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Warm Up #2 Find the Product: a. (x – 5)2 b. 4(x +5)(x – 5) ANSWER
A projectile, shot from the ground reaches its highest point of 225 meters after 3.2 seconds. For how many seconds is the projectile in the air? ANSWER 6.4 seconds
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Worksheet 4.1 Answers
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EXAMPLE 1 Graph a quadratic function in vertex form 14 Graph y = – (x + 2)2 + 5. STEP 1 Identify the constants a = – , h = – 2, and k = 5. 14 STEP 2 Plot the vertex (h, k) = (– 2, 5) and draw the axis of symmetry x = – 2.
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EXAMPLE 1 Graph a quadratic function in vertex form STEP 3 Evaluate the function for two values of x. x = 0: y = (0 + 2)2 + 5 = 4 14 – You Choose x = 2: y = (2 + 2)2 + 5 = 1 14 – Plot the points (0, 4) and (2, 1) and their reflections in the axis of symmetry. Because a < 0, the parabola opens down. STEP 4 Draw a parabola through the plotted points.
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Get Whiteboards!
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Graph the function. Label the vertex and axis of symmetry.
1. y = (x + 2)2 – 3 2. y = –(x – 1)2 + 5 a = 1 vertex is (-2 , -3) a = -1 vertex is (1 , 5) Line of Symmetry is x = 1 Line of Symmetry is x = -2 Choose x values 2 , 3 Choose x values -1 , 0 (2 , 4) and (3 , 1) (-1 , -2) and (0 , 1) Plot Symmetry Points Plot Symmetry Points (0 , 4) and (-1 , 1) (-3 , -2) and (-4 , 1)
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EXAMPLE 3 Graph a quadratic function in intercept form Graph y = 2(x + 3)(x – 1). STEP 1 Identify the x-intercepts. Because p = –3 and q = 1, the x-intercepts occur at the points (–3, 0) and (1, 0). STEP 2 Find the coordinates of the vertex. x = p + q 2 –3 + 1 = –1 = y = 2(–1 + 3)(–1 – 1) = –8 So, the vertex is (–1, –8) and the x-intercepts are (-3, 0) and (1, 0)
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5. y = (x – 3)(x – 7) 6. f (x) = 2(x – 4)(x + 1)
Graph the function. Label the vertex, axis of symmetry, and x-intercepts. 5. y = (x – 3)(x – 7) f (x) = 2(x – 4)(x + 1) x-intercepts: (3, 0) and (7, 0) x-intercepts: (4, 0) and (-1, 0) Vertex: x = (7 + 3)/2 = 5 Vertex: x = [4 + (-1)]/2 = 1.5 Vertex: y = (5 – 3)(5 – 7) = -4 Vertex: y = 2(1.5 – 4)( ) = -12.5 Vertex: (5 , -4) Vertex: (1.5 , -12.5) Line of Symmetry: x = 5 Line of Symmetry: x = 1.5
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Change from intercept form to standard form
EXAMPLE 5 Change from intercept form to standard form Write y = –2(x + 5)(x – 8) in standard form. y = –2(x + 5)(x – 8) Write original function. = –2(x2 – 8x + 5x – 40) Multiply using FOIL. = –2(x2 – 3x – 40) Combine like terms. = –2x2 + 6x + 80 Distributive property
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Change from vertex form to standard form
EXAMPLE 6 Change from vertex form to standard form Write f (x) = 4(x – 1)2 + 9 in standard form. f (x) = 4(x – 1)2 + 9 Write original function. = 4(x – 1) (x – 1) + 9 Rewrite (x – 1)2. = 4(x2 – x – x + 1) + 9 Multiply using FOIL. = 4(x2 – 2x + 1) + 9 Combine like terms. = 4x2 – 8x Distributive property = 4x2 – 8x + 13 Combine like terms.
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GUIDED PRACTICE for Examples 5 and 6 Write the quadratic function in standard form. 9. y = –(x – 2)(x – 7) f(x) = 2(x + 5)(x + 4) ANSWER ANSWER –x2 + 9x – 14 2x2 + 18x + 40 10. y = –3(x + 5)2 – 1 f(x) = –(x + 2)2 + 4 ANSWER ANSWER –3x2 – 30x – 76 –x2 – 4x
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Classwork Assignment: WS 4.2 (1-29 odd)
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