples Number of networks Class C Example #2 : 198.200.100.0 Mask: 255.255.255.0 Required networks: 12 Binary: 0 0 0 0 1 1 0 0  4 bits Required Mask: 11111111.1111111.11111111.11110000  255.255.255.240 Increments Number: 16 (128 64 32 16 8 4 2 1) Networks: 198.200.100.0 198.200.100.16 198.200.100.32 198.200.100.48. 198.200.100.208 198.200.100.224 198.200.100.240 5

6 Subnetting Examples Number of networks Class C Example #3 : 198.200.100.0 Mask: 255.255.255.0 Required networks: 60 Binary: 0 0 1 1 1 1 1 0  6 bits Required Mask: 11111111.1111111.11111111.11111100  255.255.255.252 Increments Number: 4 (128 64 32 16 8 4 2 1) Networks: 198.200.100.0 198.200.100.4 198.200.100.8 198.200.100.12. 198.200.100.244 198.200.100.248 198.200.100.252 6

7 Subnetting Examples Number of networks Class B Example #1 : 180.64.0.0 Mask: 255.255.0.0 Required networks: 30 Binary: 0 0 0 1 1 1 1 0  5 bits Required Mask: 11111111.1111111.11111000.00000000  255.255.248.0 Increments Number: 8 (128 64 32 16 8 4 2 1) Networks: 180.64.0.0 180.64.8.0 180.64.16.0 180.64.24.0. 180.64.232.0 180.64.240.0 180.64.248.0 7

8 Subnetting Examples Number of networks Class B Example #2 : 180.64.0.0 Mask: 255.255.0.0 Required networks: 100 Binary: 0 1 1 0 0 1 0 0  7 bits Required Mask: 11111111.1111111.11111110.00000000  255.255.254.0 Increments Number: 2 (128 64 32 16 8 4 2 1) Networks: 180.64.0.0 180.64.2.0 180.64.4.0 180.64.6.0. 180.64.250.0 180.64.252.0 180.64.254.0 8

9 Subnetting Examples Number of networks Class B Example #3 : 180.64.0.0 Mask: 255.255.0.0 Required networks: 280 Binary: 1 0 0 1 0 1 1 0 0  9 bits Required Mask: 11111111.1111111.11111111.10000000  255.255.255.128 Increments Number: 128 (128 64 32 16 8 4 2 1) Networks: 180.64.0.0 180.64.0.128 180.64.1.0 180.64.1.128 180.64.2.0 180.64.2.128. 180.64.254.0 180.64.254.128 180.64.255.0 180.64.255.128 9

10 Subnetting Examples Number of networks Class A Example #1 : 60.0.0.0 Mask: 255.0.0.0 Required networks: 500 Binary: 1 0 0 1 0 1 1 0 0  9 bits Required Mask: 11111111.1111111.10000000.00000000  255.255.128.0 Increments Number: 128 (128 64 32 16 8 4 2 1) Networks: 60.0.0.0 60.0.128.0 60.1.0.0 60.1.128.0 60.2.0.0 60.2.128.0. 60.254.0.0 60.254.128.0 60.255.0.0 60.255.128.0 10

11 Subnetting Examples Number of networks Class A Example #1 : 60.0.0.0 Mask: 255.0.0.0 Required networks: 1000 Binary: 1 1 1 1 1 0 1 0 0 0  10 bits Required Mask: 11111111.1111111.11000000.00000000  255.255.192.0 Increments Number: 64 (128 64 32 16 8 4 2 1) Networks: 60.0.0.0 60.0.64.0 60.0.128.0 60.0.192.0 60.1.0.0 60.1.64.0 60.1.128.0 60.1.192.0. 60.255.0.0 60.255.64.0 60.255.128.0 60.255.192.0 11

12 Calculate Hosts 12

13 Subnetting Examples Number of Hosts Process: 1. Determine The number of Hosts and Convert to Binary 2. Reserve Bits in Subnet Mask and Find the INCREMENT 3. Use Increments to find the networks 13

14 Subnetting Examples Number of Hosts Class C Example #1: 198.200.100.0 Mask: 255.255.255.0 Required hosts: 50 Binary: 0 0 1 1 0 0 1 0  6 bits Required Mask: 11111111.1111111.11111111.11000000  255.255.255.192 Increments Number: 64 (128 64 32 16 8 4 2 1) Networks: 198.200.100.0 (198.200.100.1 – 198.200.100.62) 198.200.100.64 (198.200.100.65 – 198.200.100.126) 198.200.100.128 (198.200.100.129 – 198.200.100.190) 198.200.100.192 (198.200.100.193 – 198.200.100-254) 14

15 Subnetting Examples Number of Hosts Class C Example #1: 198.200.100.0 Mask: 255.255.255.0 Required hosts: 100 Binary: 0 1 1 0 0 1 0 0  7 bits Required Mask: 11111111.1111111.11111111.10000000  255.255.255.128 Increments Number: 128 (128 64 32 16 8 4 2 1) Networks: 198.200.100.0 (198.200.100.1 – 198.200.100.126) 198.200.100.128 (198.200.100.129 – 198.200.100.254) 15

16 Subnetting Examples Number of Hosts Class B Example #1: 180.200.0.0 Mask: 255.255.0.0 Required hosts: 100 Binary: 0 1 1 0 0 1 0 0  7 bits Required Mask: 11111111.1111111.11111111.10000000  255.255.255.128 Increments Number: 128 (128 64 32 16 8 4 2 1) Networks: 180.200.0.0 (198.200.0.1 – 198.200.0.126) 180.200.0.128 (198.200.0.129 – 198.200.0.254) 180.200.1.0 (198.200.1.1 – 198.200.1.126) 180.200.1.128 (198.200.1.129 – 198.200.1.254). 180.200.253.0 (198.200.253.1 – 198.200.253.126) 180.200.253.128 (198.200.253.129 – 198.200.253.254) 16

17 Subnetting Examples Number of Hosts Class B Example #2: 180.200.0.0 Mask: 255.255.0.0 Required hosts: 300 Binary: 1 0 0 1 0 1 1 0 0  9 bits Required Mask: 11111111.1111111.11111110.00000000  255.255.254.0 Increments Number: 2 (128 64 32 16 8 4 2 1) Networks: 180.200.0.0 (180.200.0.1 – 180.200.1.254) 180.200.2.128 (180.200.0.129 – 180.200.0.254) 180.200.4.0 (180.200.1.1 – 180.200.1.126). 180.200.253.0 (180.200.253.1 – 180.200.253.126) 180.200.253.128 (180.200.253.129 – 180.200.253.254) 17

18 Subnetting Examples Number of Hosts Class B Example #2: 180.200.0.0 Mask: 255.255.0.0 Required hosts: 1500 Binary: 1 0 1 1 1 0 1 1 1 0 0  11 bits Required Mask: 11111111.1111111.11111000.00000000  255.255.248.0 Increments Number: 8 (128 64 32 16 8 4 2 1) Networks: 180.200.0.0 (180.200.0.1 – 180.200.7.254) 180.200.8.128 (180.200.8.1 – 180.200.15.254) 180.200.16.0 (198.200.16.1 – 198.200.23.254). 180.200.240.0 (180.200.240.1 – 180.200.247.254) 180.200.248.0 (180.200.248.1 – 180.200.255.254) 18

19 Reverse Calculations! 19

20 Subnetting Examples Finding the network of a given IP Address and Mask: 192.168.30.179/28 179 = 10110011 4bit = 11110000 And Result = 10110000 = 176  192.168.30.176/28 192.168.30.115/29 115 = 01110011 5bit = 11111000 And Result = 01110000 = 112  192.168.30.112/29 20

Download ppt "Saeed Darvish Pazoki – MCSE, CCNA IP Subnetting 1."

Similar presentations

© 2007 Cisco Systems, Inc. All rights reserved.Cisco Public 1 Version 4.0 Addressing the Network – IPv4 Network Fundamentals – Chapter 6.

© 2007 Cisco Systems, Inc. All rights reserved.Cisco Public 1 Version 4.0 Addressing the Network – IPv4 Network Fundamentals – Chapter 6.
IP Subnetting.

IP Subnetting.
Calculating Subnet Masks

Calculating Subnet Masks
1 IP Subnetting (Modified version of slides from Rick Graziani) Karim El Defrawy Donald Bren School of Information and Computer Science University of California.

1 IP Subnetting (Modified version of slides from Rick Graziani) Karim El Defrawy Donald Bren School of Information and Computer Science University of California.
OUR SUBNET PLANNING MISSION: We have been assigned an address of 201.222.5.0. Assume 20 subnets are needed, with 5 hosts per subnet. Our mission is to.

OUR SUBNET PLANNING MISSION: We have been assigned an address of Assume 20 subnets are needed, with 5 hosts per subnet. Our mission is to.
138.38.228.53255.255.254.0 10001010.00100110.11100010.0011010111111111.11111111.11111110.00000000 IP addressSubnet mask AND 10001010.00100110.11100010.00000000.

IP addressSubnet mask AND
CIM 2465 IP Subnetting1 IP Subnetting Textbook: Networking Basics, CCNA 1 Companion Guide, Cisco Press Cisco Networking Academy Program, CCNA 1 and 2,

CIM 2465 IP Subnetting1 IP Subnetting Textbook: Networking Basics, CCNA 1 Companion Guide, Cisco Press Cisco Networking Academy Program, CCNA 1 and 2,
Module 10: Routing Fundamentals and Subnets 10.2.9 Small Router Purchase Subnetting Example 10.3.5a Basic Subnetting 10.3.5b Subnetting a Class A Network.

Module 10: Routing Fundamentals and Subnets Small Router Purchase Subnetting Example a Basic Subnetting b Subnetting a Class A Network.
IP Addressing – Dotted-Decimal Notation –An IP address is 32 bits in size –Every IP address is grouped into four 8-bit octets –Octets are separated by.

IP Addressing – Dotted-Decimal Notation –An IP address is 32 bits in size –Every IP address is grouped into four 8-bit octets –Octets are separated by.
Introduction to Networking (Yarnfield) Classful subnetting.

Introduction to Networking (Yarnfield) Classful subnetting.
IP Addressing and Subnetting

IP Addressing and Subnetting
Ch.9 – IP Addressing Part 1 CCNA 1 version 3.1.

Ch.9 – IP Addressing Part 1 CCNA 1 version 3.1.
Information & Communication Technology

Information & Communication Technology
How to ? Subnetting. Scenario How Many Networks? 2 How Many Network addresses are required? 2 Addresses Used: 192.168.10.0 subnet mask 255.255.255.0 192.168.20.0.

How to ? Subnetting. Scenario How Many Networks? 2 How Many Network addresses are required? 2 Addresses Used: subnet mask
DCN286 INTRODUCTION TO DATA COMMUNICATION TECHNOLOGY Network Basics Introduction Instructor: Ataur Rahman

DCN286 INTRODUCTION TO DATA COMMUNICATION TECHNOLOGY Network Basics Introduction Instructor: Ataur Rahman
Subnetting Made Simple By Keith W. Noe – CCNA, CCAI Ivy Tech Community College Sellersburg, Indiana.

Subnetting Made Simple By Keith W. Noe – CCNA, CCAI Ivy Tech Community College Sellersburg, Indiana.
1 Real Networkers don’t use Decimal! Part 1. Binary & Interpreting IP Addresses October 19, 2004.

1 Real Networkers don’t use Decimal! Part 1. Binary & Interpreting IP Addresses October 19, 2004.
Classes of IP. host must have an IP address that identifies not only the host address (like a house number) but also identifies the network address (like.

Classes of IP. host must have an IP address that identifies not only the host address (like a house number) but also identifies the network address (like.
1 IP Addressing: Classful 0 network host 10 network host 110 networkhost 1110 multicast address A B C D class 1.0.0.0 to 127.255.255.255 128.0.0.0 to 191.255.255.255.

1 IP Addressing: Classful 0 network host 10 network host 110 networkhost 1110 multicast address A B C D class to to
1  You are given an IP address for a host 172.168.35.10/20  What is/are the  Subnet address?  Broadcast address?  The number of useable hosts available.

1  You are given an IP address for a host /20  What is/are the  Subnet address?  Broadcast address?  The number of useable hosts available.

Similar presentations

Ads by Google