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Published byGodwin Preston Modified over 9 years ago
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Gas Equilibria The Jungle Begins...
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What is Equilibrium? Reaction is reversible Both products and reactants are present Forward and reverse reactions take place at the same rate BUT the partial pressures must be specified For the reaction 2A = B
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Using the K eq constant Let's look at the logical consequences of the assumption that the reaction between ClNO2 and NO eventually reaches equilibrium ClNO 2 (g)+NO(g) --> NO2(g)+ClNO(g) At equilibrium: rate forward=rate reverse Substituting the rate laws for the forward and reverse reactions into this equality gives the following result. : kf(ClNO2)(NO)=kr(NO2)(ClNO) But this equation is only valid when the system is at equilibrium, as follows. At equilibrium: kf[ClNO2][NO]=kr[NO2][ClN O]
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We should replace the (ClNO2), (NO), (NO2), and (ClNO) terms with symbols that indicate that the reaction is at equilibrium. By convention, we use square brackets for this purpose. The equation describing the balance between the forward and reverse reactions when the system is at equilibrium should therefore be written kf[ClNO2][NO]=kr[NO2][ClNO] Since kf and kr are constants, the ratio of kf divided by kr must also be a constant. This ratio is the equilibrium constant for the reaction, Kc. The ratio of the concentrations of the reactants and products is known as the equilibrium constant expression.
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K expression Keq = [ClNO][NO2] [ClNO2][NO] [ClNO2][NO] Or in general terms Keq = [C] c [D] d [A] a [B] b [A] a [B] b For aA + bB --> cC + dD
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Or, the expression could be written for gases, in which case we will use pressures rather than moles/liter or molarity. N 2 O 4 --> 2NO 2 at 100 C Colorleless reddish brown Then 2NO 2 -->N 2 O 4 begins to happen until the rates become the same and we have N 2 O 4 2NO 2 What is the equilibrium constant expression for this equation? Keq = (PNO2) (PN2O4) 2 (PN2O4) 2
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Gaseous Equilibrium Expression So we can also write the general equilibrium constant as K = (PC) c (PD) d (PA) a (PB) b Note that the expression will change depending on the form of the equation.
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Rules of K 1.Reciprocal Rule N 2 O 4 --> 2NO 2 K original = [NO 2 ] 2 [N 2 O 4 ] For the reverse reaction 2NO 2 --> N 2 O 4 K reverse = 1/K orig
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Rules of K continued Coefficient Rule N 2 O 4 --> 2NO 2 K original = [NO 2 ] 2 [N 2 O 4 ] If we change the coefficients to 2 and 4 (doubling the molar ratio) K new = K orig 2
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Rules of K, concluded Multiple Equilibria K1 2NO 2 --> N 2 O 4 K2 N 2 O 4 --> N 2 + O 2 K new 2NO 2 --> N 2 + O 2 K new = K 1 K 2 Want to know why? Read the text for a great explanation!
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ICE (ice, ice baby) I initial concentration C change in concentration E final or ending concentration Remember this--you will use it over and over and over and over... When? With experimental Data!
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Protocol for Gas Equilibrium Problems 1.Write the equation 2.ICE 3.Find K 4.Plug and Chug (check units) 5.Does this answer make sense?
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