1. Electrostatic Formula

2. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2

3. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2

4. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2

5. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2

6. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

7. Electric Force F = 1 q 1 q 2 = k q 1 q 2 4  e o r 2 r 2 k = 9.0x10 9 N m 2 = 1 = -------1------------ C 2 4  e o 4  8.85x10 -12 C 2 N m 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

8. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

9. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

10. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

11. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

12. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

13. Electric Field associated with point charges E = F q F = kqq therefore E = Kqq therefore E =kq r 2 r 2 q r 2 Vector sum – x components, y components, sum of x components, sum of y components, pythagorean theorem, and inv tan of (sum of y )/(sum of x )

14. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

15. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

16. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

17. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

18. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

19. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

20. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

21. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

22. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

23. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

24. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

25. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

26. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

27. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

28. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

29. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

30. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

31. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

32. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E q d

33. Electric Field Associated with Parallel Plates The electric field is uniform between plates Work is required to move +q from the – to + W=Fd W=qEd W=qKqd W=Kqq W = Kq W =V=Joules= Electric Potential d 2 d q d q Coulomb W=qEd W = Ed V = Ed V = E = Volts q d meter

34. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

35. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

36. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

37. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

38. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

39. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

40. Capacitance C = Q V C = KA  o d K= dielectric constant A = area in m 2    x10 -12 C 2 N m 2 d = distance between plates in m

41. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

42. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

43. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

44. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

45. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

46. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

47. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

48. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

49. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

50. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

51. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

52. Capacitance W = QV = U ( Potential energy stored ) For a capacitor U = ½ QV since it is easier to add charge at first and progressively gets more difficult C = Q CV = Q therefore U =1/2 QV= ½ CV 2 V C = Q V = Q therefore U = ½ QV = ½ Q 2 V C C

53. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

54. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

55. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

56. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

57. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

58. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

59. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

60. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

61. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

62. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

63. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

64. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

65. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

66. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

67. Capacitance C parallel = C 1 +C 2 +C 3 2F4F6F2F4F6F 12  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 12x10 -6 F (3V) = 36x10 -6 C or 3.6x10 -5 Q What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 12x10 -6 F(3V) 2 = U=1.08x10 -4 J What is the charged stored on each of the capacitors? CV=Q= 2x10 -6 F (3V) = 6x10 -6 C CV=Q= 4x10 -6 F (3V) = 12x10 -6 C or 1.2x10 -5 Q CV=Q= 2x10 -6 F (3V) = 18x10 -6 C or 1.8x10 -5 Q

68. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11=1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

69. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11=1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

70. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11=1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

71. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11=1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

72. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

73. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

74. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

75. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

76. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J

77. Capacitance 1 = 1 + 1 + 1 C series C 1 C 2 C 3 2  F 4  F 6  F 1/C = 1/2  F 1/4  F + 1/6  F 1/C = 11/12  F = 12  F/11= 1.09  F 3 V What is the total charge stored in the system? C = Q V CV = Q = 1.09x10 -6 F (3V) = 3.27x10 -6 C What is the energy stored in the system? U=1/2 QV U = ½ CV 2 U= ½ 3.27x10 -6 F(3V) 2 = U=1.47x10 -5 J