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CH4(g) + 2O2(g)  CO2(g) + 2H2O (g)

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Presentation on theme: "CH4(g) + 2O2(g)  CO2(g) + 2H2O (g)"— Presentation transcript:

1 CH4(g) + 2O2(g)  CO2(g) + 2H2O (g)
Practice Quiz For Chapter 13; Gases Data: 1.0 atm = 760 torr Molar masses: 1.0 atm = 101,325 Pa O N 14.01 Ar C H R= L atm / K mol n = mass /Molar mass STP = 0 C and 1.00 atm Temp. K = Temp. C + 273 1.What is the volume of CO2 (g) measured at STP if you have 2.00g of CH4? CH4(g) + 2O2(g)  CO2(g) + 2H2O (g)

2 CH4(g) + O2(g)  CO2(g) + 2H2O (g)
1.What is the volume of CO2 (g) measured at STP if you have 2.00g of CH4? CH4(g) + O2(g)  CO2(g) + 2H2O (g) Balanced = CH4(g) + 2O2(g)  CO2(g) + 2H2O (g) T = 273 K P = 1.00 atm mass (CH4) = 2.00g PV = nRT V =? From equation

3 2. A 10. 0L tank contains 3. 20g of CO2 (g) and 5
2.A 10.0L tank contains 3.20g of CO2 (g) and 5.00g of O2 (g) at 25C What is the total pressure inside of the tank? V = 10.0L T = 25 C = 298 K P = ? atm mass (O2) = 5.00g mass (CO2) = 3.20g PV = nRT P = nRT V

4 3. A gas occupies 18.0 L at 860 torr and 38 C,
What temperature is necessary to increase the volume to 30.0L if the pressure stays the same? V1 = 18.0L P = 860 torr = 860torr/760torr = atm V2 = 30.0L T1 = 38C = 311 K T2 = ? Pressure stays constant, assume the number of moles is constant

5

6 4. An oxygen sample has a volume of 4. 50 L at 25 C and 790. 0 torr
4. An oxygen sample has a volume of 4.50 L at 25 C and torr. How many moles of oxygen molecules does it contain? V = 4.50 L T = 25 C = 298 K P = 790 torr = atm PV = nRT n=PV RT n = (1.039atm) (4.50L) ( L atm K-1 mol -1 )(298 K) n = atm L L atm K-1 mol -1 K n = moles

7 5. Convert the following:
a mm Hg to atm b atm to torr c. 68,471 Pa to mm Hg d psi to atm 1.0 atm = 760 torr = 760 mm Hg 1.0 atm = 101,325 Pa 1.0 atm = psi a. b. c. d.

8 6. A gas has a pressure of 2,500 psi, how many torr is this?
Hint atm = psi

9 7. A sample of nitrogen gas at 2. 4atm has a volume of 50. 3 L
7. A sample of nitrogen gas at 2.4atm has a volume of 50.3 L. If the pressure is decreased to 1.9 atm, will the new volume be greater or smaller? What is the new volume? This is using Boyle’s Law

10 8. A container with a moving piston contains 0
8. A container with a moving piston contains 0.89 L of methane gas at 100.5˚C. If the temperature of the gas rises by 11.3 ˚C, what is the new volume of the gas? V2 = 0.99L

11 9. Carbon dioxide is produced during the combustion of liquid propane fuel.
C3H8 + O2 3CO2 + 4H2O Balanced: C3H8 +5O2 3CO2 + 4H2O If 5.0kg of propane are burned at atm and 400 ˚ C, what volume of CO2 gas is produced? Mass propane = 5000g n(propane) = 5000g/44.11 = moles n(CO2) = 3 (113.35) = moles

12 PV =nRT V =18,780.22L


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