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HEAT TRANSFER TO A SUNROOM the affect of window type on heat transfer
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The Situation Clear Day Mid June Provo, UT The Pate’s have recently added a sunroom to the exterior of their home. In the summer the temperature rises in that room a considerable amount. Should they have installed double pane windows instead? Should they invest in windows with reflective coating? How much of a difference would these windows make?
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What We Know: Incident Solar Radiation East Wall: 5015 W/m 2 South Wall: 2997 W/m 2 West Wall: 5015 W/m 2 Temperature Data T sur, interior = 20° C T sur, exterior = 35° C Physical Properties Glass (T=300K) 1.4 W/mK Air K=.0263 W/mK (T=300K) Areas of Windows: East Wall 8.09 m 2 South Wall: 6.77 m 2 (x 2) 2.60 m 2 (x2) West Wall 8.09 m 2 Volume of the Room 60 m 3
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What We Assume: Radiation Properties of Glass Transmissivity =.95 Absorbtivity = 0 Reflectivity =.05 Emissivity =.9 Neglect radiation out of the room (only consider incident radiation) No heat transfer through the walls T sur stays constant Window areas are all square (see diagram)
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Single Pane Glass h o,i = 6 W/m 2 q conv+cond = 728 W q rad = 1606 W q total = 2324 H o, T o H i, T i
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Double Pane Glass Ra L =91.37 Δ T Ra L max = 1307 1307 < 1708 Convection between planes is negligible. Transmissivity:.9 Reflectivity:.1 h = 6 W/m 2 q conv+cond = 168 W q rad = 1522 W q total = 1690 W H o, T o H i, T i
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Double Pane Glass with Coating Reflective glass Reflectivity:.28 Transmissivity:.72 Heat transfer from convection and conduction stays the same. q conv+cond = 168 W q rad = 1217 W q total = 1385 W H i, T i H o, T o
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Air Conditioning Cost Single Pane: $122.07 Double Pane: $148.09 Coated Double Pane: $216.12 $.08/KWhr COP = 3.4 Summer Savings: $94.05 Coating: $36/Window Estimate: $216 to upgrade, 2.5 Summers to recover the savings
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Presented By: Nathan Honka Dallin Shaw Jenny Pate
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Appendix A: Radiation Data
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Appendix B: Equations Inside Convection Coefficient Thermal Resistances
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Appendix B: Equations q conv,i on inner surface: q cond through window: q conv,o = q cond = q conv,i Could not solve that system so we assumed h=6W/m 2 to determine q conv,i and q conv,o.
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Appendix C: Spreadsheet Solution SINGLE PANE Area (m 2 )q (cond + conv) q (rad) q (total) 8.09728.11606.26952334.3695 6.77609.3803.93751413.2375 6.77609.3803.93751413.2375 2.6234308.75542.75 2.6234308.75542.75 8.09728.11606.26952334.3695 8580.714
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Appendix C: Spreadsheet Solution DOUBLE PANE Area (m 2 )q (cond + conv) q (rad) q (total) 8.09167.81521.7291689.529 6.77140.4761.625902.025 6.77140.4761.625902.025 2.653.9292.5346.4 2.653.9292.5346.4 8.09167.81521.7291689.529 5875.908
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Appendix C: Spreadsheet Solution DOUBLE PANE WITH COATING Area (m 2 )q (cond + conv) q (rad) q (total) 8.09167.81217.38321385.1832 6.77140.4609.3749.7 6.77140.4609.3749.7 2.653.9234287.9 2.653.9234287.9 8.09167.81217.38321385.1832 4845.5664
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Sources Incident Solar Radiation Values: http://geology.utah.gov/sep/renewable_energy/s olar/images/data_tables/slcbld.jpg
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